Thank you very much !!! It works !!!
Sorry it took me some time to understand your solution and apply it to my
extended dataset. Just got it working !!!
Yes as.numeric is the trick..
Many thanks again for your help and time.
Regards
Meenu
On Sun, Aug 2, 2009 at 6:06 AM, David Winsemius
Hi,
The Rserve implementation of REngine does not support references (yet?).
Anyway, I don't think references are what you need here.
You probably want the methods createFile and openFile that create
RFileInputStream and RFileOutputStream which you can use to transfer
files through the R
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Jan
Theodore Galkowski
Sent: Monday, August 03, 2009 10:23 PM
To: R Project
Subject: [R] na.strings and the like; suspending
interpretation of NA
Can someone point me to
Jan Theodore Galkowski wrote:
Can someone point me to the proper place in the documentation or on the
Wiki where I can learn how to get R to stop interpreting the string NA
as something special? I have a table in a database which contains
(among other things) country codes and continent codes.
Murray Jorgensen wrote:
Hi Peter,
there is no problem if the missing cell is not in the first row or
column: the corresponding interaction parameter is omitted. In my case
the data in the (1,4) cell is missing. What results is clear to me now:
the (3,4) interaction parameter is dropped so
Dear all,
Rank of a matrix depends on which factors? Only on rows or
coumns? or both ? If there is a collinearlity in the variables ( columns )
does it effects the rank?
X-matrix((rnorm(1)),50)
dim(X)
[1] 50 200
qr(X)$rank
[1] 50
X[,2]-X[,30]
qr(X)$rank
[1] 50
Dear Harry,
Your model seems rather complex. Do you have enough data to support it?
Did you check for multicollinearity between the variables?
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en
Put your function in try() and the test it's class
gene.seq - try(getSequence (id=gene.map[,ensembl_transcript_id],
type=ensembl_transcript_id, seqType=3utr, mart=hmart))
if(class(gene.seq) == try-error){
#code to run when an error occurs
} else {
#code to run when no error
Hi Peter,
there is no problem if the missing cell is not in the first row or
column: the corresponding interaction parameter is omitted. In my case
the data in the (1,4) cell is missing. What results is clear to me now:
the (3,4) interaction parameter is dropped so that (Intercept) + Biv
now
Thanks very much :handshake:
David Winsemius wrote:
You might want to look at the ave function. It will calculate a
function within IDs and you can assign that as another row in the
datafrme before you exclude the duplicates.
David Winsemius, MD
Heritage Laboratories
West
Thanks you, this helps.
Great,
Thomas
2009/8/3 Michael Denslow michael.dens...@gmail.com:
Hi Thomas,
On Sun, Aug 2, 2009 at 11:02 AM, Thomas Steinerfinbref.2...@gmail.com wrote:
Is there a R-package with a function that returns me the timezone, if
I hand over longitude and latitude?
I know
AR == Alex Roy alexroy2...@gmail.com
on Tue, 4 Aug 2009 09:56:42 +0200 writes:
AR Dear all, Rank of a matrix depends on which factors?
AR Only on rows or coumns? or both ? If there is a
AR collinearlity in the variables ( columns ) does it
AR effects the rank?
This has
John Sanders-2 wrote:
How can I fit a truncated power law to a vector? I can't find a function
to do that. If the function provides an AIC, even better.
Okay, power law I understand - f(x) = k.x^a, or on the log-scale log(f(x))
= log(k) + a log(x) (linear)
I was unfamiliar with the term
Hello,
Is there a clearcut answer as to why R prints 'NA' sometimes instead of
standard errors?
mle2(minuslogl = nlikfun4, start = list(a = 1, c = 1, d = 0.2,
b = 0.1, b1 = 0.1), method = Nelder-Mead)
Coefficients:
Estimate Std. Error z value Pr(z)
a 3.83845751 0.47320236 8.1117 4.993e-16
Hello,
I've come across a strange error...
