On 09/10/2013 10:37, Milan Bouchet-Valat wrote:
Le mardi 08 octobre 2013 à 16:02 -0700, Ira Sharenow a écrit :
A colleague is sending me quite a few files that have been saved with MS
SQL Server 2005. I am using R 2.15.1 on Windows 7.
I am trying to read in the files using standard techniques.
Sounds like you want a 95% binomial confidence interval:
binom.test(N, P)
will compute this for you, and you can get the bounds directly with
binom.test(N, P)$conf.int
Actually, binom.test computes a two-sided confidence interval, which
corresponds roughly to 2.5 and 97.5
Dear Ryan,
On 9 October 2013 21:26, Ryan Morrison ryan.r.morri...@me.com wrote:
I'm attempting to use the bnlearn package to calculate conditional
probabilities, and
I'm running into a problem when the cpquery function is used within a loop.
I've
created an example, shown below, using data
On Wed, Oct 9, 2013 at 12:37 PM, Bert Gunter gunter.ber...@gene.com wrote:
Probably not. I would guess that most (or all) of us have no clue what
bisecting a k-means algorithm means. You might have more luck if you
explain yourself more clearly (but probably not from me in any case).
Is this
On 10.10.2013 04:04, Jeffrey Flint wrote:
Uwe,
Good news. I installed 3.0.2, and the parallel package examples ran
successfully. This time a firewall window popped up. Probably the
firewall was the problem with the snow package too, but for some reason the
window didn't pop up with the snow
Dear all
I have data related to cell count across time in 2 different types of
cells. I have transformed the count data using a log
and I want to test the H0: B cell_ttype1=Bcell_type2 across time
for that I am fitting the following model
Dear R Community,
I have the following Problem. I use foreach nested loops, which then return
a list of lists. E.g.:
[[1]]
[[1]][[1]]
Output
[[1]][[2]]
Output
[[1]][[3]]
Output
[[2]]
[[2]][[1]]
Output
What I want to achieve is a single layer list, i.e. a list in which
[[1]][[1]] becomes
On 10 Oct 2013, at 13:17, ivan i.pet...@gmail.com wrote:
test - foreach(i = 1:3) %:%
foreach (j = 1:3) %do% {
paste(i,j,sep=,)
}
Not easily reproducible, unless you write
#install.packages(foreach)
require(foreach)
in front of your code.
Here is
foo - as.numeric(as.character(your_factors) ).
It's a common mistake to forget the first conversion, in which case you end
up with an integer sequence rather than the desired values.
--
View this message in context:
FMRPROG wrote
I am generating random numbers from a normal distribution using
[snip]
I need to optimize the speed WITHOUT using the rnorm function but have no
idea how to do this. I assume I should minimise what goes in the loop?
Any help would be very much appreciated.
Looks like
Hi,
I have two integers a and b (with ab), as well as a function f(x). Is there
a way of getting the vector (f(a), ..., f(b)) from R without having to
explicitly write it out? as my a and b vary.
Thanks for your help
lt;/quote
What did you try?Further, without knowing what your function
Jeffrey Flint wrote
Good news. I installed 3.0.2, and the parallel package examples ran
successfully. This time a firewall window popped up. Probably the
firewall was the problem with the snow package too, but for some reason
the
window didn't pop up with the snow package.
Thanks for the
Perhaps you are looking for the effects package, which can plot effects
(predicted values) for terms in mer objects from lme4?
library(effects)
?effect
library(lme4)
data(cake, package=lme4)
fm1 - lmer(angle ~ recipe * temperature + (1|recipe:replicate), cake,
REML = FALSE)
Hi,
It is not clear whether all the variables are factor or only a few are..
dat- read.table(text=a coef coef.l
coef.h
1 1 0.005657825001254 0.00300612956318132 0.00830952043932667
2 2 0.00634505314577229 0.00334102345418614 0.00934908283735844
3
data.matrix() should do the job for you
Charles
On Thu, Oct 10, 2013 at 8:02 AM, arun smartpink...@yahoo.com wrote:
Hi,
It is not clear whether all the variables are factor or only a few are..
dat- read.table(text=acoef
coef.l coef.h
1 1 0.005657825001254
I wanted to provide a follow-up post regarding the question of the coxme
program and nested (multilevel) frailty analysis. As it turns out, my
failure to produce results was a result of my own error. The following
syntax seems to successfully produce results for a model accounting for both
I'm not honestly sure why data.matrix didn't work off hand. Perhaps
another user can shed some light on this. An alternative is the following:
apply(dat, 2, FUN = function(x) as.numeric(as.character(x)))
On Thu, Oct 10, 2013 at 8:26 AM, arun smartpink...@yahoo.com wrote:
Did you mean to
Firstly, please make sure to reply-all so the r-help list also receives
these emails.
