Hi All,
I have done more background research (including Frank's book) so I feel
that my second question is answered. However, as a novice R user I
still have the following problem, accessing the output of predict. So
simplifying my question, using the example provided in the Design
package
As I wrote in my previous email, you need to pick up a methods book that
deals with an introduction to regression analysis.
Using factors in R means using dummy variable coding.
The coefficients estimated in your model using factors indicate, the effect
of teaching.method = 2 in comparison to
results=c(0.31,0.36,0.33)
names(results)=c(y=good,y=better,y=best)
results
names(results)[results==max(results)]
which(names(results)==(names(results)[results==max(results)]))
More generally, however, avoid protected operators in your variable names
(like the equality sign)! Rather choose
On Wed, 12-Aug-2009 at 03:36AM -0700, jorgusch wrote:
|
| First of all, sorry for not giving all information.
|
| Secondly, thanks a lot. This is a real help!! I did not know, that you can
| use names...
| This is really simple and works great!!!
|
| If anyone is close enough to the people
Jonathan R. Blaufuss wrote:
set.seed(1)
Data=rnorm(100,sd=1)
plot(density(Data))
text(25000,0.4,
paste(\u03c3 = ,
format(round(sd(Data),digits=3),big.mark=,)),
font=2, col=blue)
That example gives a latin s in my Windows system. Using font=5 it
Hi All,
I am running a semi-stable algorithms from an R script file using 'source'.
At a certain point one of the algorithms will most probably return an error
and crash the run.
What I would like to do is to make [R] keep running and just skip to the
next command line in the external script
Hi Every one,
My question is I want to do forcasting or predictive analysis on some data
and also genearte any graph based on the analysis. is it possible in R, if
possible please give me the code it is very helpful for me.
Thanks in Advance.
--
View this message in context:
On Thu, 13 Aug 2009 00:26:46 -0700 (PDT) rajclinasia r...@clinasia.com
wrote:
R My question is I want to do forcasting or predictive analysis on
R some data and also genearte any graph based on the analysis. is it
R possible in R, if possible please give me the code it is very
R helpful for me.
In this code i try to calculate le difference between too number for two value
of th variable phase i have did this
(output - read.csv2(C:/RM2Param.csv,sep=,))
OptimYear LRPhase PriorLRPosition OptimPosition
1 2009 -1 1.15641679414676 0.252662968666702
2 2009 -1
On Wed, 12-Aug-2009 at 09:06AM -0700, Jill Hollenbach wrote:
|
| Thanks so much everybody, this has been incredibly helpful--not only is my
| immediate issue solved but I've learned a lot in the process. The lapply
| solution is best for me, as I need flexibility to edit df's with varying
|
On 13/08/09 08:55, Inchallah Yarab wrote:
[...]
for (LRPhase in c(-1,1))
+ {Phase1- output[output[,2]==LRPhase,]}
Phase1- Phase1[order (Phase1[,6]),]
[...]
why when i write for LRPhase in c(1,-1), it gives me the result only for Phase
= 1??
Because you re-assign the Phase1
On Wed, 2009-08-12 at 23:36 -0400, Scott Sherrill-Mix wrote:
I don't really use Word or .wmf but maybe try a high pixel count .png e.g.
png('test.png',height=480*5,width=480*5,res=72*5)
plot(1:10, col = red, bg = grey, pch=21, cex =1.7)
dev.off()
Scott
An EPS is likely to give better
thank you very much Allan it works!!
De : Allan Engelhardt all...@cybaea.com
Cc : r-help@r-project.org
Envoyé le : Jeudi, 13 Août 2009, 10h10mn 14s
Objet : Re: [R] for(variable in [])do
On 13/08/09 08:55, Inchallah Yarab wrote:
[...]
for (LRPhase in
Hi All,
I am running an Rscript with a bunch of algorithms that are UNSTABLE
under some parameter settings.
