roger koenker wrote:
Why I love R [Number 6]:
Chinese extend a helping hand to Russians who happen to be in Brazil
about a package written in Germany. Trotsky would be proud -- and
amazed!
... and it's so . r specific!
vQ
__
Your R is ancient, and the R posting guide asked you to update before
posting.
This is a problem in a contributed DBMS package, so the posting guide
asked you to contact the maintainer and the R-sig-db list would be
the appropriate list to use. But please ensure you are using a
current
Hi all,
Suppose I hve this vector:
x
[1] 3 4 7 17 22 12 15 12 3 3 1 1
How can I remove the top-3 element.
Yielding only:
[1] 17 22 12 15 12 3 3 1 1
- Gundala Viswanath
Jakarta - Indonesia
__
R-help@r-project.org mailing list
Hi,
I have fitted quasibinomial GLM [glm(y ~ ..., family = quasibinomial)]
to a binary response variable; quasibinomial, because there were clear
signs of underdispersion in a 'simple' binomial GLM, and so the
dispersion is a free parameter in the model.
My question is now: In a
try this:
x[-(1:3)]
# or
tail(x, -3)
Best,
Dimitris
Gundala Viswanath wrote:
Hi all,
Suppose I hve this vector:
x
[1] 3 4 7 17 22 12 15 12 3 3 1 1
How can I remove the top-3 element.
Yielding only:
[1] 17 22 12 15 12 3 3 1 1
- Gundala Viswanath
Jakarta - Indonesia
Have a look at ?tail
tail(x, -3) should do the trick.
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel biometrie, methodologie en kwaliteitszorg
Hi List,
I am trying to leverage my knowledge of R in trying to use it for tasks that
may not make R the best choice for these tasks.
I wish to automate a web scraping task, which requires a multi-step
procedure:
1) log in to a website
2) Go to a particular page
3) From the drop down menu, click
Try Firefox and an add in called I Macros from www.iopus.com as an simpler
alternative
read some stuff here
http://www.decisionstats.com/2009/01/web-crawling-automation/
regards,
Ajay
On Wed, Feb 18, 2009 at 2:06 PM, Harsh singhal...@gmail.com wrote:
Hi List,
I am trying to leverage my
Hi,
I have a binned data that looks like this.
(8.048,18.05] (-21.95,-11.95] (-31.95,-21.95] (18.05,28.05] (-41.95,-31.95]
81 76 18 18 12
(-132,-122] (-122,-112] (-112,-102] (-162,-152] (-102,-91.95]
Good Morning to Everybody,
I am searching a function which could define a
vector of colors from a vector of gray, from white to black (not from black to
white as the function gray()).
I have to use it in the function image(),
parameter col.
Thank You very much,
Enrico Foscolo
On Tue, 17 Feb 2009, Brigid Mooney wrote:
Thanks for pointing me to the quantreg package as a resource. I was hoping
to ask be able to address one quick follow-up question...
I get slightly different variants between using the rq funciton with formula
= mydata ~ 1 as I would if I ran the same
Yihui Xie wrote:
Chinese extend a helping hand to Russians who happen to be in Brazil
about a package written in Germany, which gladdened an American.
Trotsky would be even more proud -- and amazed!! :-)
Please note that rgl is maintained by a Canadian and two others (O.
Nenadić and W.
enrico.fosco...@libero.it wrote:
Good Morning to Everybody,
I am searching a function which could define a
vector of colors from a vector of gray, from white to black (not from black to
white as the function gray()).
rev(gray())
Uwe Ligges
I have to use it in the function image(),
Moumita Das wrote:
Hi All,
If you have already finished reading my previous emails regarding
segmentation fault , please have a look at this .I think this may help you
to diagnose the reason for the segmentation fault and help me,because i
don't understand much.
Rather than running the
phoebe kong wrote:
Hi friends,
I have questions about printing a pretty big size matrix.
As you could see from below, the matrix wasn't showed in R at full size
(11X11), but it was cut partly into three smaller matrices (11X4,11X4,11X3).