Second, I have just run this sequence as it provides an exact copy with
each as numeric. Use the apply function, it iterates over each column and
converts each to numeric.
dat - read.table(text=a
Dear all,
I have an R script that uses Rcpp, and I have been trying to parallelize
it using mclapply (I tried with the multicore and the parallel library)
Sometimes (not always, interestingly), the CPU use for each core drops,
usually so that the total over all cores reaches 100%, i.e., as fast
Hi,
I have trying to run a simple MR program using rmr2 in a single node
Hadoop cluster. Here is the environment for the setup
Ubuntu 12.04 (32 bit)
R (Ubuntu comes with 2.14.1, so updated to 3.0.2)
Installed the latest rmr2 and rhdfs from
Also, BTW, dat.num() is matrix, but if you use lapply(), it is still a
dataframe. Anyway, it depends on what the OP really wants as output.
dat.num - apply(dat, 2, FUN = function(x) as.numeric(as.character(x)))
dat[] - lapply(dat,function(x) as.numeric(as.character(x)))
str(dat)
I would bet that you are doing something in C++ that shares some resource
between the workers and blocks all but one worker at a time.
---
Jeff NewmillerThe . . Go Live...
my data are matrix with 3 numeric columns.
would like to have pairs plot
with scatterplots in the upper
with hist at the diag
and with correlation at the lower.
actually default pairs does almost what I want but looks semi awesome.
Especially, i didn't find out how to remove the axes from the
Hi All,
I'm trying to edit a file in place using system2 and sed from within R.
I can get my command to work unless there is a backslash in the command
in which case I'm warned about an unrecognized escape. So, for example:
system2(sed -i s/oldword/newword/g d:/junk/x/test.tex) # works fine
Hi,
Sorry to bother you again.
I tried doing regressions using lme (because i want p-values) and ran
across two issues.
*(1) about model specification:*
this is a mixed model. i tried two model specifications:
(a) specify that subjectID (subj) is nested within the between-subject
variable
Dear Jeff,
I had suspected something along those lines initially, however, as I had
stated, this only happens sometimes ...
Here is a partial top showing two of my calls:
17404 sophie20 0 12.4g 11g 1996 R 100 4.6 5:50.11 R
17405 sophie20 0 12.4g 11g 2016 R 100 4.6 5:49.86
Hi,
I have recently installed R and am trying to do some work on it. To be honest
I'm finding it a PAIN to you. I use Mac and I can open stata dta. files in R
despite using the commands suggested to me and I have been trying to get figure
out how to do reduced rank regression on it and the
Hi,
Thank you for your answers, I'm not completely sure if it's to bino.test I need
or the uniroot. Perhaps I should explain more the idea behind the code and the
actual task I'm trying to do. The idea is to calculate a confidence interval as
to the age of two DNA sequences which have
I cannot imagine how the calling process will affect this. If you want further
help I think you will need to provide a reproducible example and info as
requested by the Posting Guide.
---
Jeff Newmiller
On Thu, Oct 10, 2013 at 11:09 AM, Mash Hamid mxh...@bham.ac.uk wrote:
Hi,
I have recently installed R and am trying to do some work on it. To be honest
I'm finding it a PAIN to you.
To me?
I use Mac and I can open stata dta. files in R
Great, glad to hear it's working!
despite
I'm studying the calibration function in the survey package in preparation
for raking some survey data. Results from the rake function below agree
with other sources. When I run calibrate, I get a warning message and the M
and F weights seem to be reversed. Even allowing for that, the deviation
Hi,
I'm looking for an R function/package that will let me solve problems of the
type:
13 = 2^x + 3^x.
The answer to this example is x = 2, but I'm looking for solutions when x
isn't so easily determined. Looking around, it seems that there is no
algebraic solution for x, unless I'm mistaken.
