[Matplotlib-users] please help with arrow drawing.

2011-10-17 Thread Piter_
Hi all
I want to draw an two headed arrow between two points.
But I get a line. What I am doing wrong? I actually try to plot an
image similar to this one:
http://upload.wikimedia.org/wikipedia/commons/a/a3/Parameters_of_the_Marcus_Equation.JPG
may be I can use an annotate function for this.
Thanks for help.
Petro.

import pylab
from scipy import optimize
import numpy
x1=numpy.arange(-4000,1000,0.1)
x2=numpy.arange(-1000,4000,0.1)
y1=100*numpy.square(x1+1500)
y2=100*numpy.square(x2-1500)-0.1e9
pylab.figure()
pylab.plot(x1,y1,x2,y2)
pylab.grid(True)
pylab.arrow(-3000,0,0,-1,width=1)
pylab.xlim(-5000,5000)
pylab.ylim(-2e8,7e8)
pylab.show()
###x

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[Matplotlib-users] 0.99.1.2: error in afm.py

2011-10-17 Thread Rich Shepard
   After a long hiatus I'm again working on an application and just upgraded
matplotlib from 0.98.5.2 to 0.99.1.2. However, there's an error on start up
that I need your help in resolving.

   There are many dozens of lines containing:

Found an unknown keyword in AFM header (was Underline)

The traceback (in its entirety) shows:

Traceback (most recent call last):
   File ./eikos.py, line 6, in module
 from modelPage import modModel
   File /home/rshepard/development/trunk/modelPage.py, line 8, in module
 from matplotlib.backends.backend_wxagg import FigureCanvasWxAgg as
FigureCanvas
   File
/usr/lib/python2.6/site-packages/matplotlib/backends/backend_wxagg.py,
line 20, in module
 from matplotlib.figure import Figure
   File /usr/lib/python2.6/site-packages/matplotlib/figure.py, line 18, in
module
 from axes import Axes, SubplotBase, subplot_class_factory
   File /usr/lib/python2.6/site-packages/matplotlib/axes.py, line 12, in
module
 import matplotlib.axis as maxis
   File /usr/lib/python2.6/site-packages/matplotlib/axis.py, line 10, in
module
 import matplotlib.font_manager as font_manager
   File /usr/lib/python2.6/site-packages/matplotlib/font_manager.py, line
1301, in module
 _rebuild()
   File /usr/lib/python2.6/site-packages/matplotlib/font_manager.py, line
1292, in _rebuild
 fontManager = FontManager()
   File /usr/lib/python2.6/site-packages/matplotlib/font_manager.py, line 
1010, in __init__
 self.afmlist = createFontList(self.afmfiles, fontext='afm')
   File /usr/lib/python2.6/site-packages/matplotlib/font_manager.py, line
578, in createFontList
 font = afm.AFM(fh)
   File /usr/lib/python2.6/site-packages/matplotlib/afm.py, line 295, in
__init__
 parse_afm(fh)
   File /usr/lib/python2.6/site-packages/matplotlib/afm.py, line 283, in
parse_afm
 dcmetrics_ascii, dcmetrics_name = _parse_char_metrics(fh)
   File /usr/lib/python2.6/site-packages/matplotlib/afm.py, line 167, in
_parse_char_metrics
 name = vals[2].split()[1]
IndexError: list index out of range

   Please tell me what I need to do to resolve this error.

Rich

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Re: [Matplotlib-users] 0.99.1.2: error in afm.py

2011-10-17 Thread Benjamin Root
On Mon, Oct 17, 2011 at 12:57 PM, Rich Shepard rshep...@appl-ecosys.comwrote:

   After a long hiatus I'm again working on an application and just upgraded
 matplotlib from 0.98.5.2 to 0.99.1.2. However, there's an error on start up
 that I need your help in resolving.

