I dunno if this is the answer you are looking for, but if you want to
enforce that there is only one user set unique = True for the user in
the UserProfile class.
class UserProfile(models.Model):
user = models.ForeignKey(User, unique = True)
On Feb 11, 10:42 am, Aaron Fay <[EMAIL PROTECTED]>
I have a model something like,
class Task(models.Model):
name = models.CharField()
parent_task = models.ForeignKey('Task')
is_complete = models.BooleanField()
class TaskItem(models.Model)
name = models.CharField()
task = models.ForeignKey(Task)
is_complete = models.BooleanField()
I
'):
kwargs.update({'widget' :
forms.TextInput(attrs={'dojoType':'dijit.form.TextBox'})})
super(DojoCharField, self).__init__(*args, **kwargs)
or some thing similar.
On Feb 8, 12:32 am, shabda <[EMAIL PROTECTED]> wrote:
> I want to subclass CharField so that, its has a widget, and I do not
I want to subclass CharField so that, its has a widget, and I do not
always need to set it. So I do
class DojoCharField(forms.CharField):
def __init__(self, *args, **kwargs):
super(DojoCharField, self).__init__(*args, **kwargs)
if self.widget == None:
self.widget
I have a model like
class ProjectFile(models.Model):
project = models.ForeignKey(Project)
file = models.FileField(upload_to = '/files/')
class Project(models.Model):
name = models.CharField(max_length = 100)
With this the uploaded files will go to <>/files/,
howeverI want to upload
I want to use guids instead of auto incrementing keys with my models
for primary keys. I am using mysql. Using the UUID funcion in mysql I
can do this, but is there a simpler way?
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You received this message because you are subscribed to the
/ .
If you use them for learning or in a production setting be sure to let
me know. And if you got a few seconds, can you tell me your opinion at
http://day4.7days7apps.com/poll/Does-7days7apps-suck/
Thanks,
Shabda
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You received this message because you
http://www.b-list.org/weblog/2007/sep/22/standalone-django-scripts/
On Jan 28, 12:39 am, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
wrote:
> I'd like to run a few background processes on my server.
>
> They need access to the models in my app, the database, and the whole
> django framework.
>
>
do not get the exception.
The traceback is at,
http://dpaste.com/32727/
On Jan 27, 12:26 pm, shabda <[EMAIL PROTECTED]> wrote:
> When trying to save a model object I get an error saying,
>
> This is the line, which is causing the error. If I remove this line
> and add null +
When trying to save a model object I get an error saying,
This is the line, which is causing the error. If I remove this line
and add null + True to created_on firld I do not get the exception.
The traceback is at,
http://dpaste.com/32727/
--~--~-~--~~~---~--~~
I want to use django-queue-service to run long running processess in
background, but I can not find any documentation about this. Their
website http://code.google.com/p/django-queue-service/ does not
contain any docs. Does any one have any links, about how to use it?
(user__ne=some_uesr)
>
> On Jan 26, 6:14 am, shabda <[EMAIL PROTECTED]> wrote:
>
> > I have the model like,
>
> > class Blog(models.Model):
> > url = models.URLField()
>
> > class Entry(models.Model):
> > blog = models.ForeignKey(Blog)
> >
I have the model like,
class Blog(models.Model):
url = models.URLField()
class Entry(models.Model):
blog = models.ForeignKey(Blog)
user = models.ManyToManyField(User)
User is contrib.auth.db.USER
Now I given a blog and a user I need to find out all the Entry objects
which are a
My model is something like this,
class Job(models.Model):
name = models.CharField(...)
class Entry(models.Model):
job = models.ForeignKey(Job)
hrs_worked = models.IntegerField()
Now I want to get the sum of the hours worked in a job which I can get
by summing Entries for that job.
I want to use the ChoiceField to show choices depending on a query
set. For exmple the ChoiceField must get all active Users and them
show them in a drop down, something like what happens in Admin. How
can I do that?
--~--~-~--~~~---~--~~
You received this message
Does anybody have a code snippet for getting striped tables with
django? Basically I would need to apply alternating classes to the the
rows returned by the rowset. I do not want to do this from javascript,
but from server side.
