This reminds me of a question I have had. Imaging we have 2 lasers putting out 2 coherent light beams along the same path, one frequency is very slightly higher than the other.
Constrictive/destructive interference between the 2 beams mean that along the path at time they double in strength, but at other points cancel. So if you has thin lead shield, far far thinner than the length of the interference wavelength, and you place this where they cancel.... Surely the light would pass through this shield! Indeed, could the light not be on slightly different paths just that they only intersect and cancel at that one spot, and once through the shield they no longer need to interfere! Could some kind of diamagnetic opposite field creating energy that is localized help to create invisibility? Sort of a near field superconducting anti-field that because it doesn't transmit with the light allows an object to become invisible? And is light ever absorbed anyway? Or does it just result in an opposite photon that reduces the energy to zero, both moving on forever in utter undetectable insignificance? John On Fri, Jun 17, 2016 at 10:11 AM, <mix...@bigpond.com> wrote: > In reply to Stephen A. Lawrence's message of Thu, 16 Jun 2016 13:44:29 > -0400: > Hi, > [snip] > >The author says: > > > > "photons must become paired up in order to discharge the fuel > > cavity, so that the two photons in those pairs are essentially out > > of phase, which means they entirely cancel each other out and have > > no net electromagnetic field" > > > They also suggest that if it works the way they think it works, this will > ensure > a future for the technology. This is of course nonsense. If it works by > ejecting > photons, then you don' need the cavity at all. Just radiate the microwaves > directly into space, or for that matter don't bother even creating > microwaves, > since heat would work just as well. > > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