Here is what happens:
model - svm(traindata,trainlabels, type=C-classification,
kernel=radial, cost=10, class.weights=c(win=3,lose=1),
scale=FALSE, probability = TRUE)
predictions - predict(model, traindata)
pred - prediction(predictions,
In a raster asc object, I'd like to take the positions (x and y coordinates)
for a given pixel ID. Any idea about how to do this?
___
Paulo E. Cardoso
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi,
you need the score value , have a look at ?svm.predict and in the ROCR
example.
traindata - as.data.frame(matrix(runif(1000),ncol=10))
trainlabels -
as.factor(sample(c(win,lose),nrow(data),replace=T,prob=c(0.5,0.5)))
model - svm(traindata,trainlabels, type=C-classification,
Hi All,
I have some data where the dependent variable is a score, low (1:3) or
high (8:9), and the independent variables are 21 genotypic markers.
I'm fitting a logistic regression on the whole dataset after
transforming the score to 0/1 and normal linear regression on the high
and low
Hi
I have dataset that consists of two columns
AB0.102
AC -0.002
BA -0.102
BC 0.270
CA 0.002
CB -0.270
I wish to create a matrix so that I can eventually plot the data.
A
B
C
A
1
The function getXYcoords in the package adehabitat might help. You may
also consider asc2spixdf, which returns an object of class
SpatialPixelsDataFrame (where the coordinates are stored as well as the
values of the pixel).
Hope this helps,
Clément Calenge.
Paulo Eduardo Cardoso wrote:
In
Split the first column into two columns. One with the first letter and
one with the last letter. Then you cast() from the reshape-package to
create the matrix you want.
HTH,
Thierry
ir. Thierry Onkelinx
Instituut
You can try something about like this:
merge(transform(x, V1 = gsub(^[A-Z], , x$V1),
V3 = gsub([A-Z]$, , x$V1)),
data.frame(V1 = LETTERS[1:3],
V3 = LETTERS[1:3],
V2 = 1),
by = c(V1, V3), all = TRUE)
On Tue, Aug 4, 2009 at 8:35 AM,
Hello, mailing list!
I'm using a manova in R to study the responses of four dependent variables. I
would like to do a post hoc analysis, but I don`t know which is the best and
how to introduce in R.
I'm using a pairwise t test, but I'm not sure if it is correct, I like to use
tukeyHSD, but
My apologies, to elaborate
I carried out a correlation analysis and I want to plot the data (similar to
the graphs available in the corrplot package. However, the results are as
follows (I have many more combinations):
AB0.102
AC -0.002
BA -0.102
BC
Hi there,
I'm automatically generating buttons depending on the amount of rows
my dataframe consists of. The buttons are supposed to call a barplot-
function. Generating the buttons and displaying the barplot isn't a
problem, but once I press one of the buttons, I'm getting an error-
Dear Glen_b,
The function I'm trying to fit has the form:
P(k)
~ k^(-y) exp (– k ⁄ kx)
And deals with count data. I'm a newbie, so any more specific suggestion would
be greatly appreciated.
john
John Sanders-2 wrote:
How can I fit a truncated power law to a vector? I can't find a
Hi Steve,
First of all, thanks for your answer.
I did all that you suggested and now I have some questions.
1) when I use svm.m1$coefs I have 180 values (the number of SV) of 10 and
-10, I think that it is related with C=10 because when I change for C=100 I
have 180 values of 100 and -100. I
My apologies, to elaborate
I carried out a correlation analysis and I want to plot the data (similar to
the graphs available in the corrplot package. However, the results are as
follows (I have many more combinations):
AB0.102
AC -0.002
BA -0.102
BC
alexander russell-2 wrote:
Hello,
Is there a clearcut answer as to why R prints 'NA' sometimes instead of
standard errors?
mle2(minuslogl = nlikfun4, start = list(a = 1, c = 1, d = 0.2,
b = 0.1, b1 = 0.1), method = Nelder-Mead)
Coefficients:
Estimate Std. Error z value Pr(z)
Dear List-Members,
I have a problem with the function lqs() from package MASS. In some cases it
produces different results for the same settings and needs a random seed to be
set, in other cases not.