At a certain point one of them sends error massage and my whole run STOPS!
What I would like is to save the error massage in some file or variable and
carry on to the next command line
Here is an example in pseudo code.
Instead of
Object - function that can generate error
Other things to do
Do something like
Object - try(function that can generate error)
if(class(Object) == try-error){
things to do when an error occures
} else {
other things to do
}
HTH,
Hello,
Â
What function can I use for matrices addition? I couldnât find any
information about it in the manual or in the internet.
(A+B suits, when the number of matrixes is small, function sum() doesnât suit
for matrices addition, because it sums all variables in the matrices and
produces
Hi
I would like to plot the variation of some mean values with time,
and have the standard deviation around the mean shaded on the plot.
I could not find a way to have the shaded area on the curve with the
default R commands,
do I need a special package to do that?
Or any idea of a way with the
Dear all,
I have any problem for my R Program (R.2.8.0).
I want to use Brugs Package, this package has been installed.
But there are error messages :
library(BRugs)
Loading required package: coda
Error: package 'coda' could not be loaded
In addition: Warning messages:
1: package 'BRugs' was
Greetings,
When reading the random forest manual by Liaw, in the examples
set.seed is always used before building a forest.
Does it matter if I don't set the seed?
If I set a different seed manually each time I build a forest, will this
give better randomness?
Thank you all in advance!
--
Hi,
I am trying to import data directly from an excel spreadsheet using the RODBC
package. I am getting the following error messages, wondering if anyone can
help me with it?
connection = odbcConnectExcel('D:\\R files\\TestData.xls')
tables = sqlTables(connection)
tables
TABLE_CAT
Ricardo Rodríguez wrote:
Please, could you give me an example about how to use cat() to read the
value of a variable in a function? Any other way?
I've found how to make it globally available, thus printing it, but I
don't know how to read out the value of any variable within the
Patrick Connolly-4 wrote:
Did you notice that the method creates a dataframe with no rows?
Sure I did, but once data is in R in a proper format, you can create rows
with R tools quite easily. Though, getting first step done, is not always
obvious to me.
Maybe this is a extrem case, but the
Dear R users,
I have a problem in plotting 3 dimensional graph using mixed models.
My model is
sur_prop ~
afr_c+I(afr_c^2)+I(afr_c^3)+byear_c+I(byear_c^2)+I(byear_c^3)+I(byear_c^4)+(1|Studyparish)+afr_c:byear_c
Dear R users,
The TraMineR package for mining, describing and visualizing sequences of
states or events, and more generally discrete sequential data has been
updated to version 1.4.
Many new functionalities have been added, among which: new metrics for
computing distances between sequences,
Dear all,
working with R under Linux, I am not able to install the ncdf-package.
The following appears:
install.packages(ncdf)
Warnung in install.packages(ncdf) :
argument 'lib' is missing: using
'/user/silke/R/x86_64-unknown-linux-gnu-library/2.6'
--- Please select a CRAN mirror for use in
Kurniawati Rahmi wrote:
I have any problem for my R Program (R.2.8.0).
I want to use Brugs Package, this package has been installed.
But there are error messages :
library(BRugs)
Loading required package: coda
Error: package 'coda' could not be loaded
1: package 'BRugs' was
This is a very basic question. I am just wondering if there is a function
where i can choose a vector of points, and them helper lines are drawn.
I am asking because lines seams to be a cumbersome way to do this.
E.g.
x - 1:36
plot(log(x,1.1),xlab=Number of months, ylab=Visits(1000),main=webpage
If your csv file has points, you can read into a data.frame using
df - read.csv(file name)
in the usual way (watch the decimal sign and use read.csv2() if need be),
and coerce to a SpatialPointsDataFrame by saying
coordinates(df) - c(long, lat)
where long, lat are the names of the
Noah Silverman wrote:
Thanks for all the suggestions.