   There are many dozens of lines containing:

 Found an unknown keyword in AFM header (was Underline)

 The traceback (in its entirety) shows:

 Traceback (most recent call last):
   File ./eikos.py, line 6, in module
 from modelPage import modModel
   File /home/rshepard/development/trunk/modelPage.py, line 8, in module
 from matplotlib.backends.backend_wxagg import FigureCanvasWxAgg as
 FigureCanvas
   File
 /usr/lib/python2.6/site-packages/matplotlib/backends/backend_wxagg.py,
 line 20, in module
 from matplotlib.figure import Figure
   File /usr/lib/python2.6/site-packages/matplotlib/figure.py, line 18, in
 module
 from axes import Axes, SubplotBase, subplot_class_factory
   File /usr/lib/python2.6/site-packages/matplotlib/axes.py, line 12, in
 module
 import matplotlib.axis as maxis
   File /usr/lib/python2.6/site-packages/matplotlib/axis.py, line 10, in
 module
 import matplotlib.font_manager as font_manager
   File /usr/lib/python2.6/site-packages/matplotlib/font_manager.py, line
 1301, in module
 _rebuild()
   File /usr/lib/python2.6/site-packages/matplotlib/font_manager.py, line
 1292, in _rebuild
 fontManager = FontManager()
   File /usr/lib/python2.6/site-packages/matplotlib/font_manager.py, line
 1010, in __init__
 self.afmlist = createFontList(self.afmfiles, fontext='afm')
   File /usr/lib/python2.6/site-packages/matplotlib/font_manager.py, line
 578, in createFontList
 font = afm.AFM(fh)
   File /usr/lib/python2.6/site-packages/matplotlib/afm.py, line 295, in
 __init__
 parse_afm(fh)
   File /usr/lib/python2.6/site-packages/matplotlib/afm.py, line 283, in
 parse_afm
 dcmetrics_ascii, dcmetrics_name = _parse_char_metrics(fh)
   File /usr/lib/python2.6/site-packages/matplotlib/afm.py, line 167, in
 _parse_char_metrics
 name = vals[2].split()[1]
 IndexError: list index out of range

   Please tell me what I need to do to resolve this error.

 Rich


Rich,

In the afm.py file, a before line 167, can you print the value of the line
variable and tell us what it is?

Ben Root
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Re: [Matplotlib-users] 0.99.1.2: error in afm.py

2011-10-17 Thread Rich Shepard
On Mon, 17 Oct 2011, Benjamin Root wrote:

 In the afm.py file, a before line 167, can you print the value of the
 line variable and tell us what it is?

Ben,

   Here are lines 158-167:

 while 1:
 line = fh.readline()
 if not line: break
 line = line.rstrip()
 if line.startswith('EndCharMetrics'): return ascii_d, name_d
 vals = line.split(';')[:4]
 if len(vals) !=4 : raise RuntimeError('Bad char metrics line: %s'
 num = _to_int(vals[0].split()[1])
 wx = _to_float(vals[1].split()[1])
 name = vals[2].split()[1]

Thanks,

Rich

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Re: [Matplotlib-users] 0.99.1.2: error in afm.py

2011-10-17 Thread Benjamin Root
On Monday, October 17, 2011, Rich Shepard rshep...@appl-ecosys.com wrote:
 On Mon, 17 Oct 2011, Benjamin Root wrote:

 In the afm.py file, a before line 167, can you print the value of the
 line variable and tell us what it is?

 Ben,

   Here are lines 158-167:

 while 1:
 line = fh.readline()
 if not line: break
 line = line.rstrip()
 if line.startswith('EndCharMetrics'): return ascii_d, name_d
 vals = line.split(';')[:4]
 if len(vals) !=4 : raise RuntimeError('Bad char metrics line: %s'
 num = _to_int(vals[0].split()[1])
 wx = _to_float(vals[1].split()[1])
 name = vals[2].split()[1]

 Thanks,

 Rich


Rich,

On line 166, I want you to put print 'Line:', line. Then, rerun your
program and report back what the output of that print statement.

Ben Root
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[Matplotlib-users] matplotlib.rcParams(update) and parallel python

2011-10-17 Thread tinux

I have around 100 python files, that each create one figure using matplotlib.
Since I want to use all CPU cores, I basically did for filename in files:
execfile(filename) using a python script. However, this does not produce
the same output as running each file separately (for instance axes, figure
size are sometime wrong).

I _think_ I narrowed it down to this: In all files I need to do
matplotlib.rcParams(update). I guess that this influences the matplotlib
rc parameters and thus somehow values from some figures are used for others. 

So, my question is, how can I do something like
matplotlib.rcParams(update) so that it does not influence other scripts
that are run in parallel using 'execfile'? Or, how do I set rc parameters
for one specific script?

BTW, I tried 'pp' and 'multiprocessing', same problem with both.

Any help is greatly appreciated!

Cheers, Martin
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Re: [Matplotlib-users] 0.99.1.2: error in afm.py

2011-10-17 Thread Rich Shepard
On Mon, 17 Oct 2011, Benjamin Root wrote:

 On line 166, I want you to put print 'Line:', line. Then, rerun your
 program and report back what the output of that print statement.

