Duncan Murdoch wrote:
What's so hard about leaving an R session running, and using bookmarks
as Dieter described?
It pollutes my space, and I am a Window-closing maniac, so it won't survive
the next attack.
On 01/07/2010 11:36 AM, robert-mcfad...@o2.pl wrote:
Dnia 7 stycznia 2010 11:30 S Devriese sdmaill...@gmail.com napisał(a):
you might try
# open file connection
sink(item1.xml)
# print object
my.matrix
# close file connection
sink()
Unfortunately, It does not code letter
Hi the list,
In the package KmL (new version, not release yet), the main function
seems to work correctly but once in a while, R crash (full crash,
anything link with R is closed and windows ask if it can send a crash
report). More precisely, when I run it in a loop on 1000 data sets, the
Try this:
writeLines(do.call(paste, c(as.data.frame.table(as.matrix(x)), sep = ;)))
On Fri, Jan 8, 2010 at 12:03 AM, sugimoto iey...@sugimoto.at wrote:
Hi all,
I have the following problem:
I have a data frame (actually it is a prop.table) which I want to print as a
list, e.g.:
Liebe Liste,
bin noch absoluter R-Anfänger und trotz fleißigen Lesens der
Dokumentation noch nicht zur Lösung des folgenden Problems vorgedrungen.
Die Werte einer 2D-Matrix sollen in einem einzigen 2D-Plot dargestellt
werden, in dem jeweils für die Werte einer Zeile ein Graph aus mit
Linien
Michal Kulich wrote:
On 7.1.2010 20:22, Duncan Murdoch wrote:
A more useful example than ls() would be methods(). I think it
would be nice to have a list of methods included in the man page for
a generic function, and links to their pages if they have their own
man pages. You might want
Dieter Menne wrote:
Duncan Murdoch wrote:
What's so hard about leaving an R session running, and using bookmarks
as Dieter described?
It pollutes my space, and I am a Window-closing maniac, so it won't survive
the next attack.
Hi, Duncan,
If that works, writing up instructions would be a useful contribution.
It was always a bit of a mess, and after 15 minutes this morning I had to
go. So I hoped someone else would jump the wagon.
Dieter
--
View this message in context:
On 08.01.2010 12:18, Oliver Gondring wrote:
Liebe Liste,
bin noch absoluter R-Anfänger und trotz fleißigen Lesens der
Dokumentation noch nicht zur Lösung des folgenden Problems vorgedrungen.
Die Werte einer 2D-Matrix sollen in einem einzigen 2D-Plot dargestellt
werden, in dem jeweils für die
Hello-
Is it possible to estimate standard errors for a multiple regression model
using a randomization test approach? I have seen a lot on using the
procedure to get a test statistic, but nothing that talks about getting
actual standard errors. Is this possible? How might I do this in R?
Thank
I see. Well, I never lacked any of these capabilities... Please understand
that people who use R to do their work may have different objectives than the
developers - and they form the majority of R users.
Well how about a documentation system that could look back over your
history and notice
Dear list,
Many people seem unhappy with the new documentation server because you
need to have R running to access it, and it's not immediately obvious
how to bookmark references so they work long-term. One solution to
this problem is to have a globally available website that provides
access to
dear R experts---I am using the coef() function to pick off the coefficients
from an lm() object. alas, I also need the standard errors and I need them
fast. I know I can do a summary() on the object and pick them off this
way, but this computes other stuff I do not need. Or, I can compute (X'
Dear all,
I would like to ask if there is a simple was in R to fit the chi-squared
distribution to the empirical data?
Thanks a lot!
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
You can get SE with this:
coef(summary(your_model))[,'Std. Error']
On Fri, Jan 8, 2010 at 11:35 AM, ivo welch ivo...@gmail.com wrote:
dear R experts---I am using the coef() function to pick off the coefficients
from an lm() object. alas, I also need the standard errors and I need them
On 01/08/10 07:15, Hadley Wickham wrote:
Dear list,
Many people seem unhappy with the new documentation server because you
need to have R running to access it, and it's not immediately obvious
how to bookmark references so they work long-term. One solution to
this problem is to have a
From: ivo welch
dear R experts---I am using the coef() function to pick off
the coefficients
from an lm() object. alas, I also need the standard errors
and I need them
fast. I know I can do a summary() on the object and pick
them off this
way, but this computes other stuff I do not
On Fri, 8 Jan 2010 14:39:34 +0100 Trafim Vanishek rdapam...@gmail.com
wrote:
I would like to ask if there is a simple was in R to fit the chi-squared
distribution to the empirical data?
