[R] Box plot without original data
Hi to everyone! I need to plot a box plot but I don't have the original data, is it possible to make it just with the median, mean, sd and range of values? Any idea is welcome. Thanks in advance. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Simulating data
Hi to everyone To simulate data I only know this command: rnorm(n , mean, sd) It exists another way to specify Median and range as well? The point is that I have this information about the variable: Median: 4.3 Mean: 4.2 SD: 1.8 Range: 0-8 and I need a boxplot, but I don't have the original data, simulating data looks a good idea to solve it. Thanks in advance. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Box plot without original data
On 04/04/2014 05:36 PM, Mª Teresa Martinez Soriano wrote: Hi to everyone! I need to plot a box plot but I don't have the original data, is it possible to make it just with the median, mean, sd and range of values? Any idea is welcome. Hi Teresa, You can get the return value from the boxplot function and then substitute the values you want into the $stats component. Then pass that to the bxp function. See the help pages for boxplot and bxp. Another option is to use the box.heresy function in the plotrix package, as that function does not assume that the box will be defined by the median and (approximate) quartiles. Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Equation of a curve
On 03/04/2014 16:26, Frances Cheesman wrote: Hi all, I have a number of bacterial growth curves I would like to find the equations for these and then integrate them to find the area under the curves for me to do stats on later. Is there any way I can do this in R? Thanks, Frances [[alternative HTML version deleted]] Responding to the curve fitting question and passing over the integration issue... It is quite common to use nls to fit equations to log(count) v time data. You'll have to choose an appropriate model, ideally as a self starting nls model. Of those included in the stats package you might consider SSfpl, SSgompertz, SSlogis and SSweibull. But choice of a model is really a microbiological issue and all those models might be considered a little passe. Fitting this kind of sigmoidal model can be difficult unless the data is good. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] [R-pkgs] rDVR package
I would like to announce the release of version 0.1.1 of the rDVR package on CRAN. rDVR is an R package that allows cross Platform (Lin/Win/OSx) video recording from R. It is light weight and allows up to 10 minutes of recording by default. rDVR has a project page at http://johndharrison.github.io/rDVR/ http://cran.r-project.org/web/packages/rDVR/index.html The package comes with a vignette which contain overviews on basic operation and a few examples linking to projects such as Shiny and RSelenium. rDVR uses include bug testing, project documentation and web testing. Comments and suggestions are greatly appreciated. John Harrison [[alternative HTML version deleted]] ___ R-packages mailing list r-packa...@r-project.org https://stat.ethz.ch/mailman/listinfo/r-packages __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Equation of a curve
Thanks everyone for al your help, I don't think it's necessarily as easy as I first thought. I'm going to have a think about it and try some things out. And I'll be back if I get stuck! Thanks very much, Frances On 4 April 2014 09:11, Keith Jewell keith.jew...@campdenbri.co.uk wrote: On 03/04/2014 16:26, Frances Cheesman wrote: Hi all, I have a number of bacterial growth curves I would like to find the equations for these and then integrate them to find the area under the curves for me to do stats on later. Is there any way I can do this in R? Thanks, Frances [[alternative HTML version deleted]] Responding to the curve fitting question and passing over the integration issue... It is quite common to use nls to fit equations to log(count) v time data. You'll have to choose an appropriate model, ideally as a self starting nls model. Of those included in the stats package you might consider SSfpl, SSgompertz, SSlogis and SSweibull. But choice of a model is really a microbiological issue and all those models might be considered a little passe. Fitting this kind of sigmoidal model can be difficult unless the data is good. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/ posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Simulating data
Hi Teresa Try this: Median - 4.3 Mean - 4.2 SD - 1.8 RangeLower - 0 RangeUpper - 8 par(mfcol = c(1,2)) (bpstats - boxplot(rnorm(100, mean = Mean, sd = SD), outl = FALSE)) ## assuming normality of original data since we don't know the distribution ## get the 25% and 75% quantile q25 - qnorm(0.25, mean = Mean, sd = SD) q75 - qnorm(0.75, mean = Mean, sd = SD) yourstats - matrix(c(RangeLower, q25, Median, q75, RangeUpper), ncol = 1) bpstats$stats - yourstats bxp(bpstats, outl = FALSE) Yours sincerely / Med venlig hilsen Frede Aakmann Tøgersen Specialist, M.Sc., Ph.D. Plant Performance Modeling Technology Service Solutions T +45 9730 5135 M +45 2547 6050 fr...@vestas.com http://www.vestas.com Company reg. name: Vestas Wind Systems A/S This e-mail is subject to our e-mail disclaimer statement. Please refer to www.vestas.com/legal/notice If you have received this e-mail in error please contact the sender. -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Mª Teresa Martinez Soriano Sent: 4. april 2014 10:49 To: r-help@r-project.org Subject: [R] Simulating data Hi to everyone To simulate data I only know this command: rnorm(n , mean, sd) It exists another way to specify Median and range as well? The point is that I have this information about the variable: Median: 4.3 Mean: 4.2 SD: 1.8 Range: 0-8 and I need a boxplot, but I don't have the original data, simulating data looks a good idea to solve it. Thanks in advance. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] MANOVA post hoc testing
Dear Nicholas, On Fri, 4 Apr 2014 04:59:09 + nicholas.suraw...@csiro.au wrote: Greetings, I'm interested in performing some post hoc tests after conducting a multivariate analysis of covariance (MANCOVA) which I performed using the Anova function in the car package. The covariate did not end up being statistically significant, but the single factor's effect on the multivariate response was statistically significant. From here, I would like to use the linearHypothesis function in the car package to test for where significant differences are occurring. Codewise, to fit the MANCOVA i've used: Model_1 - Anova(lm((Y)~X+covariate)) I've then tried to perform multiple comparisons using: linearHypothesis(Model_1,matchCoefs(Model_1,X),white.adjust=TRUE) The argument white.adjust=TRUE isn't available for a multivariate linear model; see ?linearHypothesis. Also, the command (without the white.adjust argument) will give you the same test as Anova() did. Best, John John Fox, Professor McMaster University Hamilton, Ontario, Canada http://socserv.mcmaster.ca/jfox/ After I run the 2nd bit of code I get the error message: Error in vcov.default(model) : there is no vcov() method for models of class Anova.mlm. Presumably, this means that I've stuffed up in trying to estimate the variance-covariance matrix for the Anova function. Any suggestions/help to resolve this problem would be greatly appreciated. Cheers, Nic Surawski [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] simulation data
dear sir i want to simulate multivariate ordinal data matrix with categories (1,4) and n=1000 and p=10. thanks alot thanoon [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to plot data using ggplot
Hi, I have a list of cities and their coordinates, and also for each city I have a variable varA which I want to represent in a map using ggplot. For example : CityA lat 22.93977 lon 46.70663varA 545 CityB lat 23.93977 lon 46.70663varA 122 VarA values begin from 0 to 3000. I want the color scale to represent this range appropriately. Can you help Regards -- View this message in context: http://r.789695.n4.nabble.com/How-to-plot-data-using-ggplot-tp4688168.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Lognormal AR(0,1) model
Hi everyone!
I am trying to make two log-normal AR(0,1) model using R with a given
correlation between them, \rho, on the form:
X_t = \alpha X_{t-1} + a_t
Y_t = \beta Y_{t-1} + b_t
At the moment I have been making n values of correlated log-normal data,
called a_t and b_t, and generated a starting value X[1] and Y[1] using the
rnorm() function. The rest of the n-1 values are calculated in a for() loop.