My data was loaded in from a csv file with about 80 columns (3 of these
columns are nominal) no specific settings for the nominal columns.
Currently, if I call svm (e1071), I get an error about the nominal column.
Do I need to tell R to
maram salem wrote:
Dear All,
I'm trying to plot a histogram (with the relative frequencies as the Y axis),
But the scale of the y axis is given by
0e+00, 1e-04, 2e-04, 3e-04,.
Now, I have 2 questions
1- Does (1e-04=0.01831563)?
2- If this true,how can i change the given scale to
Thomas Loridan wrote:
Hi
I would like to plot the variation of some mean values with time,
and have the standard deviation around the mean shaded on the plot.
I could not find a way to have the shaded area on the curve with the
default R commands,
do I need a special package to do that?
Or any
Donald Catanzaro, PhD wrote:
Hi All,
I have done more background research (including Frank's book) so I feel
that my second question is answered. However, as a novice R user I
still have the following problem, accessing the output of predict. So
simplifying my question, using the example
2- If this true,how can i change the given scale to
(0.01,0.03,0.05,0.07,0.09)?
If you want to change the axis tickmarks you can buildt your plot with
yaxt=n and then add an axis with what you want, e.g.
axis(side=2,at=c(0.01,0.03,0.05,0.07,0.09),cex.axis=1,las=2)
Hope this helps. If not
What do you mean without success? Can you provide specifics. They
work fine for me. You need to give details of how you are using it in
your script and what conditions you see that make you think it is not
working.
On Thu, Aug 13, 2009 at 3:21 AM, Nir Shachafnirshac...@gmail.com wrote:
Hi
Scott,
Thanks for your response and insight.
I call what I'm seeing - Not coloring within the lines :)
When using pch 19, 20, or 21, it looks like the fill does no stay within the
perimeter of the circle or properly fill the circle, i.e. some blank area left.
It is demonstrated at the
willow1980 wrote:
Dear R users,
I have a problem in plotting 3 dimensional graph using mixed models.
My model is
sur_prop ~
afr_c+I(afr_c^2)+I(afr_c^3)+byear_c+I(byear_c^2)+I(byear_c^3)+I(byear_c^4)+(1|Studyparish)+afr_c:byear_c
Hanneke Wijnhoven wrote:
Frank,
Thank you for your quick response!
I want to compare the discriminative capacity of different
anthropometric measures in predicting mortality, focussing on the thin
site of these measures.
Since these associations are not linear (U shaped for BMI and inversily
By any chance is there a way to make the lty dashes longer?
Ideally it would work kind of like the following:
plot(-4:4, -4:4, type = n)
abline(-5,-4:4, lty=dashed)
abline(-2,-4:4, lty=longdash) # long dash words (love this)
abline(-4:4,-4:4, lty=longerdash)
I read the lty documentation that
Hi fellas,
I am working on a dataframe cam and it involves comparison within the
2 columns - t1 and t2 on about 20K rows and 14 columns.
###
cap = cam; # this doesn't take long. ~1 secs.
for( i in 1:length(cam$end_date))
{
x1=strptime(cam$end_date[i], %d/%m/%Y);
First of all, do the strptime conversions one time outside the loop.
I would guess that if you ran Rprof on the code, most of the time is
in that routine -- did you run Rprof?
Also you are going through the loop one too many times; your ending
value is 'length(cam$end_date)' and then you are
Update: I could not get RNetCDF working because I couldn't install udunits
version 1 properly, and udunits2 is not the right version.
However, returning to the original post, I *did* get ncdf working. Just
install it from source. Then, you can do as e.g. below
pre
library(ncdf)
jpeg(SSS.jpg,
?par
Look at line type specification:
Line Type Specification
Line types can either be specified by giving an index into a small
built-in table of line types (1 = solid, 2 = dashed, etc, see lty
above) or directly as the lengths of on/off stretches of line. This is
done with a string of an even
On Thu, 2009-08-13 at 04:53 -0700, Jason Rupert wrote:
Scott,
Thanks for your response and insight.
