Frederic VELLIEUX wrote:
Anisotropy in the diffraction pattern could simply be due to the shape of the 
crystals. The intensity of diffraction is a function of the volume of 
diffracting matter that is hit by the X-ray beam. Think for example of a thin 
plate crystal, which you rotate in the X-ray beam. When the plate is 
perpendicular to the X-ray beam, the volume of matter hit by the X-rays is much 
smaller than when the plate is parallel to the X-ray beam.
Fred, I think this is a bit misleading. Although diffraction anisotropy is often accompanied by platy or needle-y crystals, the crystal shape is neither necessary nor sufficient to produce an anisotropic B factor. You will get an anisotropic SCALE factor if bits of the crystal are moving in and out of the beam as you describe, but scale factors and B factors are not the same thing! B factors arise from differences between neighboring unit cells (within a few microns of each other), and anisotropic B factors arise when the average displacement of atoms from their ideal lattice points is higher in one direction than another. Admittedly, both scale and B can have an effect on the resolution limit, but the latter kills high-angle spots much more rapidly than the former.

Operationally, I recommend treating anisotropic data just like isotropic data. There is nothing wrong with measuring a lot of zeros (think about systematic absences), other than making irrelevant statistics like Rmerge higher. One need only glance at the formula for any R factor to see that it is undefined when the "true" F is zero. Unfortunately, there are still a lot of reviewers out there who were trained that "the Rmerge in the outermost resolution bin must be 20%", and so some very sophisticated ellipsoidal cut-off programs have been written to try and meet this criterion without throwing away good data. I am actually not sure where this idea came from, but I challenge anyone to come up with a sound statistical basis for it. Better to use I/sigma(I) as a guide, as it really does tell you how much "information vs noise" you have at a given resolution.

-James Holton
MAD Scientist

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