The data do get a lognormal look, but it is obviously not a lognormal
distribution.
As I am a novice to time-series, my question is simply: Are there any way to
make correlated log-normal distributed AR(0,1) models, and are there any
package in R that will help me?
sincerely
Chris
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[R] MICE, POST-PROCESSING imputations with two conditions
Dear R listserve,
I am writing with the hope or receiving assistance using the MICE package.My
troubles relate to post-processing imputations. I am attempting to impute
variables for which I want to specify two conditions using post-processing
imputation: 1) if the value of a variable representing the pesticide
application (PESTICIDE) is coded 0 to represent that the participant did not
conduct task then I want my duration of work in the task (DURR) and start year
for the task variables (START_DATE) to be coded as NA; 2) If the value of the
variable representing pesticide application task is coded 1 (did conduct task),
then I want my duration of work in the task and start year for the task to be
imputed using certain boundaries (restricting the values of the imputed date
and duration variables).
The two statements seem to work independently (post-processing statements are
recognized); however, I can't figure out how to combine them in one post
statement . Thus, I can't get my imputations to take the two conditions into
account; I can either restrict the variables to be set to missing if PESTICIDE
is 0, or I can get my imputations to be restricted to my specified boundaries,
but I can't get R to take both conditions into account simultaneously.
The following is the code that I am using. I am highlighting the two post
processing statements that I am having trouble with.:
ini-mice(agrican.subb, print=FALSE, max=0)
pred-ini$pred
pred[START_DATE,]-1
pred[END_DATE,]-0
pred[,END_DATE]-0
pred[,START_DATE]-0
pred[,YEAR_BIRTH]-0
pred[,year_ten]-0
pred[,DIFF]-0
pred[,ID]-0
pred[,CORN]-0
method-c(, , , , , norm, , pmm, , , , , , , norm)
post-ini$post
post[START_DATE]-imp[[j]][,i]-squeeze(imp[[j]][,i],c(agrican.subb$YEAR_TEN,
agrican.subb$ENROLLMENT_YEAR))
post[START_DATE]-imp[[j]][p$data$PESTICIDE[!r[,j]]1,i]-NA
post[DIFF]-imp[[j]][,i]-squeeze(imp[[j]][,i],c(0, 0))
#post[DIFF]-imp[[j]][p$data$PESTICIDE[!r[,j]]1,i]-NA
imp-mice(subb,post=post, pred=pred, seed=2332, method=method, maxit=3)
I will appreciate any advise that you can offer.
Thanks in advance!
Leah
Postdoctoral fellow
Section of Environment and Radiation
International Agency for Research on Cancer
150, cours Albert Thomas
69372 Lyon Cedex 08
France
schina...@fellows.iarc.fr
Tel: [+33] (0)472 73 84 85
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[R] Mistakes in date conversion for future date/time (POSIXct)
Dear R-users, I'm working on datasets which contain data from the years 1960 to 2100 with a timestep of one hour. Every year has 365 days, leap years are ignored. After reading the dataset with R I convert the column which contains date/time to POSIXct: as.POSIXct(strptime(MyData [,1], format=%d.%m.%Y : %H)) After that, I divide the data with split() into parts of one year each. Then I recognized, that the years for some rows are obviously converted wrong: They show years larger than 2100 (see example below). I've controlled my original dataset, but the dates are correct there. I also produced a date/time-sequence in R, which showed the same mistakes (see example below). The mistakes occur at the same dates like in my datasets. It's always at the end of march. datetimesequenz - seq.POSIXt(from=as.POSIXct(1960-01-01 00:00), to=as.POSIXct(2100-01-01 00:00), by=1 hour) levels(as.factor(strftime(datetimesequenz, format=%Y))) [1] 1960 1961 1962 1963 1964 1965 1966 1967 1968 1969 1970 1971 1972 1973 1974 1975 1976 1977 [19] 1978 1979 1980 1981 1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992 1993 1994 1995 [37] 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010 2011 2012 2013 [55] 2014 2015 2016 2017 2018 2019 2020 2021 2022 2023 2024 2025 2026 2027 2028 2029 2030 2031 [73] 2032 2033 2034 2035 2036 2037 2038 2039 2040 2041 2042 2043 2044 2045 2046 2047 2048 2049 [91] 2050 2051 2052 2053 2054 2055 2056 2057 2058 2059 2060 2061 2062 2063 2064 2065 2066 2067 [109] 2068 2069 2070 2071 2072 2073 2074 2075 2076 2077 2078 2079 2080 2081 2082 2083 2084 2085 [127] 2086 2087 2088 2089 2090 2091 2092 2093 2094 2095 2096 2097 2098 2099 2100 2101 2102 2103 [145] 2105 2107 2109 2110 2111 2112 2113 2114 2115 2117 2118 2120 2121 2122 2124 2125 2126 2128 [163] 2129 2130 2131 2132 2133 2135 2137 2138 2139 2140 2141 2142 2143 2145 2146 2148 2149 2150 [181] 2152 2153 2154 2156 2157 2158 2159 2160 2161 2166 Has anybody experienced the same problem and knows a workaround? I'm using R 3.0.1 under Windows 7 64bit. I also tried this with R 3.0.3, it showed the same problem. Thank you for your help! Kind regards, Matthias [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simulation data
Hi Thanoon, How about this? # replicate p=10 times random sampling n=1000 from a vector containing your ordinal categories (1,2,3,4) R - replicate(10, sample(as.vector(seq(4)), 1000, replace = T)) Cheers, Charles On Fri, Apr 4, 2014 at 7:10 AM, thanoon younis thanoon.youni...@gmail.comwrote: dear sir i want to simulate multivariate ordinal data matrix with categories (1,4) and n=1000 and p=10. thanks alot thanoon [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Charles Determan Integrated Biosciences PhD Candidate University of Minnesota [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Mistakes in date conversion for future date/time (POSIXct)
high probability you are in a daylight savings time problem. see the archives for repair strategies. probably it will be enforcing standard time on all measurements. Rich Sent from my iPhone On Apr 4, 2014, at 10:55, Winkler, Matthias matthias.wink...@ibp.fraunhofer.de wrote: Dear R-users, I'm working on datasets which contain data from the years 1960 to 2100 with a timestep of one hour. Every year has 365 days, leap years are ignored. After reading the dataset with R I convert the column which contains date/time to POSIXct: as.POSIXct(strptime(MyData [,1], format=%d.%m.