I'm wondering if there is a way to show the whole matrix
Gundala Viswanath wrote:
Hi,
I have a binned data that looks like this.
(8.048,18.05] (-21.95,-11.95] (-31.95,-21.95] (18.05,28.05] (-41.95,-31.95]
81 76 18 18 12
(-132,-122] (-122,-112] (-112,-102]
On Tue, Feb 17, 2009 at 6:59 PM, Esmail Bonakdarian esmail...@gmail.com wrote:
Well, I have a program written in R which already takes quite a while
to run. I was
just wondering if I were to rewrite most of the logic in Python - the
main thing I use
in R are its regression facilities - if it
R-help,
How can I specify the distance between the axis and axis annotation?
Thanks in advance
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
have a look at ?par() and specifically parameter 'mgp', e.g.,
compare
par(mfrow = c(1, 2))
plot(1, 1)
plot(1, 1, mgp = c(2.5, 0.5, 0))
I hope it helps.
Best,
Dimitris
Luis Ridao Cruz wrote:
R-help,
How can I specify the distance between the axis and axis annotation?
Thanks in advance
Luis Ridao Cruz wrote:
R-help,
How can I specify the distance between the axis and axis annotation?
I don't think you can do this directly, but you can do it using mtext.
For example:
x - 1:10
y - rnorm(10)
plot(x,y, axes=F)
box()
at - pretty(x)
min - par(usr)[1]
max - par(usr)[2]
at
2009/2/17 Esmail Bonakdarian esmail...@gmail.com:
Well, I have a program written in R which already takes quite a while
to run. I was
just wondering if I were to rewrite most of the logic in Python - the
main thing I use
in R are its regression facilities - if it would speed things up. I
--
Message: 72
Date: Tue, 17 Feb 2009 22:05:46 퍍 (UTC)
From: Hans W. Borchers hwborch...@gmail.com
Subject: Re: [R] Subset Regression Package
To: r-h...@stat.math.ethz.ch
Message-ID: loom.20090217t215556-...@post.gmane.org
Content-Type: text/plain; charset=us-ascii
Gabor Grothendieck wrote:
See ?Rprof for profiling your R code.
If lm is the culprit, rewriting your lm calls using lm.fit might help.
Yes, based on my informal benchmarking, lm is the main bottleneck, the rest
of the code consists mostly of vector manipulations and control structures.
I
Hello,
How to produce .tif graphic in colors using bitmap function?
e.g this produces figure in grayscale
bitmap(file=volc.tif, type = tifflzw, res = 300)
image(t(volcano)[ncol(volcano):1,])
dev.off()
I'm using Windows XP and ghostscript.
R.Version()
$platform
[1] i386-pc-mingw32
$arch
[1]
On Wed, Feb 18, 2009 at 7:27 AM, Esmail Bonakdarian esmail...@gmail.com wrote:
Gabor Grothendieck wrote:
See ?Rprof for profiling your R code.
If lm is the culprit, rewriting your lm calls using lm.fit might help.
Yes, based on my informal benchmarking, lm is the main bottleneck, the
rest
Lauri Nikkinen wrote:
Hello,
How to produce .tif graphic in colors using bitmap function?
e.g this produces figure in grayscale
bitmap(file=volc.tif, type = tifflzw, res = 300)
image(t(volcano)[ncol(volcano):1,])
dev.off()
Why not upgrade R and use the tiff() device?
Uwe Ligges
I'm
GaGr == Gabor Grothendieck ggrothendi...@gmail.com
on Tue, 17 Feb 2009 20:53:18 -0500 writes:
GaGr Check out sum.exact and cumsum.exact in the caTools package.
library(caTools)
GaGr Loading required package: bitops
x - 1/(12:14)
sum(x) - cumsum(x)[3]
GaGr [1]
Hi all,
I want to approximate te shape of an area defined by a set of points.
The convex hull is not good enough, but I think that an alpha shape
would be fine. I did an RSiteSearch(), google search, RSeek.org search,
looked at the CRAN Views, but was unable do find a function in R that
t c mudiver1200 at yahoo.com writes:
Dear List,
I am having problems running stepAIC with a
negative binomial regression model. I am working with data on
manta ray abundance, using 20 predictor variables.