--~--~-~--~~~---~--~~
You received
This is the right way to do so. Querysets are lazy. Only the rows
needed will be fetched in this example.
code_berzerker wrote:
> theres line of code in tutorial:
>
> Poll.objects.all().order_by('-pub_date')[:5]
>
> this gives 5 Poll objects. I wonder if this is efficient way of
> getting them?
I have field in a form like,
foo = forms.DateField(required = False, input_formats = '%m/%d/%Y')
Now when I try to enter a date like 10/25/2006 I am getting an error
string index out of range . Full stack trace,
Traceback:
File "C:\Python24\lib\site-packages\django\core\handlers\base.py" in
?
On Jan 22, 5:23 pm, Kenneth Gonsalves <[EMAIL PROTECTED]> wrote:
> On 22-Jan-08, at 5:45 PM, shabda wrote:
>
> > I want to have the one of the field for my form have a specific css
> > class. But if I do something like,
> > widget = forms.TextInput(attrs = {'size':60, 'cl
I want to have the one of the field for my form have a specific css
class. But if I do something like,
widget = forms.TextInput(attrs = {'size':60, 'class':'main'}
The textInput, and not its associated label gets the class. How can I
specify the class for label?
You have two underscores after start_date in start_date__month,
probably that is the problem. Change this to start_date_month, (one
underscore) and see if it works.
On Jan 22, 2:15 pm, omat <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> I have a model with a date field. When I try to filter based on
I am trying to use the manage.py dbshell call. I give the command,
F:\djangoprojects\polls>manage.py dbshell
This is giving me an error like
F:\djangoprojects\polls> ERROR 1045 (28000): Access denied for user
'ODBC'@'localhost' (using password: NO)
However in my settings.py I have set the user
Save yourself the trouble of writing a view function and use the
generic view direct_to_template
http://www.djangoproject.com/documentation/generic_views/#django-views-generic-simple-direct-to-template
On Jan 17, 12:50 pm, "Karen Tracey" <[EMAIL PROTECTED]> wrote:
> On Jan 17, 2008 2:32 AM,
function is being called.
On Jan 16, 9:54 pm, "Karen Tracey" <[EMAIL PROTECTED]> wrote:
> On Jan 16, 2008 11:31 AM, shabda <[EMAIL PROTECTED]> wrote:
>
>
>
>
>
> > I want to use some custom filters, and so I am using the steps given
> > at
> >h
I also have added this to __init__.py
__all__ = ['myfilters']
On Jan 16, 9:31 pm, shabda <[EMAIL PROTECTED]> wrote:
> I want to use some custom filters, and so I am using the steps given
> athttp://www.djangoproject.com/documentation/templates_python/#writing-...
>
> W
I want to use some custom filters, and so I am using the steps given
at
http://www.djangoproject.com/documentation/templates_python/#writing-custom-template-filters
What I did was,
1. Created a templatetags directory under th app and created
__init__.py, myfilters.py under it. Its structure is
Umm yes, I just meant that you get a own apache, and python instance,
and can customise it.
On Jan 15, 11:17 pm, Fredrik Lundh <[EMAIL PROTECTED]> wrote:
> shabda wrote:
> >> use django in a shared hosting environment or I need to buy a
> >> Dedicated server?
>
Can I
> use django in a shared hosting environment or I need to buy a
> Dedicated server?
While many people run Django in shared hosting, IMHO, that leads to
much more trouble than it is worth. But you surely do not need a
dedicated server for running django. I use Webfaction, and they are
one
You need to change this line
type="text/css" href="testing1.css" />
to
type="text/css" href="/static/testing1.css" />
On Jan 15, 1:00 pm, "James Bennett" <[EMAIL PROTECTED]> wrote:
> On Jan 15, 2008 1:08 AM, laspal <[EMAIL PROTECTED]> wrote:
>
> This:
>
> > (r'^static/(?P.*)$',
But If it were so how would running it from the development server
allow me to login?
On Jan 14, 5:13 pm, Kenneth Gonsalves <[EMAIL PROTECTED]> wrote:
> On 14-Jan-08, at 5:40 PM, shabda wrote:
>
> > Exception Type: SuspiciousOperation at /admin/
> > Exception Value
Trying to login many times in a row produced this Exception,
Exception Type: SuspiciousOperation at /admin/
Exception Value: User may have tampered with session cookie.
