Julf wrote: 
> I think you can. Remember Nyquist (or, more formally, the
> "Nyquist–Shannon sampling theorem") states that "If a function x(t)
> contains no frequencies higher than B hertz, it is completely determined
> by giving its ordinates at a series of points spaced 1/(2B) seconds
> apart."
> 
> "Completely determined" means "completely reconstructible", but I might
> be missing your point.

I do agree ( coffe + whether report is enjoyed ) but in reality no clock
does 1/(2B) perfectly so the actual nyqkvist frequency may fluctuate
slightly so in practical implementation you leave a little slush margin
.

But that the extent of my knowledge I can't do z transforms :-/ an
eternity ago I could do Laplace ( in university ).
I do understand some simple things like " completely determined " .
And actually the limited bit resolution 11/14/16/24 and whatnot of a
digital,system actually means that the residues above fs does not need
to be complete damped but say a finite xx dB is enough but this usually
is a whole lot of dB >100dB or much greater (140dB) in most filters I've
seen in the layman software I ever used .
There may be no thing as a perfectly bandwith limited signal so some
extremely small aliasing residues may be there ,but hey this is not
radio astronomy or cat scanners or anything sensitive just good old
audio :)


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