@Dave: Sorry It was a typo but for the probability figures, When C shoots B then if he is successful then A will shoot C Hence he must be unsuccessful and then if B is unsuccessful then A must will Kill B and then C must kill A if B is successful then C must kill B now Hence P(when C shoots at B)=(2/3 )*( (1/2)*(1/3) + (1/2)*(1/3) ) =2/9
When C shoots at A i am similarly getting for the case when A is killed as 1/12 and when A is safe as 5/18 Hence total 13/36 where am i wrong? -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