Full traceback,
Traceback:
File "/home/shabda/lib/python2.5/django/core/handlers/base.py" in
get_res
orms.error, and
forms.is_valid fails.
On Jan 13, 11:31 pm, Alex Koshelev <[EMAIL PROTECTED]> wrote:
> What daes it mean "I am unable to login". Error aqcures, exception
> raises or something else?
>
> On 13 янв, 18:33, shabda <[EMAIL PROTECTED]> wrote:
>
> > I have a v
I have a view function I am using for logging in people. When I am
deploying it to Apache/Mod_python, I am unable to login, but If I am
running it on the development server, I am able to login. Any
pointers?
(I am not using the builtin login, as I want to use newforms.)
The view function is,
def
_dob = request.POST['dob'] gets the string representation of dob, and
so python complains as it can't find the strftime method.
You need to change your code to,
_dob = form_name.cleaned_data['date_attribute_name']
form.cleaned_data, gets you the canonical representation for the data
type
Override __init__ for the Form, passing it the request object and
store it. Access it in .clean method.
On Jan 12, 10:45 am, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
wrote:
> I also just realized that the reason clean() wouldn't work when I
> tried to pass it the request as an argument is simply
Ove of my view function is,
def recently_featured (request):
featured = FeaturedPage.objects.all().order_by('-ordering')
paged_featured = ObjectPaginator(featured,
djikikisettings.details_per_page)
try:
page_num = request.GET['page']
page_num = int(page_num)
except:
Instead of this
def __init__(self, user):
profile = user.get_profile()
for g in profile.groups.all():
self.GROUP_CHOICES += (g.id, g.name)
super(MyForm, self)
Should it not be,
def __init__(self, user, *args, **kwargs):
profile = user.get_profile()
instead of
q_list = ObjectPaginator(Queue.objects.all(), 20)
Provide a order_by, if you would like them to be in descending order,
in order when they were created have,
q_list = ObjectPaginator(Queue.objects.all().order_by('-id'),
20)
Or better yet have a created_on field in the model,
Django adds an ID field to all models by default. Some questions about
that.
How are the values calculated. If Django asks the DB to provide it
those values, can we be sure, for all supported backends, that
1. The ids are auto incrementing, (and not just unique).
2. They start from zero.
3. The
I want to have a models.py like this,
class PageRevision(models.Model):
"""Stores a specific revision of the page"""
text = models.TextField()
revision_for = models.ForeignKey(Page, related_name =
'revision_for')
class Page(models.Model):
"""Stores the latest page, the page
text = forms.CharField(widget = forms.Textarea, initial =
self.page.text)
I just can't get this to work? Any place where I can look for dynamic
values to initial?
On Jan 6, 2:38 pm, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Sun, 2008-01-06 at 01:32 -0800, shabda wrote:
> >
I have a form, to which I want to pass some data when it is first
dipalyed,
My form is,
class EditPage(forms.Form):
text = forms.CharField(widget = forms.Textarea)
edit_summary = forms.CharField()
In my view I bind data to this form as
if request.method == 'GET':
page =
I have a model attribute of type TextField, where I am storing html
data. While displaying in template I do not want to escape it, and so
should mark this as safe. How can I do this? I read the link at
http://www.djangoproject.com/documentation/templates_python/#filters-and-auto-escaping
, but
Damn, I am feeling so stupid now :( . Thanks, that was the problem!
On Jan 6, 11:30 am, Kenneth Gonsalves <[EMAIL PROTECTED]> wrote:
> On 06-Jan-08, at 11:52 AM, shabda wrote:
>
> > I have an app, and that app is included in the installed_apps in
> > settings.py. Whn I
I have an app, and that app is included in the installed_apps in
settings.py. Whn I run manage.py runserver, tables referred in the app
are created. However none of the entities in that table are displayed
in the admin interface, which shows tables from contrib.sites and
contrib.auth. What could
Many of us would like to do a search for our website from within
django. With django-websearch[1] you can do a search for your site,
any general search on the web. I had talked about this a long time ago
here[2], and had the code, but never got around to posting this
online. The usage instruction
I have this code,
from django.contrib.auth import login
user = User.objects.get(username =
login_form.cleaned_data['username'])
login(request, user)
Which is giving me exception 'User' object has no attribute 'backend'
Traceback:
File
This is not really specific to Django, still.
