Johannes Hüsing wrote:
Am 19.05.2009 um 05:39 schrieb phen_ys:
surgery - data.frame(outcome = c(0, 0, 0, 0, 0, 0, 0, 0, 0,
+ 0, 0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 1, 1, 1, 1, 0, 1, 0,
+ 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0), age = c(50, 50, 51,
+ 51, 53, 54, 54, 54, 55, 55, 56, 56, 56,
Your problem is statistical and has nothing particularly to do with R.
It looks like homework to me.
You may care to look at it this way:
###
fm - glm(outcome ~ age, binomial, surgery)
summary(fm)
Call:
glm(formula = outcome ~ age, family = binomial, data = surgery)
On Mon, 2009-05-18 at 11:48 -0700, William Paterson wrote:
Hi,
I am using GAMMs to show a relationship of temperature differential over
time with a model that looks like this:-
gamm(Diff~s(DaysPT)+AirToC,method=REML)
where DaysPT is time in days since injury and Diff is repeat measures
Dear Christine,
The poisson family does not allow for overdispersion (nor
underdispersion). Try using the quasipoisson family instead.
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek /
is there a command like mat.or.vec for an array that I have to create with a
cicle for?
[[alternative HTML version deleted]]
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PLEASE do read the posting guide
Stavros Macrakis wrote:
On Mon, May 18, 2009 at 6:00 PM, Gabor Grothendieck ggrothendi...@gmail.com
wrote:
I understood what you were asking but R is an oo language so
that's the model to use to do this sort of thing.
I am not talking about creating a new class with an
On Tue, 19 May 2009 14:04:19 +1000 Kon Knafelman konk2...@hotmail.com
wrote:
KK i have the sample variances for 1000 samples, and i want to fit it
KK to a chi-squared distribution.
KK can someone please help me fit this to a chi-squared distribution
KK with n degrees of freedom. Thanks a lot
Wacek Kusnierczyk wrote:
Stavros Macrakis wrote:
[...]
I am not talking about creating a new class with an analogue to the
subtraction function. I am talking about a function which applies another
function to a sequence and its lagged version.
Functional arguments are used all over
Thanks. I did try using quasipoisson and a negative binomial error but am
unsure of the degree of overdispersion and whether it is simply due to
missing values. I am investigating to see if I can replace these missing
values so that I can have a balanced orthogonal design and use lme or aov
Dear list,
Has anyone used the 'copula' or 'fCopulae' package with empirical
distributions. I have two distributions (10.000 samples each) which I need
to combine using archimedean copulas (probably Clayton and/or Frank).
Is this possible? Is there an existing empirical distribution function
Wacek Kusnierczyk wrote:
btw., the error message here is confusing:
lag = 1:2
diff(1:10, lag=lag)
# Error in diff.default(1:10, lag = lag) :
# 'lag' and 'differences' must be integers = 1
is.integer(lag)
# TRUE
all(lag = 1)
# TRUE
what is meant is
cvandy wrote:
When I use wilcox.test, I get vastly different p-values than the problems
from Statistics textbooks.
For example:
The following problem comes from Applied Statistics and Probability for
Engineers, 2nd Edition, by D. C. Montgomery. Page736, problem 14.7. The
problem is to compare
I just tried it in Minitab and got
--
Test of median = 8.500 versus median not = 8.500
N for Wilcoxon Estimated
N Test Statistic P Median
C1 20 19 80.5 0.573 8.460
-
One tailed gave me closer to the textbook, but still
Dear Christine,
(Month|Block) and (1|Block) + (1|Month) are completely different random
effects. The first assumes that each Block exhibits a different linear trend
along Month. The latter assumes that each block has a random effect, each month
has a random effect and that the random effects
Dear all,
I am trying to install a package called GFCURE from a local zip file. This
package fits a cure survival model and has been downloaded from:
http://post.queensu.ca/~pengp/software.html
The problem is that when I try to install this package from a local zip file
using R,
Dear all,
I'm plotting some points on a graph where both axes need to have the
same scale. See the example below. Coord_equal does that trick but in
this case it wastes a lot of space on the y-axis. Setting the limits of
the y-axis myself was no avail.
Any suggestions to solve this problem?
Hi,
how can I remove all empty objects (which are NA or have zero rows)
from my workspace?
Thanks,
Katharina
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PLEASE do read the posting guide
Hi,
how can I use rm() on objects named like:
paste(site,i,_data,sep=) while looping
through i?
