You mean how do you linearize it? Newton's method and iterate
within each timestep. 
-J


li pan writes:
 > hi Roy,
 > thanx for the explaination. But how did you solve ((u
 > * grad)u, v)_Omega? It's a square term. I heard there
 > are some other methods, streamline, least square FEM
 > ...  I would like to hear your comments.
 > 
 > pan 
 > 
 > 
 > 
 > --- Roy Stogner <[EMAIL PROTECTED]> wrote:
 > 
 > > 
 > > On Thu, 24 Jan 2008, li pan wrote:
 > > 
 > > > I've worked with Newton type flow equation. To
 > > make it
 > > > sure, I would like to know the exact expression of
 > > > equation in ex13. Can you tell me?
 > > 
 > > The system of equations with variables (u,p) is :
 > > (partial u)/(partial t) = - (u * grad)u - div(sigma)
 > > div(u) = 0
 > > 
 > > Where sigma is the stress tensor (normalized to have
 > > unit viscosity)
 > > sigma = ((grad(u) + transpose(grad(u)))/2 - pI)
 > > 
 > > Then the weak form we use in ex13 and ex18, with
 > > test functions (v,q)
 > > is:
 > > ((partial u)/(partial t), v)_Omega = - ((u * grad)u,
 > > v)_Omega
 > >    + (sigma, grad v)_Omega + (sigma * n, v)_dOmega
 > > (div(u), q) = 0
 > > 
 > > In ex13 we use Dirichlet boundaries everywhere, so v
 > > = 0 on the
 > > boundary and we drop the dOmega term.  Otherwise,
 > > you'd substitute
 > > into that term the natural boundary condition:
 > > sigma * n = 0
 > > 
 > > which is actually what David wanted in the first
 > > place.  ;-)
 > > 
 > > You know, we probably ought to have something like
 > > this in the
 > > comments heading examples 13 and 18.  "The
 > > Navier-Stokes equations" is
 > > definitive enough, but the fact that we integrate
 > > all of sigma
 > > (including the pressure term) by parts isn't set in
 > > stone.
 > > ---
 > > Roy
 > > 
 > >
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