How can I load test a website. I have a Django website, and I want to
see how many users its can serve concurrently, and how many pages can
it generate each second. How can I do this? (I am not looking to
profile it at this moment, I just want to see
Hi everyone,
Its almost the new year here, so Happy new year!
Let me just say a big thanks to every one on the django-users list,
who helped me with most of my questions, many of them inane. In
particular James Bennet and Malcolm Tredinnick were very helpul.
Django wont be as much fun without the
Using the testing framework how can we make sure that the correct view
got called.
Documentation at http://www.djangoproject.com/documentation/testing/#testcase
says that
(django.test.client can be used to) "Test that the correct view is
executed for a given URL.", but I can't figure out how.
To allow users to log-in,
I have something like this in urls.py
(r'^accounts/login/$', 'django.contrib.auth.views.login',
{'template_name': 'myapp/login.html'}),
But myapp/login.html expects a number of extra objects from that
populated by the login view. In other generic views, I could have
g_line
def items (self):
entries = BlogEntry.objects.all()[:10]
return entries
I get no error. What I do not understand is why should the main_feed
class be instantiated as soon as I import feeds? Should not the
instantiation happen only when the feed is accesed?
On Dec 22, 1:2
Getting this error, "Error while importing URLconf 'blogango.urls':
list index out of range". The exception stack does not give any cles
to what might be wrong. The exception stack is,
Traceback:
File "C:\Python24\lib\site-packages\django\core\handlers\base.py" in
get_response
73.
I have table say BlogEntries. Now to show an archive view I need to
find the months for which at least one entry exists in the database.
If I drop to raw SQL i can write to query to achieve this as,
SELECT
created_on
, count( created_on )
FROM `myapp_blogentry`
GROUP BY year( created_on ) ,
I am trying to generate a feed.
So I added the following lines to urls.py
feeds = {'latest': main_feed}
urlpatterns += patterns('',
(r'^rss/(?P.*)/$', 'django.contrib.syndication.views.feed',
{'feed_dict': feeds})
)
The class main_feed is,
def main_feed (Feed):
blog =
I can get access to a named url from within a template by using {% url
%} tag. What can I do to get access to named url from a view function?
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You received this message because you are subscribed to the Google Groups
"Django users" group.
To
Is there a widget which can generate HTML tables from within django?
My requirement is that I have a list of ModelObjects. Now I want to
provide a UI where user can select a number of the ModelObjects, and
then press the delte button to delte them or take a action on all of
them. What I am doing
Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Wed, 2007-12-19 at 05:35 -0800, shabda wrote:
> > I have a QuerySet returned by a call like this
>
> > foos = Foo.objects.filter(id__in = [1, 2, 3])
>
> > Now I want to update each of these elements' attributes to a specific
>
I have a QuerySet returned by a call like this
foos = Foo.objects.filter(id__in = [1, 2, 3])
Now I want to update each of these elements' attributes to a specific
value. What I need to do is some thing like,
for foo in foos:
foo.price = 0
foo.save()
But this would make as many
I am trying to get a value from request.POST. After form submit,
request.POST contains the values of the ids from the checkbox
selected. I want the list of those ids. SO I am doing something like,
entry_ids = request.POST['delete'] , but this doesnot pick the list,
but instead gets me the last
And is there some setting which allows markdown to convert linebreaks
to for all line breaks? Askin users to add two spaces when they
want a line break in comment seems strange to me.
On Dec 18, 10:39 pm, shabda <[EMAIL PROTECTED]> wrote:
> So should not {{text|escape|textile}} remove
range from some days, I can not see
the styling on some pages, :( .