I tried rm(paste(site,i,_data,sep=)) but I get the error that
rm() must contain names or
text strings which is confusing me as I thought paste() would create
something like that...?
Thanks,
If you use coord_equal on data where the range on the x-axis is larger
than the range on the y-axis, then of course you'll observe extra
space on the y-axis. What did you expect?
Also, this post may be better suited to the ggplot2 mailing list:
http://had.co.nz/ggplot2/
On Tue, May 19, 2009 at
Katharina May wrote:
Hi,
how can I remove all empty objects (which are NA or have zero rows)
from my workspace?
Hi Katharina,
To remove objects that are all NA:
for(object in objects()) if(all(is.na(get(object rm(list=object)
If by zero rows you mean objects that do not have a
Thanks Jim, the removal of objects which are NA works perfectly!
For my second problem it didn't express myself correctly:
I actually meant objects with rows (attributes?) but no data in it
but I solved this
adjusting your approach:
for(object in objects()) if(is.null(dim(get(object))[1]) ||
Dear R Users,
A would like to fit a loglinear analysis to a three dimensional contingency
table. But I Don't want to run a full saturated modell. Is there any package
in R that could handle somekind of stepwise search to choose out the best
soultion? And how can I fit a non fully saturated
Look to the glm function then pass the output to the step function
Steve Friedman Ph. D.
Spatial Statistical Analyst
Everglades and Dry Tortugas National Park
950 N Krome Ave (3rd Floor)
Homestead, Florida 33034
steve_fried...@nps.gov
Office (305) 224 - 4282
Fax (305) 224 - 4147
On Tue, 19 May 2009, marc bernard wrote:
Dear all,
I am trying to install a package called GFCURE from a local zip
file. This package fits a cure survival model and has been
downloaded from:
http://post.queensu.ca/~pengp/software.html
However, it is not an R package. Read the
Note that this could be done like this for ordinary
vectors:
x - seq(1:4)^2
apply(embed(x, 2), 1, function(x, f) f(rev(x)), f = diff)
[1] 3 5 7
apply(embed(x, 2), 1, function(x, f) f(rev(x)), f = sum)
[1] 5 13 25
or a method to rollapply in zoo could be added for ordinary vectors.
Here it
Try this also:
rm(list=names(which(unlist(eapply(globalenv(), function(a)all(is.na(a) ||
is.null(a)))
On Tue, May 19, 2009 at 9:07 AM, Katharina May may.kathar...@googlemail.com
wrote:
Thanks Jim, the removal of objects which are NA works perfectly!
For my second problem it didn't
On Tue, May 19, 2009 at 6:17 AM, marc bernard
marc_bern...@hotmail.co.uk wrote:
Dear all,
I am trying to install a package called GFCURE from a local zip file. This
package fits a cure survival model and has been downloaded from:
You are assuming its in the form of an R *package* but
Dear colleagues,
I am trying a glm.nb for the distribution of a plant species with 93
environmental variables. I execute the instruction and I get the following
message: Error: C stack usage is too close to the limit.
How can I increase the memory of R?
Your sincerely,
Nora.
Have you try principal component analysis to reduce space variables?
2009/5/19 Nora Pérez norichu...@hotmail.com
Dear colleagues,
I am trying a glm.nb for the distribution of a plant species with 93
environmental variables. I execute the instruction and I get the following
message:
Katharina May wrote:
Hi,
how can I use rm() on objects named like:
paste(site,i,_data,sep=) while looping
through i?
I tried rm(paste(site,i,_data,sep=)) but I get the error that
rm() must contain names or
text strings which is confusing me as I thought paste() would create
something like
RT == Rolf Turner r.tur...@auckland.ac.nz
on Tue, 19 May 2009 11:02:08 +1200 writes:
RT On 19/05/2009, at 10:20 AM, Steve Lianoglou wrote:
Hi all,
I've (tried) to look through the bug tracker, and gmane-search the
R list to
see if this has been mentioned
Dear gabor,
Many thanks for your answer. I indeed didn't check the read me text.
