@Jai: Oops. I switched two numbers: P(when C shoots at B)=5/18 P(when C shoots at A)=13/36 P(when C shoots in air)=5/12
Dave On Jan 3, 10:36 am, Dave <[email protected]> wrote: > @Jai: If B doesn't hit A, then A surely will shoot B. Thus, B's only > chance of survival is to shoot A, so your statement that B will prefer > to kill C is incorrect. > > It also looks like you changed 33% to 1/3. When I calculate the > probabilities of C's survival using 1/3 instead of 33%, I get > > P(when C shoots at B)=13/36 > P(when C shoots at A)=5/18 > P(when C shoots in air)=5/12 > > And I see that I had made a mistake on the last calculation when using > 33%. The correct figure is 0.41312 instead of 0.49624 as I had > reported inhttp://groups.google.com/group/algogeeks/msg/30e11e6ff2945573. > > Dave > > On Jan 3, 9:34 am, jai gupta <[email protected]> wrote: > > > > > Going case by case and Taking into consideration Daves suggestion that A > > will prefer to kill B if all three are alive and B will prefer to kill C if > > all three are alive, We find the following probabilities of survival of C by > > starting. > > P(when C shoots at B)=2/9 > > P(when C shoots at A)=13/36 > > P(when C shoots in air)=5/12 > > > Hence C must chose to shoot in air.- Hide quoted text - > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
