Hi Anders,
Hence, it makes no sense storing a color in ShapeDrawable.
Well, it makes as much sense as having a color array for an
osg::Geometry... :-)
I think it's not having a color in ShapeDrawable that's the problem,
it's having no way of having no color. In other words, in osg::Geometry
you have the ability to either set a color array or not. You should have
the same ability in ShapeDrawable, i.e. set a color or not. Since
osg::Color doesn't really have a "no color" value, you probably need an
additional bool saying "use the color or not". When _useColor == false,
then no glColor call would be made by ShapeDrawable itself, and the one
from osg::Material would take effect.
Or you could just do what Robert always says, ignore ShapeDrawable even
exists (except for simple debug geometry) and use osg::Geometry
directly. Then you can do what you want.
I've wanted to rewrite ShapeDrawable to use osg::Geometry internally for
a while, but I think Paul beat me to it in osgWorks... :-)
J-S
--
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Jean-Sebastien Guay jean-sebastien.g...@cm-labs.com
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