There is some sort of radiation coming out of Rossi's Mouse reactor that
stimulates the unpowered Cat reactors. Maybe pions and muons... how can we
tell now that MDMP has a reactor that maybe is functional at a Mouse level
COP of 1.2

On Mon, Feb 29, 2016 at 12:05 AM, Jones Beene <jone...@pacbell.net> wrote:

> Bob,
>
>
>
> Isn’t the reality check that eliminating a cosmic ray contribution means
> the expected gamma counts are going to be too low to impress anyone?
> However, I am very glad you are going to the trouble – if you also test for
> radiation (all types) with and without the enclosure, and then compare the
> two. Without both, the benefits of a cave alone are small.
>
>
>
> BTW - a PNNL study I ran across says that the best material to shield
> against cosmic-ray components is iron, which has the best combination of
> primary shielding and minimal secondary neutron production. As you are
> using iron with lead – that is good.
>
>
>
> A compromise is the simple expedient to test the ongoing reaction as you
> plan but also with no shielding. If bare gives significantly more counts,
> then you have made the right choice to shield. However, it is likely that a
> bare test will show fewer, not more. That is especially true if the
> reaction itself is making muons. And didn’t Mark mention having a second
> meter anyway? Perfect.
>
>
>
> IMO - the most important finding which could come out of this is to see
> significantly more gammas in the cave than with no shielding - and to see a
> variance from inverse square when the cave is moved back from the reactor.
> If a radiation burst was to be  correlated with apparent endotherm, as in
> the last test – it would be a significant indication that Holmlid is
> correct.
>
>
>
> *From:* Bob Higgins
>
>
>
> Do you have a reference on this?  Otherwise, a lead cave would not be
> useful - it is there to protect the sensor from the cosmic rays.
>
> My understanding is that the cosmic rays produce the neutrons by
> spallation.  If the neutrons are absorbed in the lead, they will likely
> cause isotopic shift which will lead to beta emission and then
> characteristic x-rays for lead at 78 keV.  My plan is to follow the inside
> of the lead with 1/4" of Fe which will absorb all of the 78 keV but will
> produce the characteristic x-ray of Fe at 6 keV.  Then there is the boric
> acid neutron absorber, and then the aluminum absorbs the 6  keV from the
> Fe, but gives off 1.5 keV Al characteristic x-ray in small amount.
>
>
>
> On Sun, Feb 28, 2016 at 7:58 PM, Jones Beene <jone...@pacbell.net> wrote:
>
> *From:* Bob Higgins
>
> Ø       Jones, the moral of the story is that the large amount of lead
> (and it probably took a whole lot for the HPGe detector) converted some of
> the cosmic rays into a small* neutron* flux.
>
> Bob, as the thesis clearly states – the neutrons then are absorbed by the
> lead, causing the gamma radiation.
>
>
>
>
>

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