On Dec 18, 9:03 pm, "James Bennett" <[EMAIL PROTECTED]> wrote:
> On Dec 18, 2007 8:56 AM, shabda <[EMAIL PROTECTED]> wrote:
>
> > I am using textile markup filter. When I am using a variable in the
&g
I am using textile markup filter. When I am using a variable in the
template without any filter they are being auto escaped, as they
should. However, if I use any markup filter like textile or markdown,
the text is not being auto escaped. Even using the escape filter
manually does not help. (as
I have my urls.py defined as
urlpatterns = patterns('app.views',
(r'^foo/$', 'foo'),
(r'^bar/$', 'bar'),)
Now from a template i need to access these urls. So inside the
template we can refer them as /foo/, /bar/. However later when I
change the urls.py, these urls defined in urls.py
I am using the paginators(django.core.paginator) as describes at
http://www.djangoproject.com/documentation/models/pagination/ .
Are paginators lazy, like .filter and related method are? If I use
paginator = ObjectPaginator(Article.objects.all(), 5)
and then paginator.get_page(0)
would the first
How about
for s in s2:
s.price.name *= s.price.name * .9
s.price.save()
You are getting a type error coz you can not mutlipy a Model object by
float, and that is what s.price is. BTW s2[0].price * .9 would not
have worked as well, because of the same reasons!
On Dec 16, 11:08
Since I need my logged in user to be available to each template, I
need to go and add context_instance=RequestContext(request) to each
view. Is there any setting which can make RequestContext available to
each view?
A related question is, I have some objects I need to make available to
each
The call ModelObject.objects.filter(id = entry_id).values() works fine
and the call to .values converts the model object to a dictionary. But
the call ModelObject.objects.get(id = entry_id).values() fails as the
object returned by get doesnot have a .values method. So to convert
this to
Bond <[EMAIL PROTECTED]> wrote:
> Hi,
>
> On Thu, Sep 20, 2007 at 08:47:57AM -0700, shabda wrote:
> > I have a number of pages which can potentially raise the
> > self.model.DoesNotExist exception. Whenever this exception is raised,
> > it maps to a HTTP 404 fo
I have a number of pages which can potentially raise the
self.model.DoesNotExist exception. Whenever this exception is raised,
it maps to a HTTP 404 for me. (That object does not exist in the
database, so I cant show this, so I want to return a 404 exception).
So apart from manually adding
max_age=max_age, expires=expires,
domain=settings.SESSION_COOKIE_DOMAIN,
44 secure=settings.SESSION_COOKIE_SECURE or None)
Putting SESSION_COOKIE_DOMAIN = '.example.tld' in settings.py solves
the problem.
On Sep 17, 6:06 pm, shabda <[EMAIL PROTECTED]> wrote:
>
If I have my site setup at example.tld and I have used the built in
django authentication system, any page at foo.example.tld (or any
subdomain of example.tld) is not able to access the user. So if the
view is accesed from a subdomain the login_required or other
decorators fail. It looks to me
:06 pm, shabda <[EMAIL PROTECTED]> wrote:
> I am trying to loging a user after they fill a form, using code
>
> if request.method == 'POST':
> data = request.POST.copy()
> errors = form.get_validation_errors(data)
> if not errors:
>
e = callback(request, *callback_args, **callback_kwargs)
File "/home/shabda/django/redpy/reddit/views.py" in register
290. login(request, user)
File "/usr/lib/python2.4/site-packages/django/contrib/auth/views.py"
in login
32. }, context_instance=RequestContext(request))
File "/usr
I have deployed a app on Apache with mod_python. I have the flat pages
app+middleware installed.
If I let debug = True in my settings.py and try to access any flatpage
url they work fine. But if I put the debug = False in settings.py, the
flatpages return 500 http respnse. Any way I can try to
I am trying to deploy django, and to test the install I am doing this,
I run django-admin.py startproject hello in directory /root/django
I have added to my httpd.conf
SetHandler python-program
PythonHandler django.core.handlers.modpython
SetEnv DJANGO_SETTINGS_MODULE hello.settings
I am trying to deploy django on a fedora 7 system.
After following these steps I am stuck!
(Long tale of woes ahead, If you can just tell me where can I get apxs
for apache, my problem is solved.)
1. Downloaded django, tried running setup.py, got an error saying
something like
unable to open
I need to write some doctests for my app.