%Y : %H)) After that, I divide the data with split() into parts of one year each. Then I recognized, that the years for some rows are obviously converted wrong: They show years larger than 2100 (see example below). I've controlled my original dataset, but the dates are correct there. I also produced a date/time-sequence in R, which showed the same mistakes (see example below). The mistakes occur at the same dates like in my datasets. It's always at the end of march. datetimesequenz - seq.POSIXt(from=as.POSIXct(1960-01-01 00:00), to=as.POSIXct(2100-01-01 00:00), by=1 hour) levels(as.factor(strftime(datetimesequenz, format=%Y))) [1] 1960 1961 1962 1963 1964 1965 1966 1967 1968 1969 1970 1971 1972 1973 1974 1975 1976 1977 [19] 1978 1979 1980 1981 1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992 1993 1994 1995 [37] 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010 2011 2012 2013 [55] 2014 2015 2016 2017 2018 2019 2020 2021 2022 2023 2024 2025 2026 2027 2028 2029 2030 2031 [73] 2032 2033 2034 2035 2036 2037 2038 2039 2040 2041 2042 2043 2044 2045 2046 2047 2048 2049 [91] 2050 2051 2052 2053 2054 2055 2056 2057 2058 2059 2060 2061 2062 2063 2064 2065 2066 2067 [109] 2068 2069 2070 2071 2072 2073 2074 2075 2076 2077 2078 2079 2080 2081 2082 2083 2084 2085 [127] 2086 2087 2088 2089 2090 2091 2092 2093 2094 2095 2096 2097 2098 2099 2100 2101 2102 2103 [145] 2105 2107 2109 2110 2111 2112 2113 2114 2115 2117 2118 2120 2121 2122 2124 2125 2126 2128 [163] 2129 2130 2131 2132 2133 2135 2137 2138 2139 2140 2141 2142 2143 2145 2146 2148 2149 2150 [181] 2152 2153 2154 2156 2157 2158 2159 2160 2161 2166 Has anybody experienced the same problem and knows a workaround? I'm using R 3.0.1 under Windows 7 64bit. I also tried this with R 3.0.3, it showed the same problem. Thank you for your help! Kind regards, Matthias [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Mistakes in date conversion for future date/time (POSIXct)
On 04/04/2014 10:55 AM, Winkler, Matthias wrote: Dear R-users, I'm working on datasets which contain data from the years 1960 to 2100 with a timestep of one hour. Every year has 365 days, leap years are ignored. After reading the dataset with R I convert the column which contains date/time to POSIXct: as.POSIXct(strptime(MyData [,1], format=%d.%m.%Y : %H)) After that, I divide the data with split() into parts of one year each. Then I recognized, that the years for some rows are obviously converted wrong: They show years larger than 2100 (see example below). I've controlled my original dataset, but the dates are correct there. I also produced a date/time-sequence in R, which showed the same mistakes (see example below). The mistakes occur at the same dates like in my datasets. It's always at the end of march. datetimesequenz - seq.POSIXt(from=as.POSIXct(1960-01-01 00:00), to=as.POSIXct(2100-01-01 00:00), by=1 hour) levels(as.factor(strftime(datetimesequenz, format=%Y))) [1] 1960 1961 1962 1963 1964 1965 1966 1967 1968 1969 1970 1971 1972 1973 1974 1975 1976 1977 [19] 1978 1979 1980 1981 1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992 1993 1994 1995 [37] 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010 2011 2012 2013 [55] 2014 2015 2016 2017 2018 2019 2020 2021 2022 2023 2024 2025 2026 2027 2028 2029 2030 2031 [73] 2032 2033 2034 2035 2036 2037 2038 2039 2040 2041 2042 2043 2044 2045 2046 2047 2048 2049 [91] 2050 2051 2052 2053 2054 2055 2056 2057 2058 2059 2060 2061 2062 2063 2064 2065 2066 2067 [109] 2068 2069 2070 2071 2072 2073 2074 2075 2076 2077 2078 2079 2080 2081 2082 2083 2084 2085 [127] 2086 2087 2088 2089 2090 2091 2092 2093 2094 2095 2096 2097 2098 2099 2100 2101 2102 2103 [145] 2105 2107 2109 2110 2111 2112 2113 2114 2115 2117 2118 2120 2121 2122 2124 2125 2126 2128 [163] 2129 2130 2131 2132 2133 2135 2137 2138 2139 2140 2141 2142 2143 2145 2146 2148 2149 2150 [181] 2152 2153 2154 2156 2157 2158 2159 2160 2161 2166 Has anybody experienced the same problem and knows a workaround? I'm using R 3.0.1 under Windows 7 64bit. I also tried this with R 3.0.3, it showed the same problem. Thank you for your help! I don't see this in 3.1.0 beta. Do you? Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Base within reverses column order
I just noticed this annoyance, but I'm not the first one, apparently -- see http://lists.r-forge.r-project.org/pipermail/datatable-help/2012-May/001176.html The thread never answered the OP's question Is this a bug? so I assume the answer, unfortunately, is No. If not a bug, do users of within have a workaround to produce a result with columns as ordered within 'within'? I can think of a way using names and subset-with-select, but that seems unduly kludgy. Thanks, Dan __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Base within reverses column order
On 04/04/2014 1:32 PM, Dan Murphy wrote: I just noticed this annoyance, but I'm not the first one, apparently -- see http://lists.r-forge.r-project.org/pipermail/datatable-help/2012-May/001176.html The thread never answered the OP's question Is this a bug? so I assume the answer, unfortunately, is No. If not a bug, do users of within have a workaround to produce a result with columns as ordered within 'within'? I can think of a way using names and subset-with-select, but that seems unduly kludgy. I wouldn't be surprised if it is not consistent about that. It uses as.list to convert an environment to a list, and that's where the reversal occurs: but since environments are unordered collections of objects, you just happen to be seeing an undocumented and unpromised property of the internal implementation. If the order matters to you, then create your initial dataframe with the new variables (set to NA, for example), or reorder it afterwards. But generally speaking even in a dataframe (which is an ordered collection of objects), it's better to program in a way that doesn't make assumptions about the order. Columns have names, and you should use those. Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] par(mfrow)
Hi, I have some problems using the par function: I want to split the screen into 2 rows and 4 col and I type par(mfrow=c(2, 4)) but when I do that, instead of setting a graphical parameter, it creates a white Quarz. I'm currently using the R base version for Mac Os, 3.0.3 . Could you give me an help? Thank you very much, Emanuele __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] average of rows of each column
Dear useRs, I have a matrix of 120 row and 1000 columns.What I want is to get an average of a set of 12 rows starting from 1 till 120 for each column. Precisely, for column 1 the average of 1:10 rows, 11:20 rows 111:120. similarly for column 2, 3, 4 1000. So in the end i should have a matrix with 12 rows and 1000 columns. Thankyou very much in advance. Eliza [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to plot data using ggplot
1. Look into the ggmap package if you want to overlay your data onto a map. 2. Re your color scale representation, define 'appropriately'. Do you mean a continuous range expressible in a colorbar or a discrete range, and if the latter, what intervals did you have in mind? Dennis On Fri, Apr 4, 2014 at 2:42 AM, drunkenphd enrr...@fimif.upt.al wrote: Hi, I have a list of cities and their coordinates, and also for each city I have a variable varA which I want to represent in a map using ggplot. For example : CityA lat 22.93977 lon 46.70663varA 545 CityB lat 23.93977 lon 46.70663varA 122 VarA values begin from 0 to 3000. I want the color scale to represent this range appropriately. Can you help Regards -- View this message in context: http://r.789695.n4.nabble.com/How-to-plot-data-using-ggplot-tp4688168.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Revolutions blog: March roundup