I call what I'm seeing - Not coloring within the lines :)
When using pch 19, 20, or 21, it looks like the fill does no stay
within the perimeter of the circle or properly fill the
Why do you need an explicit loop at all?
(Also, your loop goes over i in 1:length(cam$end_date) but your code refers to
cam$end_date[i+1] --||--!!)
Here is a suggestion. You want to identify places where the date increases but
the volume does not change. OK, where?
ind - with(cam, {
Dear R-users,
I'm encoutering some problems with the qcc()-function. When there are
more than 25 replicates per sample the estimate for the standard
deviation becomes NA, implying that nothing is plotted (error message:
Error in plot.window(...) : need finite 'ylim' values)
On the forum I
Hello!
Using the sink function, output from R may be written to a file
instead of the screen. I would really like to write my output to a
file while running an R script and at the same time view the output
live on my screen. Is there are way to do that?
Thanks,
Michael
--
Michael Knudsen
On Thu, 13 Aug 2009 11:29:40 +0200 Silke Troemel
silke.troe...@uni-bonn.de wrote:
ST
/usr/lib64/gcc/x86_64-suse-linux/4.0.2/../../../../x86_64-suse-linux/bin/ld:
ST /usr/local/lib64/libnetcdf.a(attr.o): relocation R_X86_64_32S
ST against `a local symbol' can not be used when making a shared
ST
See the split argument in ?sink
On Thu, Aug 13, 2009 at 9:01 AM, Michael Knudsenmicknud...@gmail.com wrote:
Hello!
Using the sink function, output from R may be written to a file
instead of the screen. I would really like to write my output to a
file while running an R script and at the same
On Thu, Aug 13, 2009 at 11:35 AM, Lina Rusyteliner...@yahoo.co.uk wrote:
Hi Lina,
What function can I use for matrices addition? I couldn’t find any
information about it in the manual or in the internet.
(A+B suits, when the number of matrixes is small, function sum() doesn’t suit
for
Hi R users,
I'm here trying to understand correlated residuals in nonlinear estimation.
I'm reading/studying the book Bates, D. M. and D. G. Watts, (1988),
/Nonlinear regression analysis and its applications/, Wiley, NY. pages
92-94, trying to reproduce the figures and to find out the code in
Frank, thank you very much for your answer.
Yes, I also estimated splines like you suggested but wanted to add more
custom analyses as well. Your answer does help me however, thanks.
Hanneke
Hanneke Wijnhoven wrote:
Frank,
Thank you for your quick response!
I want to compare the
Dear sir,
I am trying to create a barplot for two propotions, with proportions successful
on the y and age on the x. So my data is in the formate of one vector
containing 0s and 1s (i.e.successful or not) with a corresponding two level
vector of age.
successage
1
I have done some ANOVA tables for some data that I have, from this I can read
the within-group variance. can anyone tell me how i may find out the
between-group variance?
Thanks Emma
--
View this message in context:
If A, B and C are matrices then:
L - list(A, B, C)
Reduce(+, L)
On Thu, Aug 13, 2009 at 5:35 AM, Lina Rusyteliner...@yahoo.co.uk wrote:
Hello,
What function can I use for matrices addition? I couldn’t find any
information about it in the manual or in the internet.
(A+B suits, when the
On Thu, 13 Aug 2009, Mcdonald, Grant wrote:
Dear sir,
I am trying to create a barplot for two propotions, with proportions successful
on the y and age on the x. So my data is in the formate of one vector
containing 0s and 1s (i.e.successful or not) with a corresponding two level
vector
Hi,
Does anyone know of a package/script that will implement the Whittle
(1953) estimator for the parameters of an invertible stationary ARMA
time series model? The estimator is defined on, for example, pg. 378
of Brockwell Davis (1991).