[snip]
The model I ran was:
glm.nb.fullglm.nb(mantas~site+year+
Dear List,
I have a data set stored in the following format:
head(dat, n = 10)
id sppcode abundance
1 10307 1000 1
2 10307 16220602 2
3 10307 2000 5
4 10307 2011 2
5 10307 2400 1
6 10307 402183
7 10307 40210102
On 18/02/2009 7:50 AM, Mark Difford wrote:
Duncan Murdoch wrote:
I don't think you can do this directly, but you can do it using mtext.
This is not correct.
It was correct at the time I wrote it. Of course things have changed
now that you and Dimitris have been so helpful: now I *do*
Dear all,
Objective: I am trying to learn about neural networks. I want to see
if i can train an artificial neural network model to discriminate
between spam and nonspam emails.
Problem: I created my own model (example 1 below) and got an error of
about 7.7%. I created the same model using the
As it happens, I have also been looking into this. I began by
considering
Ken Clarkson's hull: http://www.netlib.org/voronoi/hull.html but
eventually
discovered that its alpha shapes don't seem to treat holes in regions,
only
simply connected regions. (I would be happy to hear to the
I would think this could be approached by segmenting the probability volume
using identities such as these:
P(Y1 Z1, Y2 Z2, Y3 Z3, Y4 Z4) + P(Y1 Z1, Y2 Z2, Y3 Z3, Y4 Z4) =
P(Y1 Z1, Y2 Z2, Y3 Z3, Y4 Inf)
and
P(Y1 Z1, Y2 Z2, Y3 Z3, Y4 Inf) + P(Y1 Z1, Y2 Z2, Y3 Z3, Y4 Inf)
Gundala Viswanath wrote:
Dear all,
I have a binned data that looks like this:
dat
(-1,9] (9,19] (19,29] (29,39] (39,49] (49,59] (59,69] (69,79]
10063374 79 1643443
(79,89] (89,99]
62
I tried to plot a
lm does lots of computations, some of which you may never need. If speed
really matters, you might want to compute only those things you will really
use. If you only need coefficients, then using %*%, solve and crossprod will
be remarkably faster than lm
# repeating someone else's example
#
If the data are cross-classified, then hwy would you want a hierarchical
linear model? You might try the lmer function for this instead.
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Luwis Tapiwa Diya
Sent: Tuesday, February
lm(y ~ x-1)
solve(crossprod(x), t(x))%*%y# probably this can be done more
efficiently
You could do
crossprod(x,y) instead of t(x))%*%y
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Apologies, Jim Holtman has pointed out a couple of problems/queries with
my original email that I would like to make clear.
Firstly, I introduced a typo when trying to be helpful. In my email
below, I had incorrectly typed out one of the species codes I would
count:
1000
16220602
2011
Duncan Murdoch wrote:
There's no real difficulty there: axis takes an mgp arg as well.
Thanks for that. A good bit of practical advice, which I hadn't yet clicked
on. I won't comment on the thinking thing;)
Regards, Mark.
Duncan Murdoch-2 wrote:
On 18/02/2009 7:50 AM, Mark Difford wrote:
Thank you very much for your help
Alex
On Wed, Feb 18, 2009 at 1:26 PM, Pedro Silva psi...@porto.ucp.pt wrote:
--
Message: 72
Date: Tue, 17 Feb 2009 22:05:46 í (UTC)
From: Hans W. Borchers hwborch...@gmail.com
Subject: Re: [R] Subset Regression Package
To:
Thanks. I upgraded to R 2.8.1 and tried
tiff(filename = volc.tif, width=600, height=400, compression =
none, bg = white, res = 300)
image(t(volcano)[ncol(volcano):1,])
dev.off()
but this produces error
Error in plot.new() : figure margins too large
How this should be modified to produce a
The funniest part is that we are close to carnival in Brazil...
vacation time... more than 30C... and I am the one to try to get back
to the track...
Any clue on how to rotate the object? Examples?