Revolution Analytics staff write about R every weekday at the Revolutions blog: http://blog.revolutionanalytics.com and every month I post a summary of articles from the previous month of particular interest to readers of r-help. In case you missed them, here are some articles related to R from the month of March: Francis Smart offers five excellent reasons to use R, and notes that R is the top Google Search for statistical software: http://bit.ly/1dYHrGv Revolution Analytics is offering R training for SAS users in Singapore and online: http://bit.ly/1dYHphT The number of R user groups worldwide continues to grow, and there have already been over 135 meetings in 2014: http://bit.ly/1dYHphV Color palettes for R charts based on the production design of Wes Anderson movies: http://bit.ly/1dYHrGu A history of ensemble methods, by Mike Bowles: http://bit.ly/1dYHrGt An eBook on Big Data and Data Science by the publishers of the Big Data Journal includes articles based on R: http://bit.ly/1dYHphU An in-depth tutorial by Gaston Sanchez on handling character data with R: http://bit.ly/1dYHpi3 Joseph Rickert suggests several large, open data sets you can analyze with R: http://bit.ly/1dYHrGz Rodrigo Zamith updates his web-based application to compare NCAA basketball team performance: http://bit.ly/1dYHpyg Many R projects are under consideration for the 2014 Google Summer of Code: http://bit.ly/1dYHpyh Bob Muenchen shares his secrets of teaching with R: http://bit.ly/1dYHrGA The Atlanta Big Data Analytics Team Challenge sponsored R users to help CARE International: http://bit.ly/1dYHrGB The Human Rights Data Analysis Group uses R and ensemble models to quantify the impact of the war in Syria: http://bit.ly/1dYHrGD An index of contributed R documentation, assembled into an R meta book: http://bit.ly/1dYHrGF The deadline for submitting tutorials to the useR! 2014 conference in LA has been extended to April 10: http://bit.ly/1dYHpyk Derek Norton describes how to do ridge regression using the rxCovCor function of the RevoScaleR package: http://bit.ly/1dYHrGG In an op-ed at RSS StatsLife, I review the role of statisticians in data privacy: http://bit.ly/1dYHpyo A brief summary of the improvements in R 3.0.3: http://bit.ly/1dYHpyr Hidden Markov models in R, with application to detection regime-switching events in financial markets: http://bit.ly/1dYHpys Why automating data science is dangerous without human supervision and statistical expertise: http://bit.ly/1dYHpyt A history of Emacs and ESS-mode for R, by Rodney Sparapani: http://bit.ly/1dYHpyv Some news articles about R and Revolution Analytics in Wired, ComputerWorld, Inside BigData and Datanami: http://bit.ly/1dYHpyu Some non-R stories in the past month included: a real photo that looks like Sim City (http://bit.ly/1dYHrWY), a video of Europe's constantly-changing borders (http://bit.ly/1dYHpyw), the new FiveThirtyEight data journalism site (http://bit.ly/1dYHrWZ), bad-mannered cats (http://bit.ly/1dYHpOQ), and a surprising demonstration of change blindness (http://bit.ly/1dYHpOS). Meeting times for local R user groups (http://bit.ly/eC5YQe) can be found on the updated R Community Calendar at: http://bit.ly/bb3naW If you're looking for more articles about R, you can find summaries from previous months at http://blog.revolutionanalytics.com/roundups/. You can receive daily blog posts via email using services like blogtrottr.com, or join the Revolution Analytics mailing list at http://revolutionanalytics.com/newsletter to be alerted to new articles on a monthly basis. As always, thanks for the comments and please keep sending suggestions to me at da...@revolutionanalytics.com . Don't forget you can also follow the blog using an RSS reader, via email using blogtrottr.com, or by following me on Twitter (I'm @revodavid). Cheers, # David -- David M Smith da...@revolutionanalytics.com Chief Community Officer, Revolution Analytics http://blog.revolutionanalytics.com Tel: +1 (650) 646-9523 (Seattle WA, USA) Twitter: @revodavid __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] par(mfrow)
Hi, re: I have some problems using the par function: I want to split the screen into 2 rows and 4 col and I type par(mfrow=c(2, 4)) but when I do that, instead of setting a graphical parameter, it creates a white Quarz. I'm currently using the R base version for Mac Os, 3.0.3 . Could you give me an help? Thank you very much, But that's correct, if you don't plot something afterwards. Try plotting 8 x-y graphs, then you'll see that 8 small plot will appear (unless the margins will prove to be too large). Good luck, Franklin Bretschneider Dept of Biology Utrecht University brets...@xs4all.nl __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] average of rows of each column
Something like (only 20 columns here): x - matrix(rnorm(120*20), 120, 20) xagg - aggregate(x, list(rep(1:12, each=10)), mean) - David L Carlson Department of Anthropology Texas AM University College Station, TX 77840-4352 Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of eliza botto Sent: Friday, April 4, 2014 1:08 PM To: r-help@r-project.org Subject: [R] average of rows of each column Dear useRs, I have a matrix of 120 row and 1000 columns.What I want is to get an average of a set of 12 rows starting from 1 till 120 for each column. Precisely, for column 1 the average of 1:10 rows, 11:20 rows 111:120. similarly for column 2, 3, 4 1000. So in the end i should have a matrix with 12 rows and 1000 columns. Thankyou very much in advance. Eliza [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] solicit help to read in 384 plate color image
Hi, I am doing an experiment which results different colors of different intensities in the 384 micro titer plate. I took a picture of the plate by scanning in the image as a jpeg file and now I want to 1. read in the image file 2. grid the content 3. need to extract the intensity and color of each well. Is there a R package I can use for that? there is a package called gitter which is almost satisfying my needs. However, it can only read in grey values and no colors. If someone has the code, please share. -- Thanks. waverley [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] average of rows of each column
Hello,
Try the following.
m - 120
n - 10 # in your case this is 1000
mat - matrix(rnorm(n*m), nrow = m)
fun - function(x, na.rm = TRUE){
tapply(x, rep(1:12, each = 10), mean, na.rm = na.rm)
}
apply(mat, 2, fun)
apply(mat, 2, fun, na.rm = FALSE) # alternative
Hope this helps,
Rui Barradas
Em 04-04-2014 19:08, eliza botto escreveu:
Dear useRs,
I have a matrix of 120 row and 1000 columns.What I want is to get an average of
a set of 12 rows starting from 1 till 120 for each column. Precisely, for
column 1 the average of 1:10 rows, 11:20 rows 111:120. similarly for column
2, 3, 4 1000. So in the end i should have a matrix with 12 rows and 1000
columns.
Thankyou very much in advance.