Hello,
# I am able to
install.packages(gstat)
#but when I try to upload I get an error message
library(gstat)
#Error in loadNamespace(j - i[[1L]], c(lib.loc, .libPaths()), versionCheck
= vI[[j]]) :
# there is no package called intervals
#In addition: Warning message:
#package gstat was built
Hello,
I'm using R version 3.0.0 on a mac. I'm having trouble getting order to
behave as I expect it should. I'm trying to sort a data.frame according to
a character vector. I'm able to sort the data.frame, but it retruns an
unexpected result. I have no idea where the order that is being produced
On 10/10/2013 12:00 PM, Karl Fetter wrote:
Hello,
I'm using R version 3.0.0 on a mac. I'm having trouble getting order to
behave as I expect it should. I'm trying to sort a data.frame according to
a character vector. I'm able to sort the data.frame, but it retruns an
unexpected result. I have
On 10/10/2013 2:39 PM, Ken Takagi wrote:
Hi,
I'm looking for an R function/package that will let me solve problems of the
type:
13 = 2^x + 3^x.
The answer to this example is x = 2, but I'm looking for solutions when x
isn't so easily determined. Looking around, it seems that there is no
On 10-10-2013, at 20:39, Ken Takagi katak...@bu.edu wrote:
Hi,
I'm looking for an R function/package that will let me solve problems of the
type:
13 = 2^x + 3^x.
The answer to this example is x = 2, but I'm looking for solutions when x
isn't so easily determined. Looking around, it
Thanks! That's just what I needed.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
?uniroot
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#..
Hi everyone,
I'd like to report a similar experience. When I attempt to run the first
CFA example in bootSem(), specifically the line:
system.time(boot.cnes - bootSem(sem.cnes, R=100, Cov=hcor, data=CNES))
R crashes and I get a notice about X11. I copied my sessionInfo() below.
Any ideas
Hi everyone,
I am hoping someone can help with my attempted use of the expression
function. I have a long series of text and variable to paste together
including a degree symbol. The text is to be placed on my scatter plot
using the mtext function.
Using expression like this:
changetext =
Simona,
You need to install the dependencies:
install.packages(gstat,dependencies=T)
Tom
On Thu, Oct 10, 2013 at 11:58 AM, Simona Augyte simona.aug...@uconn.eduwrote:
Hello,
# I am able to
install.packages(gstat)
#but when I try to upload I get an error message
library(gstat)
#Error in
Revolution Analytics staff write about R every weekday at the Revolutions blog:
http://blog.revolutionanalytics.com
and every month I post a summary of articles from the previous month
of particular interest to readers of r-help.
In case you missed them, here are some articles related to R from
Hi everyone,
I am hoping someone can help with my attempted use of the expression
function. I have a long series of text and variable to paste together
including a degree symbol. The text is to be placed on my scatter plot
using the mtext function.
Using expression like this:
changetext =
Hi,
I have trying to run a simple MR program using rmr2 in a single node
Hadoop cluster. Here is the environment for the setup
Ubuntu 12.04 (32 bit)
R (Ubuntu comes with 2.14.1, so updated to 3.0.2)
Installed the latest rmr2 and rhdfs from
On 10/11/2013 02:01 AM, Witold E Wolski wrote:
my data are matrix with 3 numeric columns.
would like to have pairs plot
with scatterplots in the upper
with hist at the diag
and with correlation at the lower.
actually default pairs does almost what I want but looks semi awesome.
Especially, i
Fantastic - once again, thanks Arun - your knowledge is very impressive!
Ben Gillespie, Research Postgraduate
o---o
School of Geography, University of Leeds, Leeds, LS2 9JT
changetext = expression(paste(Change from ,mini, to , maxi, :,
diff ,degree,C,collapse=))
does not evaluate my user defined variables - mini,maxi, and diff -
just printing them out as words
bquote() can do it: put the variables which should be evaluated in .(). E.g.,
mini - 13
maxi
Wow, that really sounds terrible. Is someone making you use R? For my tasks it
is generally an improvement over other tools. Sometimes it can be a bit
puzzling, but often the result works more reliably and it gives me warnings
when my data are messed up. If you have a better tool for your work,
Hi all,
I hope you can help with this one!
I have a dataframe: 'df' that consists of a vector of times: 'dt2' and a vector
of group id's: 'group':
dates2=rep(01/02/13,times=8)
times2=c(12:00:00,12:30:00,12:45:00,13:15:00,13:30:00,14:00:00,14:45:00,17:30:00)
y =paste(dates2, times2)
Hi,
I solved the crashing issue by removing references to tclck. Here is a gist
that shows the edits: https://gist.github.com/ericpgreen/6926595
However, I am getting an error about convergence failures:
Error in bootSem2(sem.cnes, R = 100, Cov = hcor, data = CNES) :
more than 10
Hi all,
We know that Hermite polynomial is for
Gaussian, Laguerre polynomial for Exponential
distribution, Legendre polynomial for uniform
distribution, Jacobi polynomial for Beta distribution. Does anyone know
which kind of polynomial deals with the log-normal, Students t, Inverse
gamma and
On 10/10/2013 5:02 PM, Marino David wrote:
Hi all,
We know that Hermite polynomial is for
Gaussian, Laguerre polynomial for Exponential
distribution, Legendre polynomial for uniform
distribution, Jacobi polynomial for Beta distribution. Does anyone know
which kind of polynomial deals with
p.s. Orthogonal polynomials can be defined for any probability
distribution on the real line, discrete, continuous, or otherwise, as
described in the Wikipedia article on orthogonal polynomials.
