Dear Jones, If the power has to be included, it has to be measured. But only a part of the energy consumed by the motor of the pump is used to make the water to moveand this produces a small heating of water due to friction, So the reverse is true- the power of the motor has to be subtracted from Pin. Fortunately the inlet temperature of water is measured and this includes or, if you wish excludes the effect of the pump/motor. But he effect is negligible- and not on the side of Pin- it is at Pout.
Peter On Wed, Apr 20, 2011 at 5:34 PM, Jones Beene <jone...@pacbell.net> wrote: > Peter, > > > > The “Rossi effect” is controlled in a narrow range by balancing heat > removal and heat addition. > > > > It will not work reliably without constant heat removal. > > > > Therefore, power input related to the proper operation must be included as > P-in. > > > > Jones > > > > > > *From:* Peter Gluck > > > > Dear Jones, > > > > just from curiosity, in what kind of P-in has to be included the pump's > power and why? > > Peter > > > > We presume (hope) that the Swedes will not use a hose connected to > plumbing > where you get free water pressure, and will use a pump. The pump's power > must be included in P-in. > > A liter/sec pump seems to require one horsepower or about .75 kW. > > > > -- Dr. Peter Gluck Cluj, Romania http://egooutpeters.blogspot.com