Bests
From: ggrothendi...@gmail.com
Date: Tue, 19 May 2009 08:44:13 -0400
Subject: Re: [R] problem with installing a local zip file : GFCURE
To: marc_bern...@hotmail.co.uk
CC: r-help@r-project.org
ONKELINX, Thierry Thierry.ONKELINX at inbo.be writes:
I'm plotting some points on a graph where both axes need to have the
same scale. See the example below. Coord_equal does that trick but in
this case it wastes a lot of space on the y-axis. Setting the limits of
the y-axis myself was no
Thanks Peter,
There are 8 measurements less than 8.5, so calculating the probability
(binomial) of 8, or fewer, happening by chance with n = 20 and p = 0.50
gives P = 0.25-- the book answer. I've tried several problems in other
textbooks and in each case I get vastly different P-values than I
Easy enough. What if some of the matrix elements contained missing values?
Then how could you still calculate the means? Example code below:
mat1 - matrix(c(1,2,3,4,5,NA,7,8,9),3,3)
mat2 - matrix(c(NA,6,1,9,0,5,8,2,7),3,3)
mat3 - matrix(c(5,9,1,8,NA,3,7,2,4),3,3)
Gabor Grothendieck wrote:
Charles Van deZande wrote:
Thanks Peter,
There are 8 measurements less than 8.5, so calculating the probability
(binomial) of 8, or fewer, happening by chance with n = 20 and p = 0.50
gives P = 0.25-- the book answer. I've tried several problems in other
textbooks and in each case I get
Try this:
rm(list=ls(patt=site[0-9]$))
On Tue, May 19, 2009 at 7:47 AM, Katharina May may.kathar...@googlemail.com
wrote:
Hi,
how can I use rm() on objects named like:
paste(site,i,_data,sep=) while looping
through i?
I tried rm(paste(site,i,_data,sep=)) but I get the error that
rm()
That is very unusual, but the C stack can be increased under Windows
by recompiling R (see src/gnuwin32/front-ends/Makefile). On most other
OSes it is much easier, just adjust the setting via ulimit or limit in
your shell.
But I suspect the problem is that your model is too complex.
thanks to all your solutions, works out perfectly!
2009/5/19 Henrique Dallazuanna www...@gmail.com:
Try this:
rm(list=ls(patt=site[0-9]$))
On Tue, May 19, 2009 at 7:47 AM, Katharina May
may.kathar...@googlemail.com wrote:
Hi,
how can I use rm() on objects named like:
I don't get the error you mention:
site1_data-1
site2_data-2
site3_data-3
for (i in 1:3) paste(site,i,_data,sep=)
In my example, another way is: rm(list=paste(site,1:3,_data,sep=))
Or you can use rm(list=ls(pattern=you pattern)), in my example, it is:
rm(list=ls(pattern=site[1-3]_data))
Hi R-users!
I am trying to learn how to use the glmpath package. I have a dataframe like
this
dim(data)
[1] 605 109
and selected the following
response - data[,1]
features-as.matrix(data[,3:109])
mymodel - glmpath(features,response, family = binomial)
Error in if (lambda = min.lambda) {
Dear all:
I'm trying to fit the optimal Box-Cox
transformation related to nls (see the code
below) for the demand of money data in Green (3th
Edition) but in the last step R gives the next
error message.
Error en
`[.data.frame`(eval(object$data), ,
I read that Spearman rho can be used to detect the presence of trend in a time
series.
However, I cannot figure out how to use such a test to thsi purpose. First of
all which one
of the available functions and how to pass my mono-channel time series which
contains both
positive and negative
Dear R users,
I try to use a very large file (~3 Gib) with the filehash package. The
length of the dataset is around 4,000,000 obs. I get this message from R
while trying to load the dataset (named cc084.csv):
dumpDF(read.csv(cc084.csv, header=T), dbName=db01)
Erreur : impossible d'allouer un
Hi.
I am very new to R and have been diligently working my way through the manual
and various tutorials. I am now trying to work with some of my own data and
have encountered a problem that I need to fix. I have a dataframe with 8
columns and approximately 850 rows. I have provided an
Eric McKibben wrote:
Within column 6 (Question) the numbers 1:33 repeat down the entire column.
Occasionally, however, another value (-32767) appears. I need to locate
this value everytime it appears and in its place insert 33 rows that are
numbered 1:33 in column Question.
Eric McKibben wrote:
Hi.
I am very new to R and have been diligently working my way through the manual
and various tutorials. I am now trying to work with some of my own data and
have encountered a problem that I need to fix. I have a dataframe with 8
columns and approximately 850 rows. I
Dear R-users,
in a minimal example exists() gives FALSE on an object which obviously does
exist. How can I check on that list object anyway else, please?