I really cannot understand, why this happens. As well I do not understand what
exactly you
Allow me to reword this question. I have performed two fits to the same set
of data below: a weighted fit and an unweighted fit. I performed the
Durbin-Watson tests on each fit using dwtest and durbin.watson. For a
given fit (weighted or unweighted), should both dwtest and durbin.watson be
giving
I think the statistics are the same, but the p-values are not exactly
the same as they used different methods for the p-value. car uses
bootstrapping and lmtest uses the pan algorithm, said from the help
pages.
2009/8/4 Tom La Bone boo...@gforcecable.com:
Allow me to reword this question. I
Michael Becher wrote:
Dear Professor Harrell,
please allow me a brief question about the wtd.quantile() function in
your marvelous R package Hmisc that I was not able to answer using the
documentation or the web. For type=quantile, what is the exact
statistic that is estimated? The
Dear Daniel,
Thanks a lot for your answer. I will take a look in such package.
Best regards,
Caio
On Tue, Jul 28, 2009 at 10:38 PM, Daniel Malter dan...@umd.edu wrote:
Caio, check the lme4 library. The lmer function allows for fixed and random
effects.
Daniel
-
Hello,
Actually you are right. I was looking on the wrong direction. But I still
got some doubts about how to use those methods.
I want to open a file on the client machine, for example a txt
tab-delimited, and create a dataframe with its information on R.
I got to create a RFileInputStream
Hello,
I have a package that builds fine using R CMD build pkg --no-vignette,
but I get the following error when running R CMD build pkg:
** building package indices ...
Error in setwd(OutVignetteDir) : cannot change working directory
ERROR: installing package indices failed
I don't know why it
I have a piece of code as the one at the bottom, unfortunately since it
involves time series from a db it's not easy to give to mailing list a working
script.
It becomes very slow after few hundred iterations over variable sp (must
process several thousands).
The Rprof() indicates that the
My concern is that the two tests give different DW statistics for the
weighted fit and very different p-values for the same DW statistic for the
unweighted fit. Is there a right answer here?
--
View this message in context:
Thanks to Hadley (shortest and sweetest), Eric and Gabor.
I was _so_ close.
Now I think I've learned some things about the reshape function and package!
(Also transform and interaction.)
Thanks to you all,
-- David
-Original Message-
From: hadley wickham [mailto:h.wick...@gmail.com]
Dear all,
I am trying to import data with read.csv and my file is on remote
machine.
I believe that I need to open a connection, not sure about syntax
though.
I would appreciate any suggestions,
Thanks!
Olga
__
R-help@r-project.org mailing list
Hi,
On Aug 4, 2009, at 10:37 AM, Olga Lyashevska wrote:
Dear all,
I am trying to import data with read.csv and my file is on remote
machine.
I believe that I need to open a connection, not sure about syntax
though.
I would appreciate any suggestions,
Look at the different ways you can
Hi,
I have one critical question in using R.
I am currently working on some research which involves huge amounts
of data(it is about 15GB).
I am trying to use R in this research rather than using SAS or STATA.
(The company where I am working right now, is trying to switch SAS/STATA to
R)
As far
Dear all,
I am attempting to convert 10 NetCDF files into a single NetCDF file, due to
the data input requirements of a model I hope to use. I am using the ncdf
package, version 1.6. The data are global-scale water values, on a monthly
basis for 10 years (ie. 120 months of data in total; at
Hi,
On Aug 4, 2009, at 11:20 AM, Hyo Karen Lee wrote:
Hi,
I have one critical question in using R.
I am currently working on some research which involves huge amounts
of data(it is about 15GB).
I am trying to use R in this research rather than using SAS or STATA.