Sure. Use the 'fitdistr' function in the 'MASS' package.
--
Karl Ove Hufthammer
See ?display in the arm package.
On Fri, Jan 8, 2010 at 8:35 AM, ivo welch ivo...@gmail.com wrote:
dear R experts---I am using the coef() function to pick off the coefficients
from an lm() object. alas, I also need the standard errors and I need them
fast. I know I can do a summary() on the
On Fri, 8 Jan 2010 08:41:49 -0500 Jonathan Baron ba...@psych.upenn.edu
wrote:
Many people seem unhappy with the new documentation server because you
need to have R running to access it, and it's not immediately obvious
how to bookmark references so they work long-term. One solution to
Many people seem unhappy with the new documentation server because you
need to have R running to access it, and it's not immediately obvious
how to bookmark references so they work long-term. One solution to
this problem is to have a globally available website that provides
access to all
http://pledgie.com/campaigns/7707 - here you can donate as much or as
little as you like to support this project. You won't pay until the
total amount has been pledged.
I misread the documentation - do you actually pay right away. If I
don't reach the $1000, I'll pass on the money to a good
At 01:18 06/01/2010, rusers.sh wrote:
Hi,
Say i have three functions in a new package, a,b and c. I only want the one
function a to be exported for use. b and c are not very stable.
If i specify to export all the three functions in the NAMESPACE file
(export(a,b,c)), no errors appeared after
Dear All,
I know how to use the boxplot() function to generate a boxplot, but I
would like to (automatically) extract 5 numbers (median and the 4
quantiles) for each column and possibly save them into a convenient format.
Can anyone point me to the right direction? I am sure there must be an
On 8 January 2010 at 08:35, ivo welch wrote:
| dear R experts---I am using the coef() function to pick off the coefficients
| from an lm() object. alas, I also need the standard errors and I need them
| fast. I know I can do a summary() on the object and pick them off this
| way, but this
naive questions---
why is this not part of the standard R distribution? fast regression is
*not* an obscure need.
why would an se() function not be part of the standard R distribution, given
that coef() can be?
naive suggestion to add to the ?lm text
The underlying low level functions,
On Jan 8, 2010, at 9:08 AM, Lorenzo Isella wrote:
Dear All,
I know how to use the boxplot() function to generate a boxplot, but I
would like to (automatically) extract 5 numbers (median and the 4
quantiles) for each column and possibly save them into a convenient
format.
Can anyone point
On 01/08/10 14:56, Karl Ove Hufthammer wrote:
On Fri, 8 Jan 2010 08:41:49 -0500 Jonathan Baron ba...@psych.upenn.edu
wrote:
Many people seem unhappy with the new documentation server because you
need to have R running to access it, and it's not immediately obvious
how to bookmark
I have a nested list l like:
l - list(A=c(1,2,3), B=c(a, b))
l - list(l,l, list(l,l))
I want the list to be unlisted, but not on the lowest level of each
branch.
I want the lowest level of each list branch to remain as it is.
So unlist or unlist(rec=F) do not work here as the level of
On Fri, 8 Jan 2010 10:03:31 -0500 Jonathan Baron ba...@psych.upenn.edu
wrote:
In case anybody is looking for ideas in how to improve the above
site, inclusion of rendered example graphs, similar to the ones at
http://www.metaresearch.de/exlib/;, would be nice.
Why should I bother when
Hi,
I wonder what is a better way to organize a lot of R source files. I have
a lot of utility functions written and store them in several source files
(e.g util1.R, util2.R,..utilN.R). I also have a master file in which the
source command is used to load all the util.R files. When I need to use
Hello again and Happy 2010!
I was looking back at this email because I need to do some additional
processing now. I was thinking that if I take the coef(ans) I get n+1
coefficients. I guess that the coef(ans)[1] is the constant term... Do I
need to add it when I calculate the estimated value for
I am sorry, I just pressed the send button by accident before completing
my e-mail. The yest are the estimated values according to the ridge model.
Is the way that I calculate them correct? Or should I cut the
*+coef(ridge.test)[1]
*term?
Thanks a lot!
Eleni
On Fri, Jan 8, 2010 at 6:16 PM, Eleni
Hello,
I have encountered a problem which may be arising from details of my data and
or the statistics I am trying to do, or may be arising due to the way leaps
works internally. Unfortunately, I am not yet savvy enough to tell why.
