Not simple of course :-) Without going into the details it may be something like:
1) 1 second (3 x 10^10 cm at light speed) + load entrance to load center drifting time at electron speed in load (slow, I would think it can be determined based on the current, on the load's cross section area, and on the free electron density of its material) 2) source to load (3 x 10^10 cm) drifting time at electron speed in wire (slow, also to be determined as above) Michel ----- Original Message ----- From: "Terry Blanton" <[EMAIL PROTECTED]> To: <vortex-l@eskimo.com> Sent: Tuesday, August 14, 2007 1:56 AM Subject: Re: [Vo]:Potential > 1) Should read ". . . first electron outside the load drifts . . ." > > On 8/13/07, Terry Blanton <[EMAIL PROTECTED]> wrote: >> Interesting exchanges. >> >> If a pair of wires are 3 x 10^10 cm long; and, a potential is applied >> to the ends of the wires with a load resistor on the other end, I have >> two simple questions: >> >> 1) How much time passes before the first electron drifts through the >> load center point assuming the load is only 2 cm long? >> >> 2) How much time passes before the first electron to leave the source >> of potential arrives at the load? >> >> Simple questions, eh? >> >> Terry >> >> >