Also, still on the same object. If I change zoom, position, etc. with
the mouse, where to query
Let Y be a normal multivariate function. For example, let Y have 4
dimensions. I want to calculate
P(Y1 Z1, Y2 Z2, Y3 Z3, Y4 Z4).
There are R functions to do the calculation if all the inequalities
are of the type (the cdf). But is there an R function where the
The cdf, and some
Lauri Nikkinen wrote:
Thanks. I upgraded to R 2.8.1 and tried
tiff(filename = volc.tif, width=600, height=400, compression =
none, bg = white, res = 300)
image(t(volcano)[ncol(volcano):1,])
dev.off()
but this produces error
Error in plot.new() : figure margins too large
How this should be
On 18/02/2009 10:00 AM, Iuri Gavronski wrote:
The funniest part is that we are close to carnival in Brazil...
vacation time... more than 30C... and I am the one to try to get back
to the track...
Any clue on how to rotate the object? Examples?
example(spin3d)
Also, still on the same
On Wed, 18 Feb 2009, Lauri Nikkinen wrote:
Thanks. I upgraded to R 2.8.1 and tried
tiff(filename = volc.tif, width=600, height=400, compression =
none, bg = white, res = 300)
image(t(volcano)[ncol(volcano):1,])
dev.off()
but this produces error
Error in plot.new() : figure margins too large
Hi Jim,
or sorting the columns of the above table if that is what you are using to
plot.
How do you do that? Yes I am using that data exactly for the plotting.
- GV.
Jim
__
R-help@r-project.org mailing list
Thanks Prof Ripley, now I understood.
tiff(filename = volc.tif, width=600, height=400, compression =
none, bg = white, res = 300, pointsize=3)
par(mar=c(3,3,2,2), cex=1)
image(t(volcano)[ncol(volcano):1,], xaxt=n, yaxt=n)
axis(1, at=seq(0, 1, 0.1), cex.axis=0.8, tick=T)
axis(2, at=seq(0, 1, 0.1),
Hi,
If the convex hull for *all* the data points is not ideal enough, is
it feasible to break the data into small subsets using clustering
methods such as kmeans() and compute the convex hull for each cluster?
Finally we are able to know the borders of all clusters using
chull(); I don't know how
Just to be sure you're aware, there are packages for chromatograpy and mass
spec data in Bioconductor. Like xcms. Don't think any will directly address
your problem, but they might be useful.
Michael
On Tue, Feb 17, 2009 at 5:44 AM, bartjoosen bartjoo...@hotmail.com wrote:
Hi,
I'm trying to
SM == Stavros Macrakis macra...@alum.mit.edu
on Wed, 18 Feb 2009 10:00:40 -0500 writes:
SM Nice! Glad to hear it. It sounds as though it is still possible for
SM cumsum(x)[length(x)] to not be exactly equal to sum, though?
Well, possible, probably yes, platform-dependently;
I have a dissimilarity dataset with the form:
1 1 dissimilarity value
1 2 ...
1 3
1 4
2 2
2 3
2 4
...
I would like to do nonmetric multidimensional scaling with this data, but I
am having trouble using this format. I would like to either find a function
that accepts this format or find
XLSolutions Corporation (www.xlsolutions-corp.com) is proud to announce
our*** R/Splus Fundamentals and Programming Techniques and R Advanced
Programming***courses at USA locations for March - April 2009.
* New York City ** March 19-20, 2009
R/Splus Fundamentals and
Hmm. Why not use the same method to guarantee the same result? Or at
least document the possibility that cumsum(x)[length(x)] != sum(x)...
that seems like an easy trap to fall into.
-s
On Wed, Feb 18, 2009 at 11:39 AM, Martin Maechler
maech...@stat.math.ethz.ch wrote:
SM == Stavros
Can you show us the code used to get the data?
The usual methods that I can think of would have sorted the columns correctly
for you. The fact that this is not the case indicates that you are using a
different method, or doing something that looses the information along the way.
