Bayes' theorem: http://en.wikipedia.org/wiki/Bayes'_theorem P(x=even|x>3) = P(x>3|x=even)*P(x=even)/P(x>3)===>B
On Jan 14, 2:29 am, snehal jain <[email protected]> wrote: > An unbalanced dice (with 6 faces, numbered from 1 to 6) is thrown. The > probability that the face value is odd is 90% of the probability that > the face value > is even. The probability of getting any even numbered face is the > same. > If the probability that the face is even given that it is greater than > 3 is 0.75, > which one of the following options is closest to the probability that > the face value > exceeds 3? > (A) 0.453 (B) 0.468 (C) 0.485 (D) 0.492 -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