I can say that this statement works (or at least works to the
Yes, you need to have the intercept term when you predict model-based
response.
This is what you need:
ridge.test=lm.ridge(tey_values~tedata, lambda)
yest - drop(cbind(1, tedata) %*% coef(ridge.test))
Hope this helps,
Ravi.
Greetings Milton,
Our R-PLUS has features of S-PLUS and we use it to teach and those with
laptops without S-PLUS get R-PLUS.
Get a free trial of R-PLUS at:
www.xlsolutions-corp.com/order
Regards - Sue
Original Message
Subject: Re: [R] February 2010***New R Courses*** by
Thanks a lot!
Eleni
On Fri, Jan 8, 2010 at 6:35 PM, Ravi Varadhan rvarad...@jhmi.edu wrote:
Yes, you need to have the intercept term when you predict model-based
response.
This is what you need:
* ridge.test=lm.ridge(tey_values~tedata, lambda)*
* *
* yest - drop(cbind(1,
Hi Steve,
Thank you very much for your reply. Your code is more readable and obvious than
mine
Could you please help me in these questions?:
1) Formula is an alternative to y parameter in SVM. is it correct?
2) I forgot to remove the class label from the dataset besides I gave
Hello.
Consider the response-variable of data.frame df is constant, so analytically
perfect fit of a linear model is expected. Fitting a regression line using
lm result in residuals, slope and std.errors not exactly zero, which is
acceptable in some way, but errorneous. But if you use summary.lm
Hi all,
How can I get R to change the default precision value? For example:
x=0.9
1-x
[1] 0
Is there a way that I can get a non-zero value using some parameter, or some
package?
many thanks.
[[alternative HTML version deleted]]
Try something about like this:
split(unlist(l), rep(1:length(idx - rapply(l, length)), idx))
On Fri, Jan 8, 2010 at 1:35 PM, Mark Heckmann mark.heckm...@gmx.de wrote:
I have a nested list l like:
l - list(A=c(1,2,3), B=c(a, b))
l - list(l,l, list(l,l))
I want the list to be unlisted, but
Dear all,
I have this directory structure :
Dir1 Dir2 Dir3 Dir4 .
A.xml D.xmlG.xml
B.xml E.xml H.xml
C.xml F.xml I.xml
Within each of these directories (Dir1, Dir2 etc) there are a num of xml
files (A.xml, B.xml
?list.files
?file.info
?setwd
You can get a list of all the files in a directory (list.files) and then do
a file.info to determine which ones are the directories you want to search.
A list.files on that directory will give you the list of file names that you
can then process.
On Fri, Jan 8,
On 08-Jan-10 16:56:25, Paul Evans wrote:
Hi all,
How can I get R to change the default precision value? For example:
x=0.9
1-x
[1] 0
Is there a way that I can get a non-zero value using some parameter,
or some package?
many thanks.
The problem here is that, as far as R
FAQ 7.31
The precision of a floating point number is about 16 digits and your 'x' is
at that limit. If you reduce it, you will see a result:
x=0.9
1-x
[1] 0
print(1-x, digits=20)
[1] 0
x=0.99
print(1-x, digits=20)
[1] 0.00999200722162641
On Fri,
Paul Evans wrote:
How can I get R to change the default precision value? For example:
x=0.9
1-x
[1] 0
Is there a way that I can get a non-zero value using some parameter, or some
package?
many thanks.
The 'gmp' package allows calculation with arbitrary precision rationals
You need to review the assumptions of linear models:
y is assumed to be the realization of a random variable,
not a constant (or, more precisely: there are assumed to
be deviations that are N(0, sigma^2).
If you 'know' that y is a constant, then you have
two options:
1. don't do the regression
See below.
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Ulrich Keller
Sent: Thursday, January 07, 2010 4:32 AM
To: r-help@r-project.org
Subject: [R] Strange behaviour of as.integer()
I have encountered a strange behaviour of as.integer() which
Dear all,
I have a question about how to set arguments in my own function. For
example, I have a function that looks like this:
my.f - function(a = x1, b = x2)
{
x1 = equation 1
x2 = equation 2
x3 = equation 3
y = a + b
}
x1, x2, and x3 are temporary variables (intermediate
On 1/8/2010 1:29 PM, Magnus Torfason wrote:
Paul Evans wrote:
How can I get R to change the default precision value? For example:
x=0.9
1-x
[1] 0
Is there a way that I can get a non-zero value using some parameter,
or some package?
many thanks.