On 10/10/2013 5:02 PM, Marino David wrote:
Hi all,
We know that Hermite polynomial is for
Thanks so much for your response. BTW, do you know any Gauss quadrature R
package can deal with the arbitary PDF?
Thank you!
David
2013/10/11 Spencer Graves spencer.gra...@structuremonitoring.com
p.s. Orthogonal polynomials can be defined for any probability
distribution on the real line,
It is mysterious to me why the procedure proposed by Stefan Evert works.
It appears to work --- once you modify the call to binom.test() to have the
correct syntax. In a sequence of 1000 trials with random values of N, x,
and p0, the answers from Evert's procedure agreed with the answer given
Hi Ben,
I would look into ?findInterval() or ?cut() for an easier solution.
indx- match(df[,1],as.POSIXct(dt))
indx2- unique(df[,2])
lst1- lapply(split(indx,((seq_along(indx)-1)%/%2)+1),function(x) seq(x[1],
x[2]))
res - unlist(lapply(seq_along(lst1),function(i) {
I've figured it out. It ***is*** obvious why Evert's procedure works.
Once you hold your head at the correct angle, as my first year calculus
lecturer
used to say.
The binom.test() confidence interval gives you the value of a random
variable
say U (for upper) such that
Pr(U p) = p0
On Oct 10, 2013, at 3:44 AM, Andreia Fonseca wrote:
Dear all
I have data related to cell count across time in 2 different types of
cells. I have transformed the count data using a log
and I want to test the H0: B cell_ttype1=Bcell_type2 across time
for that I am fitting the following
Hi All,
I have a huge data set with the following type;
city year sex obs
1 1990 M 25
1 1990 F 32
1 1991 M 15
1 1991 F 22
2 1990 M 42
2 1990 F 36
2 1991 M 12
2 1991 F 16
I want to calculate the percentage of M and F by city, year and
## I would use the likert function in the HH package
## if necessary
## install.packages(HH)
## install.packages(reshape)
library(HH)
library(reshape)
pop - read.table(header=TRUE, text=
city year sex obs
1 1990 M 25
1 1990 F 32
1 1991 M 15
1 1991 F 22
2
This is better for plotting the percents
likert(city ~ F + M | year, data=popwide, as.percent=noRightAxis,
main=F M population by city within year)
likert(year ~ F + M | city, data=popwide, as.percent=noRightAxis,
main=F M population by year within city)
We can also plot the
Hi,
May be:
dat1- read.table(text=city year sex obs
1 1990 M 25
1 1990 F 32
1 1991 M 15
1 1991 F 22
2 1990 M 42
2 1990 F 36
2 1991 M 12
2 1991 F 16,sep=,header=TRUE,stringsAsFactors=FALSE)
library(plyr)
#by city
d1 -
Lars Bishop skrev 2013-10-05 22:17:
Hello,
I'm trying to get familiar with the coin package for doing
permutation tests. I'm not sure I understand the documentation
regarding the difference between distribution = asymptotic and
approximate in the function independence_test.
The use of
I am updating a package that works previously under R.2.15.x on a Windows OS.
When I build and run the package with R.3.0.2. I receive an error message
like the following: C_call_dqags not available for .External() for package
stats
How can compiled C (or Fortran) routines from package stats
Thanks very much! bquote() did the trick!
on Thu, Oct 10, 2013 at 6:19 PM, William Dunlap wdun...@tibco.com wrote:
changetext = expression(paste(Change from ,mini, to , maxi, :,
diff ,degree,C,collapse=))
does not evaluate my user defined variables - mini,maxi, and diff -
just printing them
Thanks for the suggestion. From R version 3.0.2, I tried
testDF7 =iconv(x = test07 , from = UCS-2, to = )
Encoding(testDF7)
[1] unknown
testDF7[1:6]
[1] NA NA NA NA NA NA
So using UCS-2 produced the same results as before.
I do not think there are any NA values. I cleaned up the csv
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