I assume that the internal call .whittle in this code due
Maybe I expect too much from a non compiled language.
Anyway, I wonder whether it is possible in R to set constant values without
using any memory location that would take useless space
bacause such values are not going to be changed along the program. It's just a
way to assign a mnemnic name
Hello,
Great to see the new metafor package for meta-analysis.
I would like to perform a meta-analysis in which I initially calculate the
intercept of the model with a nested random-effects structure. In lme, this
would be
model- lme(v3~1, random=~1|species/study, weights = varFixed(~Wt),
if you set a seed manually, it makes the results reproducible. That is, if
you set a specific seed, your randomForest procedure should produce the
exact same result every time (all others equal). As an example:
set.seed(1234)
rnorm(100)
rnorm(100)
set.seed(4531)
rnorm(100)
rnorm(100)
I'm not sure how to do this in lattice, but here is an option
with ggplot2.
library(ggplot2)
set.seed(123)
# Make sure the data has a variable that indicates
# which group is red and which one is black
DF - data.frame(x = rnorm(10), y = rnorm(10), gr = rep(1:5,
2),endpoint =
Hi,
Someone can explain to me how use Browser and Debug ?
thank you
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hi,
RG Hi,
RG I'm wondering if the following behaviour is normal:
RG setClass('A', representation(number='numeric'), RG
validity=function(object){ RG if( obj...@number -1 )
return(Invalid number); TRUE})
[1] A
RG a - new('A')
RG a
An object of class
This article might help:
http://www.biostat.jhsph.edu/~rpeng/docs/R-debug-tools.pdf
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Inchallah Yarab
Sent: Thursday, August 13, 2009 9:40 AM
To: r-help@r-project.org
Subject: [R]
On Thu, Aug 13, 2009 at 04:05:07PM +0200, mau...@alice.it wrote:
Maybe I expect too much from a non compiled language.
Anyway, I wonder whether it is possible in R to set constant values
without using any memory location that would take useless space
bacause such values are not going to be
The help page of prop.test gives you three references. Isn't it enough?
For example,
Newcombe R.G. (1998) Two-Sided Confidence Intervals for the Single
Proportion: Comparison of Seven Methods. _Statistics in Medicine_
*17*, 857-872.
Newcombe R.G. (1998) Interval Estimation
On Thu, 13 Aug 2009 15:11:03 +0200, Michael Knudsen micknud...@gmail.com
wrote:
On Thu, Aug 13, 2009 at 11:35 AM, Lina Rusyteliner...@yahoo.co.uk
wrote:
Hi Lina,
What function can I use for matrices addition? I couldn’t find any
information about it in the manual or in the internet.
Hello all,
I have a huge data set that I'm cleaning up a bit. I am extracted the
means per condition, but also need to get the n. Strangely enough I am
unable to find a function that could actually pull this off. I am
unable to use replications or count the rows using nrow.
What I am trying to
dcemri 0.10 has been released on CRAN
dcemri is (to the best of my knowledge) the first public-domain software
package for the quantitative analysis of dynamic contrast-enhanced MRI
(DCE-MRI) and diffusion-weighted MRI (DW-MRI or DWI). Data import and
export is availble for ANALYZE or NIfTI
Dear Professor Murdoch,
That is exactly the difficulty for me. I don't know how to make a prediction
with lmer using expand.grid; at the moment, I can use
“mo...@x%*%fixef(model)” to get predicted values for existing observational
data, but not data by expand.grid. Actually, if I know this, I can
From: Mcdonald, Grant
Sent: 13 August 2009 13:08
To: r-help@R-project.org
Subject: R graphics
Dear sir,
I am trying to create a barplot showing propotions,
So my data is in the format of a vector containing 0s and 1s (i.e.successful
or not) with a
We will only be able to help if you provide a reproducible example! I'm sure
this is a simple one-liner, but it's hard to tell from your example what it
should be. The functions table, length, tapply, and/or nrow may play a part
though.