The 'gmp' package allows
When the 'by' function forms subsets, are the rows in the same order as they
are in the original data frame?
For example, I want to use 'by' to calculate cumulative sums of a value 'v'
by date 'd' for different levels of a factor 'f':
Thank you Jens. I will try your solutions and post the solutions/problems I
have.
Cheers
Peter
2010/1/7 Jens Oehlschlägel oehl_l...@gmx.de
Peter,
ff objects are not allowed as subscripts to ff objects. You can take
several routes
1) use bit objects instead of logical or ff logical. This is
Just installed R 2.10.1 in win7 and when I try to run help.start() firefox will
pop up but display an error saying it could not find the url
http://127.0.0.1:16396/doc/html/index.html and that permission is denied.
Has anyone seen this? How can I fix it?
Thanks
daniel
Dear useRs,
How can I, writting the correct greek letter using postscrip or pdf function.
In my figures appears only the first letter (a of alpha, n of nu)
when include the graphs in my .tex doxument. I am using
title( expression(bar(T)(paste(-x,;,alpha))-G(paste(x,;,alpha,,,J
title(
Dear all,
I am a new user of R ;-) (I started three months ago) and I am going very
slow….
I am using lattice and am trying to draw a multipanel figure. The problems
are that I am not able to find out how to:
1. Set the order of the panels.
2. Set the order of the x axes.
:rules:
The codes I
Try this:
my.f - function(a, b) {
x1 - 2 * 3
x2 - 3 / 6
x3 - 4 * 4 / 5 - sqrt(2)
y - get(deparse(substitute(a))) + get(deparse(substitute(b)))
return(y)
}
my.f(x1, x2)
On Fri, Jan 8, 2010 at 4:15 PM, Lisa lisa...@gmail.com wrote:
Dear all,
I have a
Try this:
transform(df, v = unlist(with(df, tapply(v, f, cumsum
On Fri, Jan 8, 2010 at 4:10 PM, Daniel Murphy chiefmur...@gmail.com wrote:
When the 'by' function forms subsets, are the rows in the same order as they
are in the original data frame?
For example, I want to use 'by' to
Hi Mark,
It'll be fixed in the next version of plyr. If you want to fix it
yourself, inspect the source of list_to_dataframe and change the first
data.frame to as.data.frame.
Hadey
On Wed, Jan 6, 2010 at 8:53 AM, Mark Heckmann mark.heckm...@gmx.de wrote:
Hadley,
thanks for the quick reply:
Hey everybody,
I have a problem with the combination of the commands outer() and predict(). I
want to visualize the solutions of a regression modell in a matrix. Therefore I
want to use the command predict for a linear modell as the function inside the
command outer. I've made a small example:
Try this:
outer(x, y, FUN = function(x, y)predict(lm.1, data.frame(x, y)))
On Fri, Jan 8, 2010 at 5:49 PM, Etienne Stockhausen einohr2...@web.de wrote:
Hey everybody,
I have a problem with the combination of the commands outer() and predict().
I want to visualize the solutions of a
Hello,
I am trying to conduct a time series analysis on historic hydrologic data,
but I cannot coerce it into class ts because it does not have regular
sampling intervals (some years have 20 samples, other have 8). Specifically
I am trying to perform a CUSUM or or other step change detection, but
Thank you Kevin. I'm looking forward to trying your function when I get back
to the office.
Jerry Floren
Minnesota Department of Agriculture
Kevin Wright-5 wrote:
Here is a simple function I use. It uses Median +/- 5.2 * MAD. If I
recall, this flags about 1/2000 of values from a true
Karl Ove Hufthammer wrote:
On Fri, 8 Jan 2010 10:03:31 -0500 Jonathan Baron ba...@psych.upenn.edu
wrote:
In case anybody is looking for ideas in how to improve the above
site, inclusion of rendered example graphs, similar to the ones at
http://www.metaresearch.de/exlib/;, would be
The zoo package supports irregularly spaced time series and if your
create a zoo object z from your data then tt - as.ts(z) will give you
a ts object, tt. Since a ts object must be regularly spaced this will
add NAs to ensure that it is.
