Hi to everyone!
I need to plot a box plot but I don't have the original data, is it possible to
make it just with the median, mean, sd and range of values?
Any idea is welcome.
Thanks in advance.
__
Hi to everyone
To simulate data I only know this command:
rnorm(n , mean, sd)
It exists another way to specify Median and range as well?
The point is that I have this information about the variable:
Median: 4.3
Mean: 4.2
SD: 1.8
Range: 0-8
and I need a boxplot, but I don't have the
On 04/04/2014 05:36 PM, Mª Teresa Martinez Soriano wrote:
Hi to everyone!
I need to plot a box plot but I don't have the original data, is it possible to
make it just with the median, mean, sd and range of values?
Any idea is welcome.
Hi Teresa,
You can get the return value from the boxplot
On 03/04/2014 16:26, Frances Cheesman wrote:
Hi all,
I have a number of bacterial growth curves I would like to find the
equations for these and then integrate them to find the area under the
curves for me to do stats on later.
Is there any way I can do this in R?
Thanks,
Frances
I would like to announce the release of version 0.1.1 of the rDVR package
on CRAN. rDVR is an R package that allows cross Platform (Lin/Win/OSx)
video recording from R. It is light weight and allows up to 10 minutes of
recording by default.
rDVR has a project page at
Thanks everyone for al your help, I don't think it's necessarily as easy as
I first thought.
I'm going to have a think about it and try some things out. And I'll be
back if I get stuck!
Thanks very much,
Frances
On 4 April 2014 09:11, Keith Jewell keith.jew...@campdenbri.co.uk wrote:
On
Hi Teresa
Try this:
Median - 4.3
Mean - 4.2
SD - 1.8
RangeLower - 0
RangeUpper - 8
par(mfcol = c(1,2))
(bpstats - boxplot(rnorm(100, mean = Mean, sd = SD), outl = FALSE))
## assuming normality of original data since we don't know the distribution
## get the 25% and 75% quantile
q25 -
Dear Nicholas,
On Fri, 4 Apr 2014 04:59:09 +
nicholas.suraw...@csiro.au wrote:
Greetings,
I'm interested in performing some post hoc tests after conducting a
multivariate analysis of covariance (MANCOVA) which I performed using the
Anova function in the car package. The covariate did
dear sir
i want to simulate multivariate ordinal data matrix with categories (1,4)
and n=1000 and p=10.
thanks alot
thanoon
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Hi,
I have a list of cities and their coordinates, and also for each city I have
a variable varA which I want to represent in a map using ggplot.
For example :
CityA lat 22.93977 lon 46.70663varA 545
CityB lat 23.93977 lon 46.70663varA 122
VarA values begin from 0 to 3000.
I
Hi everyone!
I am trying to make two log-normal AR(0,1) model using R with a given
correlation between them, \rho, on the form:
X_t = \alpha X_{t-1} + a_t
Y_t = \beta Y_{t-1} + b_t
At the moment I have been making n values of correlated log-normal data,
called a_t and b_t, and generated a
Dear R listserve,
I am writing with the hope or receiving assistance using the MICE package.My
troubles relate to post-processing imputations. I am attempting to impute
variables for which I want to specify two conditions using post-processing
imputation: 1) if the value of a variable
Dear R-users,
I'm working on datasets which contain data from the years 1960 to 2100 with a
timestep of one hour. Every year has 365 days, leap years are ignored.
After reading the dataset with R I convert the column which contains date/time
to POSIXct:
as.POSIXct(strptime(MyData [,1],
Hi Thanoon,
How about this?
# replicate p=10 times random sampling n=1000 from a vector containing your
ordinal categories (1,2,3,4)
R - replicate(10, sample(as.vector(seq(4)), 1000, replace = T))
Cheers,
Charles
On Fri, Apr 4, 2014 at 7:10 AM, thanoon younis
thanoon.youni...@gmail.comwrote:
high probability you are in a daylight savings time problem. see the archives
for repair strategies. probably it will be enforcing standard time on all
measurements.
Rich
Sent from my iPhone
On Apr 4, 2014, at 10:55, Winkler, Matthias
matthias.wink...@ibp.fraunhofer.de wrote:
Dear
On 04/04/2014 10:55 AM, Winkler, Matthias wrote:
Dear R-users,
I'm working on datasets which contain data from the years 1960 to 2100 with a
timestep of one hour. Every year has 365 days, leap years are ignored.
After reading the dataset with R I convert the column which contains date/time
to
I just noticed this annoyance, but I'm not the first one, apparently
-- see
http://lists.r-forge.r-project.org/pipermail/datatable-help/2012-May/001176.html
The thread never answered the OP's question Is this a bug? so I
assume the answer, unfortunately, is No.
If not a bug, do users of within
On 04/04/2014 1:32 PM, Dan Murphy wrote:
I just noticed this annoyance, but I'm not the first one, apparently
-- see
http://lists.r-forge.r-project.org/pipermail/datatable-help/2012-May/001176.html
The thread never answered the OP's question Is this a bug? so I
assume the answer,
Hi,
I have some problems using the par function: I want to split the screen into 2
rows and 4 col and I type par(mfrow=c(2, 4)) but when I do that, instead of
setting a graphical parameter, it creates a white Quarz.
I'm currently using the R base version for Mac Os, 3.0.3 .
Could you give me
Dear useRs,
I have a matrix of 120 row and 1000 columns.What I want is to get an average of
a set of 12 rows starting from 1 till 120 for each column. Precisely, for
column 1 the average of 1:10 rows, 11:20 rows 111:120. similarly for column
2, 3, 4 1000. So in the end i should have a
1. Look into the ggmap package if you want to overlay your data onto a map.
2. Re your color scale representation, define 'appropriately'. Do you
mean a continuous range expressible in a colorbar or a discrete range,
and if the latter, what intervals did you have in mind?