-Original Message-
From:
Dear all,
I used hclust() to generate a dendrogram. After clustering, I wanted to take
the order of the genes for further plotting purposes. Anyone has an idea how
I can reoder my raw gene list as it is shown in the dendrogram?
Thanks in advance.
--
View this message in context:
Magically, the eps version seems to fix the not coloring in the lines issue
observed when using the WMF device - note that the issue was observed when
viewing it on the screen and after printing it out.
However, with eps, the color of the points when using pch 21 appears to stay
within the
You may also want to look at ?TeachingDemos::txtStart as an alternative to
sink, one advantage is that the commands as well as the output can be included.
With a little more work you can also include graphical output into a
transcript file.
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
At points of total desperation you can always consider
the time-honored, avuncular advice -- RTFM,
in this case Section 4.4 of Writing R Extensions.
url:www.econ.uiuc.edu/~rogerRoger Koenker
emailrkoen...@uiuc.eduDepartment of Economics
vox: 217-333-4558
Correct, it is not possible to fix the residual variance to 1 in the R version
of lme(), which is what one (typically) wants to do in meta-analyses, where the
sampling variances are assumed to be (approximately) known. This is however
possible in S-Plus, if you have access to that. Adding:
I'm also a newbie, but I've been getting loads of utility out of the grep
function and it's cousin gsub.
Using asterisks are tricky because * often means anything of any length in
a search pattern (e.g. delete *.* means delete all your files!). To find
the literal * using grep you would need to
Hello all!
Maybe it's a newbie question(in fact I _am_, a newbie), but I hope
you'll find the solution.
I have an equation system which has k equation and n variables (kn).
I would like to obtain a description of the solutions (which can be the
equation of lines or a plane, or everything
On Thu, Aug 13, 2009 at 6:34 AM, willow1980jianghua@shef.ac.uk wrote:
Dear Professor Murdoch,
That is exactly the difficulty for me. I don't know how to make a prediction
with lmer using expand.grid; at the moment, I can use
“mo...@x%*%fixef(model)” to get predicted values for existing
These are date and times in the format MMDDhhmmss. I would like
to take this column and make a chron object form them. I have tried a
couple of the split family of functions but they need character input
here is the data:
date.time - c(19851001001500, 19851001003000, 19851001004500,
Hi!!
I need some help in using the correct required symbol when plotting my DNA
structure using rgl. I need to plot one strand using empty circles and the
other using filled circles and if possible have sequence in the center.
I tried using pch and lty but have not been able to get it to do
Try this:
strptime(date.time, %Y%m%d%H%M%s)
On Thu, Aug 13, 2009 at 1:59 PM, stephen sefick ssef...@gmail.com wrote:
These are date and times in the format MMDDhhmmss. I would like
to take this column and make a chron object form them. I have tried a
couple of the split family of
I'm not sure that I understand your problem but if you want the vector in
character rather than numeric try:
library(Hmisc)
library(Hmisc)
time.date- Cs(19851001001500, 19851001003000, 19851001004500, 1985100101,
19851001011500, 19851001013000, 19851001014500, 1985100102,
On Wed, Aug 12, 2009 at 7:19 AM, am...@xs4all.nl wrote:
Thank you Gerrit,
Your suggestion proved right after all:
This does put error bars (dy) on the points. You only need to figure out
the proper y axis scaling.
xyplot(y~x|f,data=xy,groups=dy,panel=function(x,y,groups,subscripts,...)
?length
--- On Thu, 8/13/09, Dax rienk.doet...@gmail.com wrote:
From: Dax rienk.doet...@gmail.com
Subject: [R] How to get the n (number of observations) per conditional group
To: r-help@r-project.org
Received: Thursday, August 13, 2009, 10:11 AM
Hello all,
I have a huge data set that I'm
I'm using text miner (the tm package) to process large numbers of blog and
message board postings (about 245,000). Does anyone have any advice for how to
efficiently extract the meta data from a corpus of this size?