(The company where I am
On Tue, 4 Aug 2009, Tom La Bone wrote:
My concern is that the two tests give different DW statistics for the
weighted fit and very different p-values for the same DW statistic for the
unweighted fit. Is there a right answer here?
dwtest() is not handling WLS at the moment. I'll have a look
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Hyo Karen Lee
Sent: Tuesday, August 04, 2009 8:21 AM
To: r-help@r-project.org
Subject: [R] One critical question in R
Hi,
I have one critical question in using R.
I am
Does anyone know if there is a function like survdiff which can also handle
left-truncated and right-censored data? When I use it on left-truncated and
right-censored data I get an error message saying Right censored data only.
coxph(Surv(time1, time2, status) ~ factor(group), data=mydata)
On Tue, Aug 4, 2009 at 4:20 PM, Hyo Karen Leetotem...@gmail.com wrote:
I am currently working on some research which involves huge amounts
of data(it is about 15GB).
One point nobody has seemed to make yet is that the above statement
is meaningless...
Do you have a CSV file that is 15GB
On Tue, Aug 4, 2009 at 3:37 PM, Olga Lyashevskao...@herenstraat.nl wrote:
Dear all,
I am trying to import data with read.csv and my file is on remote machine.
I believe that I need to open a connection, not sure about syntax though.
If it's on an HTTP server then you don't need to faff with
Hi,
So the file you want to read is on the client machine, and you want to
transfer it to the server and read it into R ?
What I guess you need is :
- open a FileInputStream, many many tutorials on the web will tell you
how this works.
- open a RFileOutputStream
- call the read(byte[] b)
Actually, I tried doing
data2 = unique(data)
mod = lm(y ~ x1 + ... + xn, data2)
fitted(mod)
and I still get les fitted values than observations.
Federico
On 4 Aug 2009, at 12:18, Federico Calboli wrote:
Hi All,
I have some data where the dependent variable is a score, low (1:3) or
high
Dear R users,
I am new user for elastic net. I am trying to use elasticnet library.
I have marker data with 359 markers and 168 samples, and response is
metabolites. I am trying to do regression between a metabolite and markers.
But i am getting the following error:
Deducer 0.1 has been released to CRAN
Deducer is designed to be a free, easy to use, alternative to proprietary
software such as SPSS, JMP, and Minitab. It has a menu system to do common
data manipulation and data analysis tasks, and an excel-like spreadsheet in
which to view and edit data
Hi,
On Aug 4, 2009, at 1:03 PM, ram basnet wrote:
Dear R users,
I am new user for elastic net. I am trying to use elasticnet library.
I have marker data with 359 markers and 168 samples, and response is
metabolites. I am trying to do regression between a metabolite and
markers.
But i am
Hi,
I've done a more complete response in my blog. http://tr.im/vshK
Romain
On 08/04/2009 06:10 PM, Romain Francois wrote:
Hi,
So the file you want to read is on the client machine, and you want to
transfer it to the server and read it into R ?
What I guess you need is :
- open a
I write about R every weekday at the Revolutions blog:
http://blog.revolution-computing.com
In case you missed them, here are some articles from last month of
particular interest to R users.
http://bit.ly/2HPlOe announced a directory of R user groups available
on the Revolutions blog.
Your first posting made me think that you were complaining that the
fitted values were less than the raw values. Your second posting makes
me think that you may be conflating the English word less with the
word English fewer. Many native speakers make the same error, but in
this context
Hi,
I am getting stuck over an apparently simple problem in the use of regular
expressions :
To collect together the first letters of the words from the Perl motto, “There
is more than one way to do it” in the following form – TIMTOWTDI.
