On Mon, Jul 11, 2011 at 12:31 PM, Øyvind Harboe <oyvind.har...@zylin.com> wrote:
> On Mon, Jul 11, 2011 at 12:17 PM, Drasko DRASKOVIC
> <drasko.drasko...@gmail.com> wrote:
>> On Mon, Jul 11, 2011 at 7:31 AM, Øyvind Harboe <oyvind.har...@zylin.com> 
>> wrote:
>>> Now a sequence of 8 bit words happens to be identical to
>>> little endian representation
>> In what way ? 8 bits is 8 bits - one byte, bits 7:0. I do not see BE
>> or LE representation here...
>
> Consider a series of words in memory where the width is greater than 8.
>
> Clearly a BE series has a different representation than a LE version.
>
> For a series of words that are 8 bits long, then the BE series and
> LE series are identical.
>
> Further, if you have 32 bits stored in a series of bytes in memory,
> then the memory layout is identical to the memory layout of
> little endian layout.

Sorry Øyvind,
I did not get at first that you meant on this - a byte array in the
mem. Yes, I agree, it has LE order when memory is observed (which is
one of the main arguments of the LE camp why LE is natural).

BR,
Drasko
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