If you show
To answer my own post, and for the archives (hopefully not that anyone
has to repeat what I had to do ;-), after much hair-pulling , frowning
at the screen and general dumb headedness the following slab of R code
achieves the results I wanted. It isn't elegant but does a job.
msr - function(x) {
For version 2.3-30 of chron which just appeared on CRAN this can
be simplified to:
library(chron)
tt - times(0:47/48)
tt
chron(1/1/09, tt) # no rep needed
On Mon, Feb 16, 2009 at 6:04 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
Try this (and see R News 4/1 for more).
library(chron)
On 18/02/2009 12:41 PM, Stavros Macrakis wrote:
Hmm. Why not use the same method to guarantee the same result? Or at
least document the possibility that cumsum(x)[length(x)] != sum(x)...
that seems like an easy trap to fall into.
Assuming equality of floating point numbers computed by two
I am using glm.nb, a ~b*c ( b is categorical and c is continuous). when I
run this model I get the warning message:
Warning messages:
1: In theta.ml(Y, mu, sum(w), w, limit = control$maxit, trace =
control$trace :
iteration limit reached
2: In theta.ml(Y, mu, sum(w), w, limit = control$maxit,
Hi all, do you know if an R program is compiled to machine language when
executed? And also is there any way to disassemble an R code/program: to see
how it is generating the machine instructions for the processor? Thanks
--
View this message in context:
Dear R users,
I use function kqr from package kernlab a large number of time and
every time it is used it prints an info message which slows the
process. Please note that it is not a warning message or an error
message and that there is no info option in the function that could
be set to
hmm, further investigation shows that two different fits are used.
Why did nnet decide to use different fits when the data is basically
the same (2 factors in nn1 and binary in nn2)?
# uses an entropy fit (maximum conditional likelihood)
nn1
a 57-3-1 network with 178 weights
inputs: make
I am using auto.arima to find the best arima model but am a little confused
by the output. I want to choose the best model using the BIC criteria.
This is my code (straightforward where a is the data)
Hi all,
When running Rmdr using the demo data file using the following
commands:
data(mdrdata)
cvk-10
nbr=2
res-rmdr(mdrdata,10,2, randomize=TRUE)
I could not find the statistical results, but like this:
[1] 1
Cross Validation 1 Wed Feb 18 09:05:23 2009
The best set of loci is 13 17
Cross
This is my approach:
If cosa is your data.frame . e.g.
cosa
i1 i2 dis
[1,] 1 1 0.00
[2,] 1 2 0.93
[3,] 1 3 0.80
[4,] 1 4 1.00
[5,] 2 2 0.00
[6,] 2 3 0.02
[7,] 2 4 0.22
[8,] 3 3 0.00
[9,] 3 4 0.95
[10,] 4 4 0.00
# first crate a square matrix of
This is my situation:
I have a significant amount of data, and need to send it in pieces to R. I
need R to return certain parameters for further use.
I am sending files from C# (that are being queried from a database) into R.
Currently I am trying to use the R(D)-Com package to figure out how to
francogrex wrote:
Hi all, do you know if an R program
If R program means pure R code, than now, R is an interpreted language.
For more information on the interpreter, you might want to start reading
the manual R Internals.
Uwe Ligges
is compiled to machine language when
executed? And
Hi all,
I'm trying to fit a model using the shorthand coeff[factor] instead of
coding dummy variables. Is there a way to keep this notation when
specifying constraints? See example below:
x = runif(200)
b0 = c(rep(0,100),runif(100))
b1 = 1
fac - as.factor(rep(c(0,1), each=100))
y =
Hello R-help,
I am trying to import a large dataset from SPSS into R. The SPSS file
is in .SAV format and is about 1GB in size. I use read.spss to import
the file and get an error saying that I have run out of memory. I am
on a MAC OS X 10.5 system with 4GB of RAM. Monitoring the R process
tells
Hi list,
I would like to use ggplot2 in creating a line plot with 4 lines (groups), 2
of which I want in colour and the remaining two as dotted lines.