Ben,

   Sorry I mis-understood your request.

   I redirected the output to a file 'error.log' and it contains 104,777
lines from the 'print line' command. I can gzip it and send it to you off
the list but it's 5.5M in size.

   When I grep for Underline in error.log it's not found. That seems to be
the unknown keyword.

   How would you like me to proceed?

Thanks,

Rich

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Re: [Matplotlib-users] 0.99.1.2: error in afm.py

2011-10-17 Thread Benjamin Root
On Monday, October 17, 2011, Rich Shepard rshep...@appl-ecosys.com wrote:
 On Mon, 17 Oct 2011, Benjamin Root wrote:

 On line 166, I want you to put print 'Line:', line. Then, rerun your
 program and report back what the output of that print statement.

 Ben,

   Sorry I mis-understood your request.

   I redirected the output to a file 'error.log' and it contains 104,777
 lines from the 'print line' command. I can gzip it and send it to you off
 the list but it's 5.5M in size.

   When I grep for Underline in error.log it's not found. That seems to be
 the unknown keyword.

   How would you like me to proceed?

 Thanks,

 Rich


I only need the last line printed by that print statement.  I want to see
how the parsing failed.

Ben
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Re: [Matplotlib-users] 0.99.1.2: error in afm.py

2011-10-17 Thread Rich Shepard
On Mon, 17 Oct 2011, Benjamin Root wrote:

 I only need the last line printed by that print statement.  I want to see
 how the parsing failed.

Ben,

   Here are the last 3:

Line: C 125 ; WX 273 ; N braceright ; B 55 -68 244 707 ;
Line: C 126 ; WX 586 ; N asciitilde ; B 39 219 531 408 ;
Line: C 127 ; WX 262 ; N  ; B 64 506 246 730 ;

   I see there's no character in the last line. Isn't that interesting!

Rich

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[Matplotlib-users] Figure legend for 1.1.0 doesn't properly handle errorbars?

2011-10-17 Thread Sterling Smith
Let me first say that I appreciate the work that the developers have put into 
matplotlib.  You're doing a great job. 

I have filed a bug report at 

https://github.com/matplotlib/matplotlib/issues/533

wherein I post the following

Consider:

from pylab import *
x = arange(0,1,.01)
y = x**2
fig = figure(2)
ax = fig.add_subplot(111)
errorbar(x,y,yerr=x/10.,label='$x^2$')
errorbar(x,y**3,yerr=x/10.,label='$x^6$')
legend(loc='upper center')
h,l = ax.get_legend_handles_labels()
fig.legend(h,l,loc='lower right')


I am getting the right legend for the axes based legend, but the figure based 
legend seems to be using the different parts of the errorbar for subsequent 
handles, instead of using them as a group.  From what I can tell, this has 
appeared since the upgrade to version 1.1.0.

I am running on Linux, python 2.7, gtkAgg backend.

Thanks,
Sterling


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[Matplotlib-users] Matplotlib 1.1.0 Error in triangulation.py

2011-10-17 Thread Floyd John
Hello,

I have read your instruction for bug reporting but this is fairly simple.

There is a call to self.get_cpp_triangulation() which exists but there is also 
a call to self._get_cpp_triangulation at line 174 to obtain the neighbours. 

Easy to fix. 

Regards
John
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Re: [Matplotlib-users] Figure legend for 1.1.0 doesn't properly handle errorbars?

2011-10-17 Thread Jae-Joon Lee
Somehow, Figure.legend flattens the given handle list and this is the
cause of the problem.

https://github.com/matplotlib/matplotlib/blob/master/lib/matplotlib/figure.py#L994

Does anyone know why this is necessary?
I just filed a pull request to remove this.

https://github.com/matplotlib/matplotlib/pull/534/files

Meanwhile, you may do

from matplotlib.legend import Legend
l = Legend(fig, h, l, loc='lower right')
fig.legends.append(l)

This should be equivalent to fig.legend(h,l,loc='lower right').

Or, if you don't need axes legend, you may do

legend(h,l,loc='lower right', bbox_to_anchor=[0,0,1,1],
   bbox_transform=fig.transFigure)

Regards,

-JJ

On Tue, Oct 18, 2011 at 6:59 AM, Sterling Smith smit...@fusion.gat.com wrote:
 Let me first say that I appreciate the work that the developers have put into 
 matplotlib.  You're doing a great job.