Eliza
[[alternative HTML version deleted]]
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[R] how to change annotations in contour function from rsm package
Dear All, I am using R3.0.3 and rsm 2.04. Since I want do log transformation on my data, so I want change annotation of Slice at ... For example, I want change (Slice at W = 1.25, L=2) in the first graph into (Slice at W = log(1.25), L=log(2)). Can anyone tell me how can I change it? Thanks library(rsm) heli.rsm - rsm(ave ~ block + SO(x1, x2, x3, x4), data = heli) windows(width=10.8/2*3, height=10.8) par(mfrow = c(2, 3)) contour(heli.rsm, ~ x1 + x2 + x3 + x4, image = TRUE) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Mistakes in date conversion for future date/time (POSIXct)
On Apr 4, 2014, at 9:54 AM, Duncan Murdoch wrote: On 04/04/2014 10:55 AM, Winkler, Matthias wrote: Dear R-users, I'm working on datasets which contain data from the years 1960 to 2100 with a timestep of one hour. Every year has 365 days, leap years are ignored. After reading the dataset with R I convert the column which contains date/time to POSIXct: as.POSIXct(strptime(MyData [,1], format=%d.%m.%Y : %H)) After that, I divide the data with split() into parts of one year each. Then I recognized, that the years for some rows are obviously converted wrong: They show years larger than 2100 (see example below). I've controlled my original dataset, but the dates are correct there. I also produced a date/time-sequence in R, which showed the same mistakes (see example below). The mistakes occur at the same dates like in my datasets. It's always at the end of march. datetimesequenz - seq.POSIXt(from=as.POSIXct(1960-01-01 00:00), to=as.POSIXct(2100-01-01 00:00), by=1 hour) levels(as.factor(strftime(datetimesequenz, format=%Y))) [1] 1960 1961 1962 1963 1964 1965 1966 1967 1968 1969 1970 1971 1972 1973 1974 1975 1976 1977 [19] 1978 1979 1980 1981 1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992 1993 1994 1995 [37] 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010 2011 2012 2013 [55] 2014 2015 2016 2017 2018 2019 2020 2021 2022 2023 2024 2025 2026 2027 2028 2029 2030 2031 [73] 2032 2033 2034 2035 2036 2037 2038 2039 2040 2041 2042 2043 2044 2045 2046 2047 2048 2049 [91] 2050 2051 2052 2053 2054 2055 2056 2057 2058 2059 2060 2061 2062 2063 2064 2065 2066 2067 [109] 2068 2069 2070 2071 2072 2073 2074 2075 2076 2077 2078 2079 2080 2081 2082 2083 2084 2085 [127] 2086 2087 2088 2089 2090 2091 2092 2093 2094 2095 2096 2097 2098 2099 2100 2101 2102 2103 [145] 2105 2107 2109 2110 2111 2112 2113 2114 2115 2117 2118 2120 2121 2122 2124 2125 2126 2128 [163] 2129 2130 2131 2132 2133 2135 2137 2138 2139 2140 2141 2142 2143 2145 2146 2148 2149 2150 [181] 2152 2153 2154 2156 2157 2158 2159 2160 2161 2166 Has anybody experienced the same problem and knows a workaround? I'm using R 3.0.1 under Windows 7 64bit. I also tried this with R 3.0.3, it showed the same problem. Thank you for your help! I don't see this in 3.1.0 beta. Do you? I'm not seeing it on a Mac in 3.0.2 either. max(datetimesequenz) [1] 2100-01-01 PST length(datetimesequenz) [1] 1227241 Duncan Murdoch David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] average of rows of each column
Dear David and Rui, Thankyou very much. :D Eliza From: dcarl...@tamu.edu To: eliza_bo...@hotmail.com; r-help@r-project.org Subject: RE: [R] average of rows of each column Date: Fri, 4 Apr 2014 15:14:32 -0500 Something like (only 20 columns here): x - matrix(rnorm(120*20), 120, 20) xagg - aggregate(x, list(rep(1:12, each=10)), mean) - David L Carlson Department of Anthropology Texas AM University College Station, TX 77840-4352 Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of eliza botto Sent: Friday, April 4, 2014 1:08 PM To: r-help@r-project.org Subject: [R] average of rows of each column Dear useRs, I have a matrix of 120 row and 1000 columns.What I want is to get an average of a set of 12 rows starting from 1 till 120 for each column. Precisely, for column 1 the average of 1:10 rows, 11:20 rows 111:120. similarly for column 2, 3, 4 1000. So in the end i should have a matrix with 12 rows and 1000 columns. Thankyou very much in advance. Eliza [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Sweave files into LaTex
Hi,
I'm writing a thesis in Latex (say master.tex). I'd like to include R
code/results from an .Rwd file. I've naively tried:
1) Add ONLY the code below in Rcode.Rnw file:
\section{Exploratory data analysis}
eval=TRUE, echo=FALSE=
library(ggplot2)
data(diamonds)
head(diamonds)
@
2) Then, in the master.tex file add the following line:
\include{Rcode.Rnw}
But of course, that didn't work.Any help would be much appreciated.
Best,
Axel.
[[alternative HTML version deleted]]
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Re: [R] Sweave files into LaTex
On 04/04/2014, 7:10 PM, Axel Urbiz wrote:
Hi,
I'm writing a thesis in Latex (say master.tex). I'd like to include R
code/results from an .Rwd file. I've naively tried:
1) Add ONLY the code below in Rcode.Rnw file:
\section{Exploratory data analysis}
eval=TRUE, echo=FALSE=
library(ggplot2)
data(diamonds)
head(diamonds)
@
2) Then, in the master.tex file add the following line:
\include{Rcode.Rnw}
But of course, that didn't work.Any help would be much appreciated.
You want
\include{Rcode.tex}
But you have to run Sweave to produce Rcode.tex from Rcode.Rnw. The
patchDVI package has functions to make this easy if you're using
TeXWorks or some other LaTeX editors -- see the vignette.
Duncan Murdoch
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[R] rehh package for iHS and Rsb on NGS data
Hello expert community. Is there anybody whose used rehh package for iHS and rsb. I have gone through the tutorial a dozen times, I need expert help to enable me apply it to my p.falciparum snp data from the illumina platform. Thanks James Abugri -- * The information contained in this email and any attachments may be legally privileged and confidential. If you are not an intended recipient, you are hereby notified that any dissemination, distribution, or copying of this e-mail is strictly prohibited. If you have received this e-mail in error, please notify the sender and permanently delete the e-mail and any attachments immediately. You should not retain, copy or use this e-mail or any attachments for any purpose, nor disclose all or any part of the contents to any other person.* [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to plot data using ggplot
djmuseR wrote Do you mean a continuous range expressible in a colorbar or a discrete range, and if the latter, what intervals did you have in mind? I mean diskrete values like : 54508 25 101 420 95 928 24 1656 108 18 213 70. The problem is that range is from 0-4000 while only one value is near 4000 and all the others are below 1000. Please advice.. Regards -- View this message in context: http://r.789695.n4.nabble.com/How-to-plot-data-using-ggplot-tp4688168p4688191.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Subsetting data by ID with different constraints
Hello, I have a data set with many individuals all with multiple timed observations, and I would like to subset the data to exclude later timed observations. However, I would like to exclude different amounts of data for each individual. These individuals have two types of data: DV and dose. What I would like to do is exclude later instances when one of the types of data is no longer included. The data is structured with an (approximate) 28 day cycle. Each individual has a baseline DV, and on day 1, they receive their first dose. Around day 28, they will have their first DV observed. This means that an individual should have one less dose data item than they have DV data items. What I would like is to take the following: IDTIMEDV DOSE TYPE 1 0 0NA 2 1 1 NA 1001 1 27 0NA 2 1 29 NA 1001 1 54 2NA 2 1 84 3NA 2 1 100 3NA 2 1 127 3NA 2 2 0 0NA 2 2 1 NA 1201 2 28 4NA 2 2 29 NA 1201 2 56 8NA 2 2 57 NA 1001 3 0 2NA 2 3 1 NA 80 1 3 28 5NA 2 3 56 2NA 1 3 84 1NA 2 4 0 0NA 2 4 1 NA 1001 4 29 NA 1001 4 57 NA 1001 4 85 NA 1001 ... And turn it into: IDTIMEDV DOSE TYPE 1 0 0NA 2 1 1 NA 1001 1 27 0NA 2 1 29 NA 1001 1 54 2NA 2 2 0 0NA 2 2 1 NA 1201 2 28 4NA 2 2 29 NA 1201 2 56 8NA 2 3 0 2NA 2 3 1 NA 80 1 3 28 5NA 2 4 0 0NA 2 ... My thought for how to do this was to: (1) Subset the data by the maximum time an individual had an observed DV (type=2). However, this will be a different time for every patient, and I was unsure how to do this type of subsetting. (2) After I had done that, I would want to take my new subsetted data and determine the maximum time an individual had a dose. Then I would determine the total rows of data a patient had up to their last dose data time. Then I could subset the data by taking the first n+1 observations for each individual, n=total rows of data a patient had up to their last dose data time. This step I would hope I could determine from knowing how to do step (1), if I can use table and max interchangeably. Any help would be appreciated! [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] rehh package for iHS and Rsb on NGS data
On Apr 4, 2014, at 11:46 PM, James Abugri wrote: Hello expert community. Is there anybody whose used rehh package for iHS and rsb. I have gone through the tutorial a dozen times, I need expert help to enable me apply it to my p.falciparum snp data from the illumina platform. This sounds like it would be more appropriate on the BioConductor forum. Thanks James Abugri -- * The information contained in this email and any attachments may be legally privileged and confidential. If you are not an intended recipient, you are hereby notified that any dissemination, distribution, or copying of this e-mail is strictly prohibited. If you have received this e-mail in error, please notify the sender and permanently delete the e-mail and any attachments immediately. You should not retain, copy or use this e-mail or any attachments for any purpose, nor disclose all or any part of the contents to any other person.* [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Removing White spaces with NA
Hi,
Check if this works:
n - 1e7
dat - data.frame(Col1=c(A, , B,C, ,,D,rep('',n)),
stringsAsFactors=FALSE)
dat2 - dat
dat[dat==''] - NA
which(dat$Col1=='')
#integer(0)
#or
dat2$Col1[dat2$Col1==''] - NA
which(dat2$Col1=='')
#integer(0)
A.K.