### R code ###
library(ggplot2)
### create data
vals - rnorm(400)
div- c(rep(A,100),rep(B,100),rep(C,100),rep(D,100))
n- rep(1:100,4)
df-
G'day all,
On Wed, 18 Feb 2009 12:41:27 -0500
Stavros Macrakis macra...@alum.mit.edu wrote:
Hmm. Why not use the same method to guarantee the same result?
Hmm, I did not look at the source code but, potentially, sum() could
use some tricks to reduce rounding errors further that would not be
Dear R users,
My question is more methodology related rather than specific to R usage. Using
time on study as time in a cox model, eg:
library(Design)
stanf.cph1=cph(Surv(time, status) ~ t5+id+age, data=stanford2, surv=T)
#In this case the 1000-day survival probability would be:
Duncan, Berwin, Martin,
Thanks for your thoughtful explanations, which make perfect sense.
May I simply suggest that the non-identity between last(cumsum) and
sum might be worth mentioning in the cumsum doc page?
-s
__
Dear R experts:
I have a list (a very long one) and I need to create successively txt
outputs (on diferent files ideally) for the data of each component of the
list.
How can I do this?
Thanks in advance!!
[[alternative HTML version deleted]]
Harsh wrote:
Hi list,
I would like to use ggplot2 in creating a line plot with 4 lines (groups), 2
of which I want in colour and the remaining two as dotted lines.
### R code ###
library(ggplot2)
### create data
vals - rnorm(400)
div- c(rep(A,100),rep(B,100),rep(C,100),rep(D,100))
n-
Hi,
For me running winbugs through wine just works. Even when I do not specify
any directories.
The example they give in the bugs helpfile was my starting point.
Setup is suse 11.1, latest Wine, R, R2WinBUGS winbugs.
I assume you first tried without specifying directories?
The directories
I've downloaded the RcolorBrewer package, but when I try to run
mypalette-brewer.pal(7,Greens)
(or any other command with brewer.pal)
I get the following error message - Error: could not find function
brewer.pal
Does anyone know why that's happening? Is there smth else I need to
download?
diego Diego wrote:
Dear R experts:
I have a list (a very long one) and I need to create successively txt
outputs (on diferent files ideally) for the data of each component of the
list.
How can I do this?
Maybe this could help you:
list2Files - list(1:3, letters[1:10], matrix(1:15, 5, 3))
Alina Sheyman wrote:
I've downloaded the RcolorBrewer package, but when I try to run
mypalette-brewer.pal(7,Greens)
(or any other command with brewer.pal)
I get the following error message - Error: could not find function
brewer.pal
Does anyone know why that's happening? Is there smth else I
I figured it out
thanks
On Wed, Feb 18, 2009 at 3:50 PM, Domenico Vistocco visto...@unicas.itwrote:
Alina Sheyman wrote:
I've downloaded the RcolorBrewer package, but when I try to run
mypalette-brewer.pal(7,Greens)
(or any other command with brewer.pal)
I get the following error message
Hello R Users and Developers,
I have a basic question about how R works. Over the past few years I have
struggled when I try to generate a new data frame that I believe should
contain numeric data in some columns and character data in others only to
find everything converted to character data.
Hello dear R members.
I have been learning the Anova syntax in order to perform an SS type III
Anova with repeated measures designs (thank you Prof. John Fox!)
And another question came up: where/what are the (between/within) residuals
for my model?
Play code:
phase -
gina patel wrote:
I would like to add the greek letter mu to replace u in my title shown below.
main=R=[0.001uM]:A=[750uM]
i tried using main=expression(R=[0.001~mu~M]:A=[750~mu~M])
plot(1:3, main=expression(paste(R=[0.001~,mu,~M]:A=[750~,mu,~M])))
Ciao,
domenico
but this is not working at
Uwe Ligges wrote:
Hi all,
I've managed to get JAGS working on my Ubuntu Hardy Linux with a 32-bit
computer and AMD processors using R 2.8.1. JAGS is great. I've read
that
JAGS is the fastest, but that hasn't been my experience. At any rate, I
have more experience with WinBUGS under Windows
Dear everyone
I would like to change values in vectors doing a translation. i.e. I have a
start vector giving me the levels in one vector (numbers 1 to x - rating)
and then I have a second vector giving me the values to be allocated (loss
probabilities), but the number of potential rating
The culprit is the cbind function. When given 2 vectors (not already something
else), cbind will create a matrix, not a data frame. A matrix can only have 1
type, so the numbers get converted to character. In your first example you
never do create a data frame, you just build a matrix (try
I have yet another question concerning maps.