Dennis
On Fri, Apr 4,
Revolution Analytics staff write about R every weekday at the Revolutions blog:
http://blog.revolutionanalytics.com
and every month I post a summary of articles from the previous month
of particular interest to readers of r-help.
In case you missed them, here are some articles related to R from
Hi,
re:
I have some problems using the par function: I want to split the screen into
2 rows and 4 col and I type par(mfrow=c(2, 4)) but when I do that,
instead of setting a graphical parameter, it creates a white Quarz.
I'm currently using the R base version for Mac Os, 3.0.3 .
Could
Something like (only 20 columns here):
x - matrix(rnorm(120*20), 120, 20)
xagg - aggregate(x, list(rep(1:12, each=10)), mean)
-
David L Carlson
Department of Anthropology
Texas AM University
College Station, TX 77840-4352
Original Message-
From:
Hi,
I am doing an experiment which results different colors of different
intensities in the 384 micro titer plate.
I took a picture of the plate by scanning in the image as a jpeg file and
now I want to
1. read in the image file
2. grid the content
3. need to extract the intensity and color of
Hello,
Try the following.
m - 120
n - 10 # in your case this is 1000
mat - matrix(rnorm(n*m), nrow = m)
fun - function(x, na.rm = TRUE){
tapply(x, rep(1:12, each = 10), mean, na.rm = na.rm)
}
apply(mat, 2, fun)
apply(mat, 2, fun, na.rm = FALSE) # alternative
Hope this helps,
Rui
Dear All,
I am using R3.0.3 and rsm 2.04. Since I want do log transformation on my
data, so I want change annotation of Slice at ... For example, I want
change (Slice at W = 1.25, L=2) in the first graph into (Slice at W =
log(1.25), L=log(2)). Can anyone tell me how can I change it?
Thanks
On Apr 4, 2014, at 9:54 AM, Duncan Murdoch wrote:
On 04/04/2014 10:55 AM, Winkler, Matthias wrote:
Dear R-users,
I'm working on datasets which contain data from the years 1960 to 2100 with
a timestep of one hour. Every year has 365 days, leap years are ignored.
After reading the dataset
Dear David and Rui,
Thankyou very much. :D
Eliza
From: dcarl...@tamu.edu
To: eliza_bo...@hotmail.com; r-help@r-project.org
Subject: RE: [R] average of rows of each column
Date: Fri, 4 Apr 2014 15:14:32 -0500
Something like (only 20 columns here):
x - matrix(rnorm(120*20), 120, 20)
xagg
Hi,
I'm writing a thesis in Latex (say master.tex). I'd like to include R
code/results from an .Rwd file. I've naively tried:
1) Add ONLY the code below in Rcode.Rnw file:
\section{Exploratory data analysis}
eval=TRUE, echo=FALSE=
library(ggplot2)
data(diamonds)
head(diamonds)
@
2) Then, in
On 04/04/2014, 7:10 PM, Axel Urbiz wrote:
Hi,
I'm writing a thesis in Latex (say master.tex). I'd like to include R
code/results from an .Rwd file. I've naively tried:
1) Add ONLY the code below in Rcode.Rnw file:
\section{Exploratory data analysis}
eval=TRUE, echo=FALSE=
library(ggplot2)
Hello expert community.
Is there anybody whose used rehh package for iHS and rsb. I have gone through
the tutorial a dozen times, I need expert help to enable me apply it to my
p.falciparum snp data from the illumina platform.
Thanks
James Abugri
--
* The information contained in this email
djmuseR wrote
Do you mean a continuous range expressible in a colorbar or a discrete
range,
and if the latter, what intervals did you have in mind?
I mean diskrete values like : 54508 25 101 420 95 928 24
1656 108 18 213 70.
The problem is that range is from 0-4000
Hello,
I have a data set with many individuals all with multiple timed
observations, and I would like to subset the data to exclude later timed
observations.
However, I would like to exclude different amounts of data for each
individual. These individuals have two types of data: DV and dose. What
On Apr 4, 2014, at 11:46 PM, James Abugri wrote:
Hello expert community.
Is there anybody whose used rehh package for iHS and rsb. I have gone through
the tutorial a dozen times, I need expert help to enable me apply it to my
p.falciparum snp data from the illumina platform.
This sounds
Hi,
Check if this works:
n - 1e7
dat - data.frame(Col1=c(A, , B,C, ,,D,rep('',n)),
stringsAsFactors=FALSE)
dat2 - dat
dat[dat==''] - NA
which(dat$Col1=='')
#integer(0)
#or
dat2$Col1[dat2$Col1==''] - NA
which(dat2$Col1=='')
#integer(0)
A.K.
On Wednesday, April 2, 2014 2:20 PM, arun
Hi,
I have daily data arranged by date and site. Keeping the number of columns as
there are, I will like to aggregate (FUN=mean) from daily to monthly the
following data (only part is shown here) which starts in 1971 and ends in 1980.
Year Month Day Site Sim001 Sim002 Sim003 Sim004
1 1971
You have been around long enough that we should not have to tell you how to
provide data in a reproducible manner... read ?dput.
---
Jeff NewmillerThe . . Go Live...
Hi,
I have daily data arranged by date and site. Keeping the number of columns as
there are, I will like to aggregate (FUN=mean) from daily to monthly the
following data (only part is shown here) which starts in 1971 and ends in 1980.
structure(list(Year = c(1971, 1971, 1971, 1971, 1971,
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