On Wednesday, April 2, 2014 2:20 PM, arun smartpink...@yahoo.com wrote:
Hi,
May be this helps:
dat - data.frame(Col1=c(A, , B,C, ,,D), stringsAsFactors=FALSE)
is.na(dat) - dat==''
dat$Col1
#[1] A NA B C NA NA D
A.K.
Hi All, I have a table and a column with values as below Col1
A B
C D I need to replace the Empty cells with the value NA as below
Col1
A
NA
B
C
NA
NA
D I tried a code, which was not working.
Table.name$column.name - gsub(,NA, table.name$column.name) Can anyone help
me with this ?
Thanks and regards,
Praveen
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and provide commented, minimal, self-contained, reproducible code.
[R] Aggregate time series from daily to monthly by date and site
Hi, I have daily data arranged by date and site. Keeping the number of columns as there are, I will like to aggregate (FUN=mean) from daily to monthly the following data (only part is shown here) which starts in 1971 and ends in 1980. Year Month Day Site Sim001 Sim002 Sim003 Sim004 1 1971 1 1 GGG1 8.58 -12.67 4.45 -1.31 2 1971 1 1 GGG2 11.82 -9.94 -3.37 4.94 3 1971 1 1 GGG3 7.72 -11.94 -1.17 4.70 4 1971 1 1 GGG4 8.93 -10.81 4.66 2.88 5 1971 1 1 GGG5 9.82 -6.78 -4.19 -0.01 6 1971 1 1 GGG6 13.93 -3.39 -3.84 1.83 7 1971 1 1 GGG7 10.94 -7.58 1.74 -7.51 8 1971 1 1 GGG8 5.07 -16.09 1.26 1.12 9 1971 1 1 GGG9 11.13 -9.96 -7.06 5.25 10 1971 1 1 GG10 7.66 -8.68 -2.65 5.25 11 1971 1 1 GG11 1.06 6.14 -4.88 3.78 12 1971 1 1 GG12 14.93 -12.43 -4.06 4.94 13 1971 1 1 GG13 7.56 -10.81 -2.32 2.32 14 1971 1 1 GG14 6.18 -7.58 -1.64 9.83 15 1971 1 1 GG15 10.96 -0.62 0.56 -1.59 16 1971 1 1 GG16 4.94 1.52 0.31 6.45 17 1971 1 1 GG17 0.79 0.83 -0.35 4.26 18 1971 1 1 GG18 4.91 -3.29 -5.69 3.10 19 1971 1 1 GG19 0.68 -0.50 3.35 5.50 20 1971 1 1 GG20 4.50 1.14 4.84 6.94 21 1971 1 1 GG21 3.13 3.35 3.62 2.76 22 1971 1 1 GG22 2.91 1.10 0.77 5.10 23 1971 1 1 GG23 -2.27 -5.25 -3.05 1.95 24 1971 1 1 GG24 8.18 2.00 -0.42 15.13 25 1971 1 1 GG25 3.87 -4.09 -2.55 -9.18 26 1971 1 1 GG26 5.10 2.28 1.34 2.88 27 1971 1 1 GG27 7.23 2.46 2.89 4.28 28 1971 1 1 GG28 8.55 5.64 3.09 -5.01 29 1971 1 1 GG29 1.39 4.64 9.79 -0.27 30 1971 1 1 GG30 6.85 -12.11 4.98 1.91 31 1971 1 1 GG31 4.25 -2.21 9.59 -1.46 32 1971 1 1 GG32 -0.24 -16.54 4.99 -0.60 33 1971 1 1 GG33 9.86 -7.38 11.77 -8.99 34 1971 1 1 GG34 9.92 -16.33 13.07 -8.79 35 1971 1 1 GG35 5.11 -7.63 0.41 -3.09 36 1971 1 1 GG36 6.14 -11.61 10.38 -7.09 37 1971 1 1 GG37 8.14 -12.78 11.01 -5.20 38 1971 1 1 GG38 7.52 -12.86 3.43 -7.55 39 1971 1 1 GG39 4.19 -9.99 6.08 -4.04 40 1971 1 1 GG40 1.02 4.84 0.55 -3.80 41 1971 1 1 GG41 -2.43 -13.75 6.49 -10.66 42 1971 1 1 GG42 6.85 -12.33 2.85 -6.34 43 1971 1 1 GG43 4.94 -13.43 11.17 -3.62 44 1971 1 1 GG44 8.11 -21.13 11.32 -8.49 45 1971 1 1 GG45 7.34 -12.63 -0.89 -2.29 46 1971 1 1 GG46 10.56 -3.16 -0.48 0.38 47 1971 1 1 GG47 -6.52 1.61 10.80 5.25 48 1971 1 1 GG48 2.66 -2.36 1.86 8.60 49 1971 1 1 GG49 -4.89 5.54 6.63 5.83 50 1971 1 1 GG50 0.11 3.59 5.14 8.94 51 1971 1 1 GG51 3.90 1.23 4.13 9.86 52 1971 1 1 GG52 3.87 -0.25 8.72 4.62 53 1971 1 1 GG53 2.55 -1.49 15.01 4.33 54 1971 1 1 GG54 -0.20 -1.65 4.78 10.15 55 1971 1 1 GG55 5.09 0.90 5.56 7.87 56 1971 1 1 GG56 -2.40 -2.29 5.69 9.07 57 1971 1 1 GG57 1.32 -2.35 10.39 0.04 58 1971 1 1 GG58 3.49 -2.01 8.99 2.85 59 1971 1 1 GG59 4.93 -2.07 6.95 6.00 60 1971 1 1 GG60 -9.58 1.37 10.59 4.54 61 1971 1 1 GG61 9.08 -0.64 3.92 13.50 62 1971 1 1 GG62 2.85 4.75 3.40 12.39 63 1971 1 1 GG63 7.71 3.02 3.95 11.79 64 1971 1 1 GG64 4.50 5.44 0.87 6.29 65 1971 1 1 GG65 0.99 3.76 2.28 15.45 66 1971 1 1 GG66 8.72 5.16 1.11 15.82 67 1971 1 1 GG67 12.45 2.54 4.36 19.79 68 1971 1 1 GG68 8.83 4.11 6.21 13.12 69 1971 1 1 GG69 8.94 5.03 1.73 6.50 70 1971 1 1 GG70 5.05 -1.12 2.50 -4.63 71 1971 1 1 GG71 9.82 4.53 4.19 1.79 72 1971 1 1 GG72 11.72 -0.15 1.85 -0.80 73 1971 1 1 GG73 1.21 -4.98 8.65 1.29 74 1971 1 1 GG74 7.92 0.85 6.24 8.88 75 1971 1 1 GG75 3.45 -3.04 7.82 1.28 76 1971 1 1 GG76 1.34 -0.06 7.43 6.55 77 1971 1 1 GG77 8.25 -3.01 5.19 5.78 78 1971 1 1 GG78 2.92 -1.10 -1.71 5.46 79 1971 1 1 GG79 2.10 4.02 -3.16 2.83 80 1971 1 1 GG80 -3.19 1.77 -2.66 8.00 81 1971 1 1 GG81 4.75 -3.36 -7.00 6.25 82 1971 1 1 GG82 -0.30 1.56 -2.08 4.94 83 1971 1 1 GG83 1.69 -1.63 0.36 5.01 84 1971 1 1 GG84 3.31 1.12 8.61 5.32 85 1971 1 1 GG85 5.18 -2.39 3.22 2.95 86 1971 1 1 GG86 2.43 -2.05 7.99 7.46 87 1971 1 1 GG87 3.02 4.51 -1.19 5.71 88 1971 1 1 GG88 -5.31 1.52 11.38 -3.51 89 1971 1 1 GG89 -6.70 -0.61 10.20 3.51 90 1971 1 1 GG90 -5.90 2.54 8.87 9.46 91 1971 1 1 GG91