I tried the following code :
# A regex problem
On 4 Aug 2009, at 18:27, David Winsemius wrote:
Your first posting made me think that you were complaining that the
fitted values were less than the raw values. Your second posting makes
me think that you may be conflating the English word less with the
word English fewer. Many native speakers
On 4 Aug 2009, at 18:27, David Winsemius wrote:
Your first posting made me think that you were complaining that the
fitted values were less than the raw values. Your second posting makes
me think that you may be conflating the English word less with the
word English fewer. Many native speakers
Try this:
library(gsubfn)
strapply(astr, \\w+, ~ substr(x, 1, 1), simplify = c)
[1] T i m t o w t d i i t f f T
On Tue, Aug 4, 2009 at 1:28 PM, ravirv...@yahoo.se wrote:
Hi,
I am getting stuck over an apparently simple problem in the use of regular
expressions :
To collect together the
And here is a second way:
strapply(astr, (\\w)\\w+, c, simplify = c)
[1] T i m t o w t d i i t f f T
On Tue, Aug 4, 2009 at 1:42 PM, Gabor
Grothendieckggrothendi...@gmail.com wrote:
Try this:
library(gsubfn)
strapply(astr, \\w+, ~ substr(x, 1, 1), simplify = c)
[1] T i m t o w t d i i t
Thanks Barry and Steve,
I am trying to import data with read.csv and my file is on remote
machine.
I believe that I need to open a connection, not sure about syntax
though.
Probably works with ftp: too. How remote is it?
In fact it is a bit more complicated.
I am working on a Mac machine,
I admit that I've not done a thorough search on this topic, but from the
several instructional manuals and/or tutorials I've looked at, I don't see
any mention of relational database capabilities in R? Have I missed
something, and if so, can someone point me in the right direction to get
Hi,
Did your search include this :
R RSiteSearch( database )
Romain
On 08/04/2009 08:04 PM, Jim Bouldin wrote:
I admit that I've not done a thorough search on this topic, but from the
several instructional manuals and/or tutorials I've looked at, I don't see
any mention of relational
Dear R Users
I'm writing my first simulation in R.
I've put across my problems with a smaller example in the attachment along
with the questions.
Please help.
Best regards
Meenu
mydat-read.table(textConnection(Level spread change State
4.57 1.6 BlF NA
4.45 2.04 BrS NA
3.07 2.49 BlS NA
3.26
Good point. I'm not sure how I missed that.
This does lead to an additional question:
Is the probability of the true label the best prediction to feed to
the ROCR package, or is it better to use the decision.value
Anybody have any experience on this one?
Thanks!
-N
On 8/4/09 3:28 AM,
On Aug 4, 2009, at 2:04 PM, Jim Bouldin wrote:
I admit that I've not done a thorough search on this topic, but from
the
several instructional manuals and/or tutorials I've looked at, I
don't see
any mention of relational database capabilities in R? Have I missed
something, and if so,
Hello,
since a couple of days I'm trying hard to elicit a certain thing
out of the Sweave function of R. Unfortunately I'm quite unsuccessful.
It's only about a small, ridiculous minus sign, which does not appear
in the final pdf of a latex file, if I try to incorporate the Computer-
Modern
Dear UseRs,
I declared a `$` method for a S4 class. Can I have ab automatic completion
for this operator in R? Lists and environment objects provide this feature
by default, but my object is an extension of function class which does
not have subseting defined. How to be?
Thanks for any
Is the probability of the true label the best prediction to feed to
the ROCR package, or is it better to use the decision.value
Since AFAIK they are related by a monotonous transformation, both
approaches should lead to the same ROC curve, shouldn't they? (not
tested)
On Tue, Aug 4, 2009 at
I hadn't thought of that. I'll run some tests...
-N
On 8/4/09 11:49 AM, Tobias Sing wrote:
Is the probability of the true label the best prediction to feed to
the ROCR package, or is it better to use the decision.value
Since AFAIK they are related by a monotonous transformation, both
Hi all,
On October 19, I'll be offering a one data ggplot2 course in
conjunction with the ISMI Manufacturing Week. The course is open to
all and you can attend in person (Austin TX) or over the web. More
information available from http://lookingatdata.com/ismi-2009/
Regards,
Hadley
--
Suppose I have an n-diml array A and I want to extract the first row -- ie
all elements A[1, ...]
