>>> How do they convert then, when they do not know from which endianes to >>> convert from ? >> >> Conversion is done from byte array of jtag chain. > How ?
buf_get_u32 does conversion from uint8* array example: mips_ejtag_get_impcode (mips_ejtag.c) field.in_value is filled by jtag_add_dr_scan with 4 times uint8. buf_get_u32 converts byte array to host endian uint32 >> The endianness of MIPS EJTAG tap seems to have always the same endianness, >> no matter of MIPS CPU memory endianness. > What makes you think so ? Because openocd works in all combinations of BE and LE host and target. (If you revert commit 2482244b0788c007dd789c21a4416379c229ea5c.) So yes, it's just a guess. Could this be the explanation: http://downloads.buffalo.nas-central.org/LS2_MIPSel/DevelopmentTools/JTAG/MD00047-2B-EJTAG-SPC-03.10.pdf Page 97: Byte 0 refers to bits 7:0, byte 1 refers to bits 15:8, byte 2 refers to bits 23:16, and byte 3 refers to bits 31:24, independent of endianess. Please also see Chapter 6.3.3, 6.3.6, 6.4.1, etc. TAPs are alway LSB first, so endianness doesn't matter here. _______________________________________________ Openocd-development mailing list Openocd-development@lists.berlios.de https://lists.berlios.de/mailman/listinfo/openocd-development