Re: [R] Aggregate time series from daily to monthly by date and site
You have been around long enough that we should not have to tell you how to provide data in a reproducible manner... read ?dput. --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On April 4, 2014 9:02:03 PM PDT, Zilefac Elvis zilefacel...@yahoo.com wrote: Hi, I have daily data arranged by date and site. Keeping the number of columns as there are, I will like to aggregate (FUN=mean) from daily to monthly the following data (only part is shown here) which starts in 1971 and ends in 1980. Year Month Day Site Sim001 Sim002 Sim003 Sim004 1 1971 1 1 GGG1 8.58 -12.67 4.45 -1.31 2 1971 1 1 GGG2 11.82 -9.94 -3.37 4.94 3 1971 1 1 GGG3 7.72 -11.94 -1.17 4.70 4 1971 1 1 GGG4 8.93 -10.81 4.66 2.88 5 1971 1 1 GGG5 9.82 -6.78 -4.19 -0.01 6 1971 1 1 GGG6 13.93 -3.39 -3.84 1.83 7 1971 1 1 GGG7 10.94 -7.58 1.74 -7.51 8 1971 1 1 GGG8 5.07 -16.09 1.26 1.12 9 1971 1 1 GGG9 11.13 -9.96 -7.06 5.25 10 1971 1 1 GG10 7.66 -8.68 -2.65 5.25 11 1971 1 1 GG11 1.06 6.14 -4.88 3.78 12 1971 1 1 GG12 14.93 -12.43 -4.06 4.94 13 1971 1 1 GG13 7.56 -10.81 -2.32 2.32 14 1971 1 1 GG14 6.18 -7.58 -1.64 9.83 15 1971 1 1 GG15 10.96 -0.62 0.56 -1.59 16 1971 1 1 GG16 4.94 1.52 0.31 6.45 17 1971 1 1 GG17 0.79 0.83 -0.35 4.26 18 1971 1 1 GG18 4.91 -3.29 -5.69 3.10 19 1971 1 1 GG19 0.68 -0.50 3.35 5.50 20 1971 1 1 GG20 4.50 1.14 4.84 6.94 21 1971 1 1 GG21 3.13 3.35 3.62 2.76 22 1971 1 1 GG22 2.91 1.10 0.77 5.10 23 1971 1 1 GG23 -2.27 -5.25 -3.05 1.95 24 1971 1 1 GG24 8.18 2.00 -0.42 15.13 25 1971 1 1 GG25 3.87 -4.09 -2.55 -9.18 26 1971 1 1 GG26 5.10 2.28 1.34 2.88 27 1971 1 1 GG27 7.23 2.46 2.89 4.28 28 1971 1 1 GG28 8.55 5.64 3.09 -5.01 29 1971 1 1 GG29 1.39 4.64 9.79 -0.27 30 1971 1 1 GG30 6.85 -12.11 4.98 1.91 31 1971 1 1 GG31 4.25 -2.21 9.59 -1.46 32 1971 1 1 GG32 -0.24 -16.54 4.99 -0.60 33 1971 1 1 GG33 9.86 -7.38 11.77 -8.99 34 1971 1 1 GG34 9.92 -16.33 13.07 -8.79 35 1971 1 1 GG35 5.11 -7.63 0.41 -3.09 36 1971 1 1 GG36 6.14 -11.61 10.38 -7.09 37 1971 1 1 GG37 8.14 -12.78 11.01 -5.20 38 1971 1 1 GG38 7.52 -12.86 3.43 -7.55 39 1971 1 1 GG39 4.19 -9.99 6.08 -4.04 40 1971 1 1 GG40 1.02 4.84 0.55 -3.80 41 1971 1 1 GG41 -2.43 -13.75 6.49 -10.66 42 1971 1 1 GG42 6.85 -12.33 2.85 -6.34 43 1971 1 1 GG43 4.94 -13.43 11.17 -3.62 44 1971 1 1 GG44 8.11 -21.13 11.32 -8.49 45 1971 1 1 GG45 7.34 -12.63 -0.89 -2.29 46 1971 1 1 GG46 10.56 -3.16 -0.48 0.38 47 1971 1 1 GG47 -6.52 1.61 10.80 5.25 48 1971 1 1 GG48 2.66 -2.36 1.86 8.60 49 1971 1 1 GG49 -4.89 5.54 6.63 5.83 50 1971 1 1 GG50 0.11 3.59 5.14 8.94 51 1971 1 1 GG51 3.90 1.23 4.13 9.86 52 1971 1 1 GG52 3.87 -0.25 8.72 4.62 53 1971 1 1 GG53 2.55 -1.49 15.01 4.33 54 1971 1 1 GG54 -0.20 -1.65 4.78 10.15 55 1971 1 1 GG55 5.09 0.90 5.56 7.87 56 1971 1 1 GG56 -2.40 -2.29 5.69 9.07 57 1971 1 1 GG57 1.32 -2.35 10.39 0.04 58 1971 1 1 GG58 3.49 -2.01 8.99 2.85 59 1971 1 1 GG59 4.93 -2.07 6.95 6.00 60 1971 1 1 GG60 -9.58 1.37 10.59 4.54 61 1971 1 1 GG61 9.08 -0.64 3.92 13.50 62 1971 1 1 GG62 2.85 4.75 3.40 12.39 63 1971 1 1 GG63 7.71 3.02 3.95 11.79 64 1971 1 1 GG64 4.50 5.44 0.87 6.29 65 1971 1 1 GG65 0.99 3.76 2.28 15.45 66 1971 1 1 GG66 8.72 5.16 1.11 15.82 67 1971 1 1 GG67 12.45 2.54 4.36 19.79 68 1971 1 1 GG68 8.83 4.11 6.21 13.12 69 1971 1 1 GG69 8.94 5.03 1.73 6.50 70 1971 1 1 GG70 5.05 -1.12 2.50 -4.63 71 1971 1 1 GG71 9.82 4.53 4.19 1.79 72 1971 1 1 GG72 11.72 -0.15 1.85 -0.80 73 1971 1 1 GG73 1.21 -4.98 8.65 1.29 74 1971 1 1 GG74 7.92 0.85 6.24 8.88 75 1971 1 1 GG75 3.45 -3.04 7.82 1.28 76 1971 1 1 GG76 1.34