Interactively if I know 'n' I can write A[1,] with (n-1) commas.
How do I do the same more generally, eg in a script?
(I can think of doing this by converting A to a vector then extracting
sink(..., type=c(output,message), split=TRUE) at the beginning of
your session should do it?
Jacob Wegelin wrote:
Consider all the text that one sees on the console during an R session.
Is there a way, within R, to make all this text--both the output and
the messages--automatically get
Hi,
On Aug 4, 2009, at 3:23 PM, Steve Jaffe wrote:
Suppose I have an n-diml array A and I want to extract the first
row -- ie
all elements A[1, ...]
Interactively if I know 'n' I can write A[1,] with (n-1) commas.
How do I do the same more generally, eg in a script?
(I can think of
Will take a look when back from holidays in 2 weeks.
Uwe
David Winsemius wrote:
Not sure you can call it a bug when the help page says for angles in
range (180, 360) that some support functions may not work properly.
On Aug 3, 2009, at 2:12 PM, Vivek Ayer wrote:
Hey guys,
Not sure if I
Yes, I was thinking more in terms of mental operations than physical.
I think the following works, but it doesn't seem entirely transparent :-)
Given array A, and a vector of row indices v (ie 1 = v = dim(A)[1]), the
slice of rows v is
A[ outer(v, dim(A)[1]*( 1:prod(dim(A)[-1])-1 ), '+') ]
On Tue, Aug 4, 2009 at 11:37 AM, Vitalie S.vitosm...@rambler.ru wrote:
Dear UseRs,
I declared a `$` method for a S4 class. Can I have ab automatic completion
for this operator in R? Lists and environment objects provide this feature
by default, but my object is an extension of function class
Although you *do* have to re-assign the dimensions, otherwise the result is
just a flat vector, ie
slice - A[ outer(v, dim(A)[1]*( 1:prod(dim(A)[-1])-1 ), '+') ]
dim(slice) - dim(A)[-1]
Steve Jaffe wrote:
A[ outer(v, dim(A)[1]*( 1:prod(dim(A)[-1])-1 ), '+') ]
--
View this message in
You can do
A - HairEyeColor
do.call([, c(list(A),list(1,T,T)))
Sex
Eye Male Female
Brown 32 36
Blue11 9
Hazel 10 5
Green3 2
Regards
Søren
Fra: r-help-boun...@r-project.org [r-help-boun...@r-project.org]
correction -- that would work for a single row, if you want the result to be
an array with one fewer dimensions. But in general you get an array of the
same dimension you started with (where the first dimension may be length 1).
So:
dim(slice) - c(length(v), dim(arr)[-1])
Although you *do*
Thanks. This seems to mirror the output *both* to the console *and* to the
sink file. The error messages, on the other hand, show up only in the
console.
On Tue, Aug 4, 2009 at 3:24 PM, Allan Engelhardt all...@cybaea.com wrote:
sink(..., type=c(output,message), split=TRUE) at the beginning of
That is exactly what I needed! I dunno why I did not think about it
earlier duuhhh!!!
thanks very much!!!
sapply(modelos, AIC) did the job!
more specifically, (I wanted a dataframe to make comparaisons easy)
k=as.data.frame(sapply(modelos,AIC))
df_results=cbind(k,modelo=rownames(k))
Hi Steve,
I had the same problem when writing the hierobarp function in plotrix.
Have a look at the source code (v2.6-4 in my copy lines 128-133) as the
solution seems to work well.
Jim
__
R-help@r-project.org mailing list
Is there a place that shows how to create two plots that are stacked on top of
each other where they share a common x-axis scale, but have differnt y-axis
scale?