TM does a great job of using MPI for many functions (e.g. tmMap) which
On Thu, Aug 6, 2009 at 7:27 AM, Kito Palaxoukitopala...@yahoo.com wrote:
Hi all,
I have a data frame like this:
DF - data.frame(x = rnorm(10), y = rnorm(10), gr = rep(1:5, 2))
and I make the following xy-plot:
library(lattice)
xyplot(y ~ x, data = DF, groups = gr, type = b, col = 1)
Try this:
as.chron(date.time, %Y%m%d%H%M%S)
On Thu, Aug 13, 2009 at 12:59 PM, stephen sefickssef...@gmail.com wrote:
These are date and times in the format MMDDhhmmss. I would like
to take this column and make a chron object form them. I have tried a
couple of the split family of
Dear all,
I am analyzing counts of seabirds made from line transects at sea.
I have been fitting Poisson and negative binomial distributions to the data
using the goodfit function from the vcd library. I would also like to
evaluate how well a quasi-poisson distribution fits the data. However,
I have noticed an interesting behavior when comparing how the base
plot() function deals with a data argument that downloads data from the
internet vs. how xyplot() in lattice performs the same task.
The goal is to plot hourly temperature data. The data is downloaded and
formatted for R using
On Thu, 13 Aug 2009, Nigel Harding wrote:
Dear all,
I am analyzing counts of seabirds made from line transects at sea.
I have been fitting Poisson and negative binomial distributions to the data
using the goodfit function from the vcd library. I would also like to
evaluate how well a
Ok, I was able to figure out one part by using rgl.spheres. I am still trying
to insert text using rgl.texts. Does any one have a simple example?
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Nair, Murlidharan T
Sent:
mauede wrote:
Maybe I expect too much from a non compiled language.
Anyway, I wonder whether it is possible in R to set constant values
without using any memory location that would take useless space
bacause such values are not going to be changed along the program. It's
just a way to
I have a set of 52 weekly values, one is the desired high lake stage for
a week, and the other is the desired low lake stage for each week. It
looks like this:
week
High
Low
1
16
14.5
2
16
14.5
3
15.95
14.45
4
15.84
14.34
5
15.73
14.23
6
15.61
14.11
7
15.5
14
8
15.38
Hello All:
I am having the following data file named data.dat
Number of people
Number of pets
Age of trees
ifn - data.dat
dat - read.table(ifn)
colnames(dat)-c(Variables)
I want R to read all these in a string but when I ask R to read these,
it gives me error because there more than one
mauede wrote:
Maybe I expect too much from a non compiled language.
Anyway, I wonder whether it is possible in R to set constant values
without using any memory location that would take useless space
bacause such values are not going to be changed along the program. It's
just a way to
Use readLines indeed.
On Thu, Aug 13, 2009 at 3:21 PM, Mohsen Jafarikia jafari...@gmail.comwrote:
Hello All:
I am having the following data file named data.dat
Number of people
Number of pets
Age of trees
ifn - data.dat
dat - read.table(ifn)
colnames(dat)-c(Variables)
I want R to
mauede wrote:
Maybe I expect too much from a non compiled language.
Anyway, I wonder whether it is possible in R to set constant values
without using any memory location that would take useless space
bacause such values are not going to be changed along the program. It's
just a way to
Hi all,
Can you use the truncreg() function to do point-to-point truncation,
i.e., specify a different point=, for each point in your dataset. I
guess in that sense this would be a nonlinear fit.
Thanks,
Vivek
__
R-help@r-project.org mailing list
mauede wrote:
Maybe I expect too much from a non compiled language.
Anyway, I wonder whether it is possible in R to set constant values
without using any memory location that would take useless space
bacause such values are not going to be changed along the program. It's
just a way to
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