SmoothData - list(exists=TRUE, span=0.001)
SmoothData
$exists
[1] TRUE
$span
[1] 0.001
exists(SmoothData)
TRUE
exists(SmoothData$span)
Hi,
how do I create a string of the comma-separated content of a vector?
I've got the vector i with several numeric values as content:
str(i)
num 99
and want to create a SQL statement to look like the following where
the part '(2, 4, 6, 7)' should be
the content of the vector i:
select * from
SmoothData$span is not an object which can be checked by exists(), but
part of an object which can be checked by is.null().
On Wed, May 20, 2009 at 12:07 AM, Žroutík zrou...@gmail.com wrote:
Dear R-users,
in a minimal example exists() gives FALSE on an object which obviously does
exist. How
On 5/19/2009 12:07 PM, Žroutík wrote:
Dear R-users,
in a minimal example exists() gives FALSE on an object which obviously does
exist. How can I check on that list object anyway else, please?
SmoothData - list(exists=TRUE, span=0.001)
SmoothData
$exists
[1] TRUE
$span
[1] 0.001
Žroutík wrote:
Dear R-users,
in a minimal example exists() gives FALSE on an object which obviously does
exist. How can I check on that list object anyway else, please?
SmoothData - list(exists=TRUE, span=0.001)
SmoothData
$exists
[1] TRUE
$span
[1] 0.001
exists(SmoothData)
Žroutík wrote:
SmoothData - list(exists=TRUE, span=0.001)
SmoothData
$exists
[1] TRUE
$span
[1] 0.001
exists(SmoothData)
TRUE
exists(SmoothData$span)
FALSE
'SmoothData$span' = 'foo'
exists(SmoothData$span)
# TRUE
exists(SmoothData[[2]])
Dear Dieter,
I tried that. But it rescales one of the axis. The resulting graph is
still square. But now 1 cm Y-axis equal 2.5 cm on the X-axis. This seems
not te be the documented behaviour.
ggplot(ds, aes(x = x, y = y)) + geom_point() + coord_equal(ratio = 2/5)
From sessionInfo()
R 2.9.0
Linlin Yan wrote:
SmoothData$span is not an object which can be checked by exists(), but
part of an object which can be checked by is.null().
is.null is unhelpful here, in that lists can contain NULL as a named
element, and retrieving a non-existent element returns NULL:
foo =
Thanks Peter,
You are correct! After I sent the previous message, I realized that I was
comparing the sign test against the Wilcoxon test. I would have replied
sooner, but I realized that while I was out walking my dogs.
CHV
 
Charles H Van deZande
---Original Message---
From:
Hi,
Thank you very much for the answer.
However, I have still some misunderstandings.
from the output, can we say that plant and leaf age are significant but not
their interaction?
And the last question I promise, what would you advise me to write in the
paper to explain the different method
# Here are two options:
p - ggplot(mtcars, aes(wt, mpg)) + geom_point() + geom_text(aes(x = 5, y =
30, label = A Label))
#or
response - c(2,4)
xvar - c(1,2)
label - response;
myData - data.frame(response,xvar,label)
p - ggplot(myData, aes(y=response, x=xvar))
p + geom_bar(position=dodge,
see ?paste
e.g.
x - seq(0,10,1)
paste(x, collapse=, )
2009/5/19 Katharina May may.kathar...@googlemail.com:
Hi,
how do I create a string of the comma-separated content of a vector?
I've got the vector i with several numeric values as content:
str(i)
num 99
and want to create a SQL
pompon wrote:
Hi,
Thank you very much for the answer.
However, I have still some misunderstandings.
from the output, can we say that plant and leaf age are significant but not
their interaction?
And the last question I promise, what would you advise me to write in the
paper to explain the
Colleagues
R2.8.1 in OSX
I often combine two commands as follows:
length(grep(TEXT, OBJECT)) 0
to see if a particular snippet of text exists within an object.
Is there a single command that would accomplish this?