Re: [R] Aggregate time series from daily to monthly by date and site
Hi, I have daily data arranged by date and site. Keeping the number of columns as there are, I will like to aggregate (FUN=mean) from daily to monthly the following data (only part is shown here) which starts in 1971 and ends in 1980. structure(list(Year = c(1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971, 1971), Month = c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1), Day = c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1), Site = c(GGG1, GGG2, GGG3, GGG4, GGG5, GGG6, GGG7, GGG8, GGG9, GG10, GG11, GG12, GG13, GG14, GG15, GG16, GG17, GG18, GG19, GG20, GG21, GG22, GG23, GG24, GG25, GG26, GG27, GG28, GG29, GG30, GG31, GG32, GG33, GG34, GG35, GG36, GG37, GG38, GG39, GG40, GG41, GG42, GG43, GG44, GG45, GG46, GG47, GG48, GG49, GG50, GG51, GG52, GG53, GG54, GG55, GG56, GG57, GG58, GG59, GG60, GG61, GG62, GG63, GG64, GG65, GG66, GG67, GG68, GG69, GG70, GG71, GG72, GG73, GG74, GG75, GG76, GG77, GG78, GG79, GG80, GG81, GG82, GG83, GG84, GG85, GG86, GG87, GG88, GG89, GG90, GG91, GG92, GG93, GG94, GG95, GG96, GG97, GG98, GG99, G100 ), Sim001 = c(8.58, 11.82, 7.72, 8.93, 9.82, 13.93, 10.94, 5.07, 11.13, 7.66, 1.06, 14.93, 7.56, 6.18, 10.96, 4.94, 0.79, 4.91, 0.68, 4.5, 3.13, 2.91, -2.27, 8.18, 3.87, 5.1, 7.23, 8.55, 1.39, 6.85, 4.25, -0.24, 9.86, 9.92, 5.11, 6.14, 8.14, 7.52, 4.19, 1.02, -2.43, 6.85, 4.94, 8.11, 7.34, 10.56, -6.52, 2.66, -4.89, 0.11, 3.9, 3.87, 2.55, -0.2, 5.09, -2.4, 1.32, 3.49, 4.93, -9.58, 9.08, 2.85, 7.71, 4.5, 0.99, 8.72, 12.45, 8.83, 8.94, 5.05, 9.82, 11.72, 1.21, 7.92, 3.45, 1.34, 8.25, 2.92, 2.1, -3.19, 4.75, -0.3, 1.69, 3.31, 5.18, 2.43, 3.02, -5.31, -6.7, -5.9, -4.73, -8.13, -7.67, 3.73, -2.4, 1.46, -4.71, 0.33, -3.11, 2.45), Sim002 = c(-12.67, -9.94, -11.94, -10.81, -6.78, -3.39, -7.58, -16.09, -9.96, -8.68, 6.14, -12.43, -10.81, -7.58, -0.62, 1.52, 0.83, -3.29, -0.5, 1.14, 3.35, 1.1, -5.25, 2, -4.09, 2.28, 2.46, 5.64, 4.64, -12.11, -2.21, -16.54, -7.38, -16.33, -7.63, -11.61, -12.78, -12.86, -9.99, 4.84, -13.75, -12.33, -13.43, -21.13, -12.63, -3.16, 1.61, -2.36, 5.54, 3.59, 1.23, -0.25, -1.49, -1.65, 0.9, -2.29, -2.35, -2.01, -2.07, 1.37, -0.64, 4.75, 3.02, 5.44, 3.76, 5.16, 2.54, 4.11, 5.03, -1.12, 4.53, -0.15, -4.98, 0.85, -3.04, -0.06, -3.01, -1.1, 4.02, 1.77, -3.36, 1.56, -1.63, 1.12, -2.39, -2.05, 4.51, 1.52, -0.61, 2.54, 2.88, 6.79, 5.5, -2.36, 4.18, -0.13, 5.68, 1.82, 3.21, 0.21), Sim003 = c(4.45, -3.37, -1.17, 4.66, -4.19, -3.84, 1.74, 1.26, -7.06, -2.65, -4.88, -4.06, -2.32, -1.64, 0.56, 0.31, -0.35, -5.69, 3.35, 4.84, 3.62, 0.77, -3.05, -0.42, -2.55, 1.34, 2.89, 3.09, 9.79, 4.98, 9.59, 4.99, 11.77, 13.07, 0.41, 10.38, 11.01, 3.43, 6.08, 0.55, 6.49, 2.85, 11.17, 11.32, -0.89, -0.48, 10.8, 1.86, 6.63, 5.14, 4.13, 8.72, 15.01, 4.78, 5.56, 5.69, 10.39, 8.99, 6.95, 10.59, 3.92, 3.4, 3.95, 0.87, 2.28, 1.11, 4.36, 6.21, 1.73, 2.5, 4.19, 1.85, 8.65, 6.24, 7.82, 7.43, 5.19, -1.71, -3.16, -2.66, -7, -2.08, 0.36, 8.61, 3.22, 7.99, -1.19, 11.38, 10.2, 8.87, 7.23, 8.07, 2.77, 9.61, -1.1, -2.05, 6.39, 6.6, -2.89, -6.41), Sim004 = c(-1.31, 4.94, 4.7, 2.88, -0.01, 1.83, -7.51, 1.12, 5.25, 5.25, 3.78, 4.94, 2.32, 9.83, -1.59, 6.45, 4.26, 3.1, 5.5, 6.94, 2.76, 5.1, 1.95, 15.13, -9.18, 2.88, 4.28, -5.01, -0.27, 1.91, -1.46, -0.6, -8.99, -8.79, -3.09, -7.09, -5.2, -7.55, -4.04, -3.8, -10.66, -6.34, -3.62, -8.49, -2.29, 0.38, 5.25, 8.6, 5.83, 8.94, 9.86, 4.62, 4.33, 10.15, 7.87, 9.07, 0.04, 2.85, 6, 4.54, 13.5, 12.39, 11.79, 6.29, 15.45, 15.82, 19.79, 13.12, 6.5, -4.63, 1.79, -0.8, 1.29, 8.88, 1.28, 6.55, 5.78, 5.46, 2.83, 8, 6.25, 4.94, 5.01, 5.32, 2.95, 7.46, 5.71, -3.51, 3.51, 9.46, 8.55, 6.71, 7.36, 10.96, 3.47, -1.99, 5.75, 1.56, -4.38, 0.67)), .Names = c(Year, Month, Day, Site, Sim001, Sim002, Sim003, Sim004), row.names = c(NA, 100L), class = data.frame) Thanks for your useful solution. Atem. [[alternative HTML version deleted]] __