On Fri, Jan 8, 2010 at 3:05 PM, Erin Hestir
Let's say I have 8 variables and I want to generate all combinations of those
variables (In pairs, threes fours, etc) to run in multiple linear regression.
Is there a built-in function to do that in R?
Or at a minimum, how could I take those variables and generate all possible
combinations.
Try ave:
transform(df, v = ave(v, f, FUN = cumsum))
On Fri, Jan 8, 2010 at 1:10 PM, Daniel Murphy chiefmur...@gmail.com wrote:
When the 'by' function forms subsets, are the rows in the same order as they
are in the original data frame?
For example, I want to use 'by' to calculate cumulative
That's what I want. Thank you so much.
Lisa
Henrique Dallazuanna wrote:
Try this:
my.f - function(a, b) {
x1 - 2 * 3
x2 - 3 / 6
x3 - 4 * 4 / 5 - sqrt(2)
y - get(deparse(substitute(a))) + get(deparse(substitute(b)))
return(y)
}
my.f(x1, x2)
On
?expand.grid
On Fri, Jan 8, 2010 at 3:26 PM, Richardson, Patrick
patrick.richard...@vai.org wrote:
Let's say I have 8 variables and I want to generate all combinations of those
variables (In pairs, threes fours, etc) to run in multiple linear regression.
Is there a built-in function to do
Thanks for the answer.
The situation is that I don't know anything of y a priori. Of course I then
would not do a regression on constant y's, but isn't it a problem of stability
of the algorithm, if I get an adj RSquare of 0.6788 for
a least square fit on this type of data? I think lm should
Just to clarify this point: I don't think the problem is that y is
perfectly fittable, but that it is constant. Since the variance of a
constant is zero, there is no variance to explain.
-Ista
On Fri, Jan 8, 2010 at 2:32 PM, Jan-Henrik Pötter henrik.poet...@gmx.de wrote:
Thanks for the answer.
Let's say that I have a bunch of matrices.
They look like this (pardon using fruit for examples, my actual data tables
are far too enormous):
Matrix1
Apples Oranges Pears
A 5 6 7
B 5 3 4
C 8 9 10
D 11
This will start off sounding very easy, but I think it will be very
complicated.
Let's say that I have a matrix, which shows the number of apples that each
person in a group has.
OriginalMatrix-matrix(c(2,3,5,4,6),nrow=5,ncol=1,byrow=T,dimnames=list(c(Bob,Frank,Joe,Jim,David),c(Apples)))
Type
?rank
in the prompt and look at the ties.method argument.
Best,
Daniel
-
cuncta stricte discussurus
-
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of MRKidd
Sent: Friday,
Dear R family
I have a problem with invertibility in a matrix.
m1 - ar(x, method='mle')
Error in solve.default(res$hessian * length(x)) :
Lapack routine dgesv: system is exactly singular
How could I avoid this problem?
Best
Moohwan
__
On 08-Jan-10 21:09:08, MRKidd wrote:
This will start off sounding very easy, but I think it will be
very complicated.
Let's say that I have a matrix, which shows the number of apples
that each person in a group has.
OriginalMatrix-matrix(c(2,3,5,4,6),nrow=5,ncol=1,byrow=T,
Is this what you want:
x1$names - rownames(x1)
x1
Apples Oranges Pears names
A 5 6 7 A
B 5 3 4 B
C 8 910 C
D 11 1314 D
E 15 3 8 E
F 1 4 5 F
x2$names - rownames(x2)
x2
Apples
On 01/09/2010 12:41 AM, Jonathan Baron wrote:
...
Such a website exists:
http://finzi.psych.upenn.edu
Right near the top is a set of links to (almost) all package
documentation. Duncan Murdoch helped here by including an option to
build static pages in the R source.
There is also a search
Hi,
I'm responding to a post about finding roots of a cubic or quartic equation
non-iteratively. One obviously could create functions using the explicit
algebraic solutions. One post on the subject noted that the square-roots in
those solutions also require iteration, and one post claimed
On Jan 8, 2010, at 3:26 PM, Richardson, Patrick wrote:
Let's say I have 8 variables and I want to generate all combinations
of those variables (In pairs, threes fours, etc) to run in multiple
linear regression. Is there a built-in function to do that in R?
The formula syntax allows that.
