A question from someone writing C extension modules for python but not involved in python-dev:
It has been said that compiling python with --without-llvm would not include unladen swallow and would bypass llvm together with all C++. Basically, as I understand it, --without-llvm gives the 'usual' cpython we have today. Is this correct? If this is correct, I still have one worry: since I wouldn't want to touch the python install most linux distributions ship or most windows/mac users install (or what MS/Apple ships) I will simply have no choice than working with the python variant that is installed. Is it anticipated that most linux distros and MS/Apple will ship the python variant that comes with llvm/US? I suppose the goal of merging llvm/US into python 3.x is this. If this is the case then I, as a C extension author, will have no choice than working with a python installation that includes llvm/US. Which, as far as I undestand it, means dealing with C++ issues. Is this correct? Or the same pure C extension module compiled with C-only compilers would work with llvm-US-python and cpython? Cheers, Danil -- Psss, psss, put it down! - http://www.cafepress.com/putitdown _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
