This is because ScGeom algorithms don't need total strain (*). (*) One exception : HertzMindlin, thats why I suggested deriving it from Dem3Dof rather than ScGeom.
Hi guys, perhaps I am escaping something. Why would HM need total strain? As it is now it is incremental, same way as computed in PFC. Anyway, PFC or not I have been studying Mindlin's paper and I plan to code the exact formulation in the future. And again it is all incremental. So no problem on my side with the current design. Cheers. Chiara
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