Dennis
Dennis Fisher MD
P (The P Less Than Company)
Phone:
Hi,
R=2.9.0 ships grepl, which lets you do that:
any( grepl( TEXT, OBJECT) )
You can also:
install.packages( operators )
require( operators )
OBJECT %~+% TEXT
Romain
Dennis Fisher wrote:
Colleagues
R2.8.1 in OSX
I often combine two commands as follows:
length(grep(TEXT, OBJECT)) 0
Greetings. I'm trying to learn to program in R. (I'm definitely NOT new to
programming, just to R.) A colleague suggested that I have a look at the
book:
An Introduction to S and S-Plus
by:
Phil Spector
I've glanced at the book, and it does indeed seem to be the kind of thing I
Maybe you should just bypass that book for one of these?
http://www.springer.com/series/6991
-Ro
On Tue, May 19, 2009 at 12:01 PM, Michael Hannon jm_han...@yahoo.com wrote:
Greetings. I'm trying to learn to program in R. (I'm definitely NOT new to
programming, just to R.) A colleague
On Tue, May 19, 2009 at 12:07 PM, routík zrou...@gmail.com wrote:
SmoothData - list(exists=TRUE, span=0.001)
exists(SmoothData$span)
FALSE
As others have said, this just checks for the existence of a variable with
the (strange) name SmoothData$span.
In some sense, in R semantics, xxx$yyy
Stavros Macrakis wrote:
You might think that you can check names(xxx) to see if the slot has been
explicitly set, but it depends on *how* you have explicitly set the slot to
NULL:
xxx$hello - 3
xxx$hello - NULL
names(xxx)
character(0) # no names --
Dear R users,
I have 1 data.frame of 1500x80 - data1. I found out that there are a
few cells of data that I have misplace, and I need to fix the ordering
of them.
In an attempt trying to swap column 22 23 of the Subject with
misplaced data, I did the following:
data2 - data1
while (theta1!=theta) {...}
gives the error message:
Error in while (theta1 != theta) { :
missing value where TRUE/FALSE needed
but when i extract theta1!=theta and paste it into the console it comes up
with the output TRUE which contradicts the error message- im not sure what I
am doing
dlogl - -(n/theta)-sum((y/(theta)^2)*((1-exp(y/theta))/(1+exp(y/theta)))
d2logl - (n/theta^2) - sum((-2y/theta^3)*(1-exp(y/theta))/(1+exp(y/theta)))
- sum(((2*y/theta^4)*exp(y/theta))/((1+exp(y/theta))^2))
returns the error message:
Error: unexpected symbol in:
dlogl -
On Mon, May 18, 2009 at 9:22 AM, Thomas Lumley tlum...@u.washington.edu wrote:
On Mon, 18 May 2009, Debbie Zhang wrote:
Based on a set of binomial sample data, how would you utilize the nlm
function in R to estimate the true proportion of the population?
I can't see why anyone would want to
You're missing a ) off end of the first line. You should consider
using an editor (e.g. ESS/Emacs) that does parentheses matching. I
found this in less than 5 sec (less time than I'm taking to write you
a note) by cut and pasting in Emacs.
--sundar
On Tue, May 19, 2009 at 12:52 PM, deanj2k
On 19-May-09 19:52:20, deanj2k wrote:
dlogl -
-(n/theta)-sum((y/(theta)^2)*((1-exp(y/theta))/(1+exp(y/theta)))
d2logl - (n/theta^2) -
sum((-2y/theta^3)*(1-exp(y/theta))/(1+exp(y/theta)))
- sum(((2*y/theta^4)*exp(y/theta))/((1+exp(y/theta))^2))
returns the error message:
Error:
On Tue, May 19, 2009 at 2:01 PM, Michael Hannon jm_han...@yahoo.com wrote:
Greetings. I'm trying to learn to program in R. (I'm definitely NOT new to
programming, just to R.) A colleague suggested that I have a look at the
book:
An Introduction to S and S-Plus
by:
Phil Spector
There are 17 different help pages in 5 different packages citing
Agresti and Coull. This is quickly displayed using the RSiteSearch
package as follows:
library(RSiteSearch)
HTML(RSiteSearch.function(Agresti and Coull))
I have not checked all these 17, but they doubtless help
My favorite tool for finding things like this is
RSiteSearch.function in the RSiteSearch package. For the objects
you mention, I get the following:
library(RSiteSearch)
hits(a.s - RSiteSearch.function(auto.stats)) # 0
hits(sx - RSiteSearch.function(saving.x)) # 0
hits(rn -
Hi
I'm fairly new to R and am trying to analyse some large spectral datasets
using stepwise regression (fairly standard in this area). I have a field
sampled dataset, of which a proportion has been held back for validation. I
gather than step() needs to be fed a regression model and lm() can
Hello,
I am working on a data set (already as a plm.data object) located
here: http://econsteve.com/arch/plmWithDensity.Robj
With the following R session:
library(plm)
...
load(plmWithDensity.Robj)
model - plm(RATE ~ density08, data=plmWithDensity)
Error: subscript out of bounds
I am not
On Tue, 19 May 2009, Stephen J. Barr wrote:
Hello,
I am working on a data set (already as a plm.data object) located
here: http://econsteve.com/arch/plmWithDensity.Robj
With the following R session:
library(plm)
...
load(plmWithDensity.Robj)
model - plm(RATE ~ density08,
See ?toString
x - 0:10
toString(x)
See ?sQuote for cases where the vector is a character and needs to be quoted.