Try this. (The second line removes the suffixes in the column names.)
out - merge(x1, x2, by = 0, all = TRUE)[-1]
names(out) - sub(\\..*, , names(out))
out
Apples Oranges Pears Apples Oranges Pears
1 5 6 7 5 3 9
2 5 3 4 3 2 1
3
On Jan 8, 2010, at 4:50 PM, Moohwan Kim wrote:
Dear R family
I have a problem with invertibility in a matrix.
m1 - ar(x, method='mle')
Error in solve.default(res$hessian * length(x)) :
Lapack routine dgesv: system is exactly singular
How could I avoid this problem?
Take out the
Hi
I observed an interesting behavior of R. Can you find where is the bug, or
it is not a bug but made deliberately.
- Hide quoted text -
arr = c();#defined the empty array
a= c(x1, x2);
b = c(y1, y2);
arr = rbind(arr,a);#row bind the first
You need to reread the help for [, specifically the drop argument.
?[
Sarah
On Fri, Jan 8, 2010 at 5:57 PM, Fahim fahim...@gmail.com wrote:
Hi
I observed an interesting behavior of R. Can you find where is the bug, or
it is not a bug but made deliberately.
- Hide quoted text -
arr =
On Jan 8, 2010, at 5:57 PM, Fahim wrote:
Hi
I observed an interesting behavior of R. Can you find where is the
bug, or
it is not a bug but made deliberately.
- Hide quoted text -
arr = c();#defined the empty array
a= c(x1, x2);
b = c(y1, y2);
arr = rbind(arr,a);
Hi,
I would like to estimate a quadratic almost ideal demand system in R which is
estimated usually by nonlinear seemingly unrelated regression. But there is no
such function in R yet but it is readily available in STATA (nlsur), see B. Poi
(2008): Demand-system estimation: Update, Stata
Hi Jeff,
Your request makes a lot of sense. I often modify files in the packages
I maintain, typically by loading the package, then working on a copy of
the function, continually sourcing the new code until it works
correctly, and then checking and building the package. Apart from the
On Fri, Jan 8, 2010 at 10:06 PM, Jim Lemon j...@bitwrit.com.au wrote:
It's not the first time I've said it, but Jonathan Baron's search engine has
always provided answers when my local R help can't. The only change I would
make is to default to searching R functions only.
Another interface to
Hello listers,
Does anybody know how to add text to an xyplot without whipping out
the existing curve?
That's all.
For instance,
Lets say you generate a graph like this
A - data.frame(x = rnorm(100), y = rnorm(100))
xyplot(y ~ x, data = A)
How would you add 'Hello world'?
I tried 6.02E23
On 01/09/2010 05:15 AM, Lisa wrote:
Dear all,
I have a question about how to set arguments in my own function. For
example, I have a function that looks like this:
my.f- function(a = x1, b = x2)
{
x1 = equation 1
x2 = equation 2
x3 = equation 3
y = a + b
}
x1, x2, and x3 are
library(R.utils);
sourceDirectory(myRFiles/, modifiedOnly=TRUE);
See ?sourceDirectory (regardless what the Rd help say, any '...'
argument is passed to sourceTo()).
/Henrik
On Fri, Jan 8, 2010 at 7:38 AM, Hao Cen h...@andrew.cmu.edu wrote:
Hi,
I wonder what is a better way to organize a lot
On 2010.01.08 19:44:39, Ivan Gregoretti wrote:
Hello listers,
Does anybody know how to add text to an xyplot without whipping out
the existing curve?
That's all.
For instance,
Lets say you generate a graph like this
A - data.frame(x = rnorm(100), y = rnorm(100))
xyplot(y ~ x, data
On Jan 8, 2010, at 8:10 PM, Jason Morgan wrote:
On 2010.01.08 19:44:39, Ivan Gregoretti wrote:
Hello listers,
Does anybody know how to add text to an xyplot without whipping out
the existing curve?
That's all.
For instance,
Lets say you generate a graph like this
A - data.frame(x =
Thank you. It works.
Ivan
Ivan Gregoretti, PhD
National Institute of Diabetes and Digestive and Kidney Diseases
National Institutes of Health
5 Memorial Dr, Building 5, Room 205.
Bethesda, MD 20892. USA.
On Fri, Jan 8, 2010 at 8:13 PM, David Winsemius dwinsem...@comcast.net wrote:
On Jan 8,
Hi i want do a line graph.
My y axis contains numeric values. My x axis contains non numeric
statements.
This is what i want the graph to look like.
When i try to plot this graph on R it comes up with the following error
message:
Error in plot.window(...) : need finite 'xlim' values
In
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