This time I want to create a colored map of number of students by state.
Can this be done using palettes in Rcolor brewer, is there some other way?
I've been looking through R archives, but am still really at a loss here, so
all help will be much
On 18/02/2009 4:24 PM, Christian Langkamp wrote:
Dear everyone
I would like to change values in vectors doing a translation. i.e. I have a
start vector giving me the levels in one vector (numbers 1 to x - rating)
and then I have a second vector giving me the values to be allocated (loss
Alan Smith wrote:
Hello R Users and Developers,
I have a basic question about how R works. Over the past few years I have
struggled when I try to generate a new data frame that I believe should
contain numeric data in some columns and character data in others only to
find everything converted
The call to replace is replacing the 1st 3 elements of a (your indexes in
Trans_CR) with the values and leaving the 4-6 elements alone. For what you
want, try:
A - Trans_Prob_values[ match(a, Trans_CR) ]
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain
Hi all,
I've compiled R (version 2.8.1) from the source code with --with-
blas= option in order to use external multi-threaded blas package.
However, it's very hard to verify that compilation is correct and R is
using multi-threads correctly or not. Which command or operation in R
will run with
Thank you for providing advice on this graphics question.
I am building an interaction.plot.
d=data.frame(xx=c(3,3,2,2,1,1),yy=c(4,3,4,3,4,3),zz=c(5.1,4.2,4.4,3.5,3.3,-1.1,-1.3)
d[[1]]-as.factor(d[[1]])
d[[2]]-as.factor(d[[2]])
print(d)
interaction.plot(d$xx, d$yy, d$zz,
type=b,
Hi,
Thanks for your help. I have looked at the beginners documentation and
while there are options to configure various aspects of the plot none of
them seem to have the desired effect. I have managed to ensure that the
plot fills the space vertically with no margins, no axes etc (using
Dear Tal,
I suppose that the between residuals would be obtained, for your example,
by residuals(mod.ok). I'm not sure what the within residuals are. You
could apply the transformation for each within-subject effect to the matrix
of residuals to get residuals for that effect -- is that what you
Hi all:
Using the example below, is there a way to add Y axis titles to each graphic
instead of sharing the same title?
library(ggplot2)
RT = matrix(c(814, 500, 424, 394, 967, 574, 472, 446),4,2)
colnames(RT) = c('repetition','alternation')
rownames(RT) = c('7-yrs','11-yrs','15-yrs','21-yrs')
dobomode wrote:
Hello R-help,
I am trying to import a large dataset from SPSS into R. The SPSS file
is in .SAV format and is about 1GB in size. I use read.spss to import
the file and get an error saying that I have run out of memory. I am
on a MAC OS X 10.5 system with 4GB of RAM. Monitoring
I am fairly new to log-linear modelling, so as opposed to trying to fit
modells, I am still trying to figure out how it actually works - hence I am
looking at the interpretation of parameters. Now it seems most people skip
this part and go directly to measuring model fit, so I am finding very few
James,
you're probably interested in image function rather than in
filled.contour. Type ?image to see the syntax.
Cheers,
Patrizio
2009/2/18 James Nicolson jlnicol...@gmail.com:
Hi,
Thanks for your help. I have looked at the beginners documentation and
while there are options to configure
Try this (or replace selected occurrences of * with ~ to get spaces
instead of juxtaposition):
plot(1:3, main = ~ R=[ * 0.001 * mu * Mu * ]:A=[ * 750 * mu * Mu * ])
On Wed, Feb 18, 2009 at 3:56 PM, gina patel ginapatel1...@yahoo.com wrote:
I would like to add the greek letter mu to replace u in
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