Say have the following data: airquality
Stack plot(airquality$Day, airquality$Wind) on top of plot(airquality$Day,
Hi,
On Aug 3, 2009, at 10:37 PM, Weiwei Shi wrote:
Hi
I am wondering if R or some others provide free-to-use graph mining
tools,
like mining some frequent structure in a x-y plot data?
It sounds like you're looking for a library does frequent subgraph
mining across a graph dataset. I'm
Please consider the following inputs:
PrsnSerialno-c(735,1147,2019,4131,4131,4217,4629,4822,4822,5979,5979,6128,6128,7004,7004,
7004,7004,7004,7438,7438,9402,9402,9402,10115,10115,11605,12693,12693,12693)
Hi Sir
How to get Wakeby distribution curve on L-moment ratio diagram?
Regards
--
AMINA SHAHZADI
Department of Statistics
GC University Lahore, Pakistan.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
dear all,
I got a problem with pattern matching using grep. I extracted a list of
characters from a data frame, and I tried to match this list of characters
to a column from another data frame. In return, I got only one match, but
there should be far more matches. Any ideas what has gone wrong?
R-help,
I get the following error message when trying to connect to an Oracle database
through R (2.8.1) under Linux (Ubuntu 9.04).
channel-odbcConnect(magnus,uid=luisr,pwd=juanayzakarias)
Warning messages:
1: In odbcDriverConnect(st, ...) :
[RODBC] ERROR: state IM002, code 0, message
R-help,
I get the following error message when trying to connect to an Oracle
database
through R (2.8.1) under Linux (Ubuntu 9.04).
channel-odbcConnect(magnus,uid=luisr,pwd=juanayzakarias)
Warning messages:
1: In odbcDriverConnect(st, ...) :
[RODBC] ERROR: state IM002, code 0, message
I would use sshfs or an alternatively remote file system access. Ssh
to your Linux box and then mount the mac os x filesystem via sshfs, or
afs for example. Alternatively, can't you copy the data to the Linux
box using sftp first?
--
Dr. Mark Wardle
Specialist registrar, Neurology
(Sent
The magic I was looking for is to pass as.is=TRUE to sqlQuery of
RODBC.
The reference to read.table is a little oblique, but with that, all
works fine.
An education!
:-)
Thanks much,
Jan
On Tue, 04 Aug 2009 09:05:05 +0200, Peter Dalgaard
p.dalga...@biostat.ku.dk said:
Jan Theodore
On Aug 4, 2009, at 11:16 AM, Rnewbie wrote:
dear all,
I got a problem with pattern matching using grep. I extracted a list
of
characters from a data frame, and I tried to match this list of
characters
to a column from another data frame. In return, I got only one
match, but
there
Dear R users,
I am new user for elastic net. I am trying to use elasticnet
library.
I have marker data with 359 markers and 168
samples, and response is metabolites. I am trying to do regression between
a metabolite and markers.
But i am getting the following error:
Hi,
Trying to setup a logistic regression model. (Something new to me. I
usually use SVM.)
The person explaining the concept explained to me that I can include a
group variable so that the probabilities predicted by the model will
be per group
Does this make sense to anyone? If so, how
On Aug 4, 2009, at 6:33 PM, Noah Silverman wrote:
Hi,
Trying to setup a logistic regression model. (Something new to me. I
usually use SVM.)
The person explaining the concept explained to me that I can include a
group variable so that the probabilities predicted by the model will
be per
Thanks David,
But HOW do I indicate the grouping variable in the formula?
Thanks!
-N
On 8/4/09 3:37 PM, David Winsemius wrote:
On Aug 4, 2009, at 6:33 PM, Noah Silverman wrote:
Hi,
Trying to setup a logistic regression model. (Something new to me. I
usually use SVM.)
The person
On Aug 4, 2009, at 6:38 PM, Noah Silverman wrote:
Thanks David,
But HOW do I indicate the grouping variable in the formula?
Hard to tell. You have told us absolutely nothing about the problem.
Discrete variables cause no problems in formulas. Perhaps one of :
?factor
?cut
?quantile
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