 I have filed a bug report at

 https://github.com/matplotlib/matplotlib/issues/533

 wherein I post the following

 Consider:

 from pylab import *
 x = arange(0,1,.01)
 y = x**2
 fig = figure(2)
 ax = fig.add_subplot(111)
 errorbar(x,y,yerr=x/10.,label='$x^2$')
 errorbar(x,y**3,yerr=x/10.,label='$x^6$')
 legend(loc='upper center')
 h,l = ax.get_legend_handles_labels()
 fig.legend(h,l,loc='lower right')


 I am getting the right legend for the axes based legend, but the figure based 
 legend seems to be using the different parts of the errorbar for subsequent 
 handles, instead of using them as a group.  From what I can tell, this has 
 appeared since the upgrade to version 1.1.0.

 I am running on Linux, python 2.7, gtkAgg backend.

 Thanks,
 Sterling


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Re: [Matplotlib-users] Matplotlib 1.1.0 Error in triangulation.py

2011-10-17 Thread John Hunter
On Mon, Oct 17, 2011 at 6:58 PM, Floyd John
john.fl...@environment.nsw.gov.au wrote:
 Hello,

 I have read your instruction for bug reporting but this is fairly simple.

 There is a call to self.get_cpp_triangulation() which exists but there is 
 also a call to self._get_cpp_triangulation at line 174 to obtain the 
 neighbours.

 Easy to fix.

Thanks for the report.  Even easy issues are best reported on the
issue tracker so they will be less likely to fall between the cracks,
we can tag them and assign developers to them, etc.

I've opened https://github.com/matplotlib/matplotlib/issues/535

JDH

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Re: [Matplotlib-users] matplotlib.rcParams(update) and parallel python

2011-10-17 Thread John Hunter
On Mon, Oct 17, 2011 at 2:57 PM, tinux hoffmann.mar...@gmail.com wrote:

 I have around 100 python files, that each create one figure using matplotlib.
 Since I want to use all CPU cores, I basically did for filename in files:
 execfile(filename) using a python script. However, this does not produce
 the same output as running each file separately (for instance axes, figure
 size are sometime wrong).
 I _think_ I narrowed it down to this: In all files I need to do
 matplotlib.rcParams(update). I guess that this influences the matplotlib
 rc parameters and thus somehow values from some figures are used for others.

 So, my question is, how can I do something like
 matplotlib.rcParams(update) so that it does not influence other scripts
 that are run in parallel using 'execfile'? Or, how do I set rc parameters
 for one specific script?

 BTW, I tried 'pp' and 'multiprocessing', same problem with both.

The problem is that the rc params are module level in matplotlib so in
a persistent process like ipython if one script modifies the rc
params, subsequent files executed in the same process will be
affected.  You can restore the rc params to their default state by
doing before each call to execfile

import matplotlib
matplotlib.rc_file_defaults()


We face the same issue in the plot_directive which we use when
building the matplotlib documentation.  We define a function
clear_state in

  
https://github.com/matplotlib/matplotlib/blob/master/lib/matplotlib/sphinxext/plot_directive.py#L484

which closes all open figures, restore the rc defaults, and the
updates the defaults to an rc dictionary of the parameters we want for
each run.

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[Matplotlib-users] ellipsoids

2011-10-17 Thread pratik
Is there a function that can draw an ellipsoid like matlab's ellipsoid
function?
relevant:
http://stackoverflow.com/questions/2153768/draw-ellipse-and-ellipsoid-in-matlab

Thanks,

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Re: [Matplotlib-users] ellipsoids

2011-10-17 Thread Benjamin Root
On Mon, Oct 17, 2011 at 10:42 PM, pratik pratik.mallya...@gmail.com wrote:

 Is there a function that can draw an ellipsoid like matlab's ellipsoid
 function?
 relevant:

 http://stackoverflow.com/questions/2153768/draw-ellipse-and-ellipsoid-in-matlab

 Thanks,


from matplotlib.patches import Ellipse
import matplotlib.pyplot as plt

x = 0.5
y = 0.5
a = 4
b = 1
theta = 45.0
ell = Ellipse((x, y), a, b, theta)

ax = plt.gca()
ax.add_artist(ell)
plt.show()

There are some additional kwargs to the Ellipse constructor that allows you
to control color and such.

I hope that helps!
Ben Root
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