On 12/2/07, Zefram <[EMAIL PROTECTED]> wrote:
> If M and N are not contiguous, then it's more difficult because the
> desired output range is not contiguous. Using the C-style conditional
> operator, and C syntax, how about (given M < N):
>
> t = 4*(X == M ? 0 : 1) + 2*(Y == M ? 0 : 1) + (Z == M ? 0 : 1);
> d = t + (t < M ? 0 : t < N-1 ? 1 : 2);
> return 11*d;
What are you smoking, Zefram? See my message before about M and N
being arbitrary (different) digits.
--
Taral <[EMAIL PROTECTED]>
"Please let me know if there's any further trouble I can give you."
-- Unknown
