>> I think this is what I want. Thanks! So I might have to repeat this
>> a few hundred times to actually get a legal position?
>
> Are you aware that nearly all of these positions will be final positions?
> ...if you actually need middle game positions you will have to
> use a different procedure...
(The procedure from Paul Pogonyshev is repeated below.)
On average it will have 54 stones, 27 empty points. It you want a more
middle-game-ish position, increase the probability of an empty point
(e.g. empty 0.6, black 0.2, white 0.2). This will also give you a legal
position more frequently.
Darren
------------------------
1. create a really random position, i.e. traverse all intersection and
assign a black/white/empty state at random to each;
2. if it happens to be not legal, discard and repeat step 1.
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