On Thu, Oct 4, 2012 at 9:45 AM, Jim Klimov <jimkli...@cos.ru> wrote:
> 2012-10-04 20:36, Freddie Cash пишет:
>>
>> On Thu, Oct 4, 2012 at 9:14 AM, Richard Elling <richard.ell...@gmail.com>
>> wrote:
>>>
>>> On Oct 4, 2012, at 8:58 AM, Jan Owoc <jso...@gmail.com> wrote:
>>> The return code for zpool is ambiguous. Do not rely upon it to determine
>>> if the pool is healthy. You should check the health property instead.
>>
>>
>> Huh. Learn something new everyday. You just simplified my "pool
>> health check" script immensely. Thank you!
>>
>> pstatus=$( zpool get health storage | grep "health" | awk '{ print $3 }' )
>> if [ "${pstatus}" != "ONLINE" ]; then
>
>
> Simplify that too with "zpool list":
>
> # zpool list -H -o health rpool
> ONLINE
Thanks! Was trying to figure out how to remove the heading as I use
-H a lot with zfs commands, but it didn't work for "zpool get" and I
didn't bother reading to figure it out. :)
--
Freddie Cash
fjwc...@gmail.com
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