Jason Law
Statistician
City of Portland
Bureau of Environmental Services
Water Pollution Control Laboratory
6543 N Burlington Avenue
Portland, OR 97203-5452
Ah, thank you for the help, and for the explanation of what is going
on. I suppose I will have to reload my data with plm.data set such
that RATE is not a factor. For my time index, will
2000,2000.25,2000.5, etc. work? Meaning 2000 quarter 1, 2000 quarter
2, etc? Or is there some special way that
On Mon, May 18, 2009 at 11:47 AM, Dimitri Liakhovitski ld7...@gmail.com wrote:
Hello!
I have a question about my lattice barchart that I am trying to build
in Section 3 below. I can't figure out a couple of things:
1. When I look at the dataframe test that I am trying to plot, it
looks right
On Tue, 19 May 2009, Stephen J. Barr wrote:
Ah, thank you for the help, and for the explanation of what is going
on. I suppose I will have to reload my data with plm.data set such
that RATE is not a factor.
plmWithDensity$RATE - as.numeric(as.character(plmWithDensity$RATE))
should suffice.
Try this (note dot after ~):
lm(response[, 3] ~., as.data.frame(spectra.spec[, 2:20]))
On Tue, May 19, 2009 at 6:21 PM, MikSmith m...@hsm.org.uk wrote:
Hi
I'm fairly new to R and am trying to analyse some large spectral datasets
using stepwise regression (fairly standard in this area). I
Dear useRs,
A new version of actuar is available since last Friday. This is mainly
a bugfix release. From the NEWS file:
Version 1.0-2
=
USER-VISIBLE CHANGES
o mfoo() and levfoo() now return Inf instead of NaN for infinite
moments. (Thanks to David Humke for the idea.)
BUG
Thank you for the advice. For the density08 variable, that is
population density in year 2008. I also have population densities for
year 2000, so I could put them both in, and interpolate between them
for the times that are covered by the panel (2000-2008), and then just
have a density column that
There's 10 files in c:\\
I wanna copy 3 of them to d:\\
How to do it via R?
Thanks!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
?file.copy
On Tue, May 19, 2009 at 9:51 PM, XinMeng xm...@capitalbio.com wrote:
There's 10 files in c:\\
I wanna copy 3 of them to d:\\
How to do it via R?
Thanks!
__
R-help@r-project.org mailing list
Exactly what are you trying to do? Are you trying to just change a subset
of the values? 'subset' does not have an 'assignment' operator. Maybe you
want something like this (but it is not clear from your description. Also
it is not clear if you have exactly the same set of matching values in
If DF is your data frame:
DF2 - edit(DF)
and then make the changes manually in the spreadsheet that
pops up.
On Tue, May 19, 2009 at 3:50 PM, tsunhin wong thjw...@gmail.com wrote:
Dear R users,
I have 1 data.frame of 1500x80 - data1. I found out that there are a
few cells of data that I
Dear R users,
I have been using a dynamic data extraction from raw files strategy at
the moment, but it takes a long long time.
In order to save time, I am planning to generate a data set of size
1500 x 2 with each data point a 9-digit decimal number, in order
to save my time.
I know R is
Hi R users:
Is there a function to obtain the correlation within groups
from this very simple lme model?
modeloMx1
Linear mixed-effects model fit by REML
Data: barrag
Log-restricted-likelihood: -70.92739
Fixed: fza_tension ~ 1
(Intercept)
90.86667
Random effects:
Formula: ~1 |
I am struggling with a simple repeated-measure model:
fit-lme(trait~year * A, random = ~1|subj/year)
A being a factor with three levels. I got have the following results
for anova(fit):
numDF denDF F-value p-value
(Intercept) 1 126 2471.4720 .0001
year 2060
Hi all,
I installed the package inline (windows-version) but can not compile any
code, I alway get an error message
ERROR(s) during compilation : source code errors or compiler
configuration errors!
Unfornutanely there is no description where the package finds a
c-compiler nor where so set
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