So I am running the interactive shell by
manage.py shell
But since ipython is already installed on my system, the i python
prompt starts and I can't just copy paste the shell output for
creating the doctests. Is there some way I can ask the manage.py
Traceback (most recent call last):
File "C:\Python24\lib\site-packages\django\core\handlers\base.py" in
get_response
77. response = callback(request, *callback_args, **callback_kwargs)
File "C:\Python24\lib\site-packages\django\contrib\auth\decorators.py"
in _checklogin
14. return
Oh shucks, since I want to recalculate this attribute each time, I
would need this to be in the view function.
Still how would I override __init__ in django Models?
On Sep 5, 11:10 pm, shabda <[EMAIL PROTECTED]> wrote:
> That seems too easy to be true. :).
> I have one more query, wh
That seems too easy to be true. :).
I have one more query, where should I add this code? Considering this
attribute would be used in many views, I am trying to override
__init__.
def __init__(self, *vargs):
models.Model.__init__(self, *vargs)
http://diveintomark.org/archives/2004/07/06/nfc
I was walking across a bridge one day, and I saw a man standing on the
edge, about to jump off. So I ran over and said, "Stop! Don't do it!"
"I can't help it," he cried. "I've lost my will to live."
"What do you do for a living?" I asked.
He
I have a python model
class MyModel(models.Model):
fld1 = models.TextField()
fld1 = models.TextField()
I want to have a non database item in this model class, which I can
populate in the views. What is the recommended way to do this.
When I run the command
$ python manage.py syncdb
I am getting an error like
Failed to install index for auth.Message model: (2006, 'MySQL server
has gone away')Installing index for auth.Permission model
I am on python 2.3.4, mysql 5.0.46, cent OS.
My tables get created though.
What can be the
Yes the problem was with python-devel. After installing all the
depndebcies, it went through fine.
On Aug 19, 1:20 pm, Thejaswi Puthraya <[EMAIL PROTECTED]>
wrote:
> On Aug 19, 1:16 pm, shabda <[EMAIL PROTECTED]> wrote:
>
> > But even that is not helping. I am on a
: error: `PyExc_ImportError' undeclared (first use in
this function)
error: command 'gcc' failed with exit status 1
3.
cd /sw/lib/mysql
(that file is not on my system)
So unabl;e to build the MySQL-python-1.2.2 library.
On Aug 19, 12:52 pm, shabda <[EMAIL PROTECTED]> wrote:
> I am trying
I am trying to setup django with mysql, After installing django and
mysql I am trying to set up mysql-python.
So I give the command
$ easy_install MySQL-python
And am getting a ton of errors.
On the page http://www.djangobook.com/en/beta/chapter02/, under
comments for mysql it says,
"Don't forget
I have apache installed on linux with mod_php, mysql. I am trying to
get django working here, and am following the intsallation steps at
http://www.djangobook.com/en/beta/chapter21/ .
Step 1. Install mod_python
did yum install mod_python. Checked that mod_python is installed.
Step 2.
Add this to
thanks, That solves my problem.
On Jun 21, 11:05 pm, Tim Chase <[EMAIL PROTECTED]> wrote:
> > I want to use some stored procedures. I am mySql. Is there
> > some way I can define stored procedures from withing django?
> > (We can call already defined procedures,
>
Hi,
I want to use some stored procedures. I am mySql. Is there some way I
can define stored procedures from withing django?
(We can call already defined procedures,
http://www.djangosnippets.org/snippets/118/
discusses how, but can we also define stored procedures from within
django?)
Hi,
What host do you people recommend for hosting a small-medium traffic
django site. Its just a hobby hobby site so I dont want too costly a
host, but since this is the first django app I would be hosting, I
would prefer a host with reasonable support and one which specialises
in django.
Also using locals() and printing is not very useful as it dumps too
much data to screen to be any use.
On Jun 18, 10:04 pm, shabda <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I am prototyping an app. Since I am just prtotyping I do not want to
> write templates yet. SO is there some
ue of ``None``
So providing default values for models should be possible.
On Jun 18, 9:30 pm, shabda <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I have a model class like this
>
> class Link(models.Model):
> link = models.URLField()
> user = models.ForeignKey(User, unique=F
Hi,
I have a model class like this
class Link(models.Model):
link = models.URLField()
user = models.ForeignKey(User, unique=False)
text = models.TextField(maxlength = 20)
votes = models.IntegerField()
I want some of the fields to have defaults, like I want votes to have
a
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