-1 on this suggestion from me too. The current API is composable ( https://en.m.wikipedia.org/wiki/Composability ), the suggestion is to make it less so, and make it harder to learn
On Sat, 19 Jan 2019 at 08:01, charettes <charett...@gmail.com> wrote: > To echo my comments on the PR I don't like the idea of relaying args and > kwargs to filter() > as it I think it adds little value considering it paints us in a corner > with regards to future > count()/exists() API change. > > For example if we ever want to add `distinct` kwarg and fields arg passing > to .count() in the > future (like it's Count() analog) we wouldn't be able to do so. I would > consider these additions > way more in line and coherent with the current QuerySet's API. > > Considering this and Tim's point about Python's Zen I'm strongly -1 on > this one. > > Cheers, > Simon > > Le vendredi 18 janvier 2019 15:12:22 UTC-6, Sjoerd Job Postmus a écrit : >> >> Dear all, >> >> >> This is probably a feature that has been proposed before, but I could >> not find a discussion on it, so I proposed it on the tracker, and Tim >> also couldn't find a discussion. >> >> (ticket: https://code.djangoproject.com/ticket/30118 ) >> >> I would like to propose being able to write >> `SomeModel.objects.exists(field=value)` over >> `SomeModel.objects.filter(field=value).exists()` (and similar for >> `.count(**kwargs)`. >> >> >> As Tim rightfully commented: "There should be one-- and preferably only >> one --obvious way to do it.". >> >> >> I'm proposing this is a case where the obvious way would eventually be >> more in line with my suggestion instead of what we currently use. >> >> >> Consider the following code example (from >> >> https://github.com/django/django/blob/709a8b861de14204f0e13c9a0fbfd61c11b3565d/tests/auth_tests/test_management.py#L998): >> >> >> >> Permission.objects.filter( >> content_type__model=opts.model_name, >> content_type__app_label=opts.app_label, >> codename=codename, >> ).exists() >> >> There is a weird (to me, your mileage might vary) ").exists()" as a >> final line, and I would like to write this as >> >> Permission.objects.exists( >> content_type__model=opts.model_name, >> content_type__app_label=opts.app_label, >> codename=codename, >> ) >> >> This pattern seems to be quite rare in the Django codebase itself, but >> in the codebase at work we have several cases of `queryset.filter(<lots >> of lines>).exists()` (and similar with count), and I am expecting this >> to also be prevalent in other codebases out there. >> >> >> Arguing against it however are the following lines of the Zen of Python: >> >> - "Explicit is better than implicit." >> >> - Maybe also "Special cases aren't special enough to break the rules.", >> because `.filter().count()` and `.exclude().count()` are both the same >> pattern, but this would only create an alternative for the first. >> >> - "There should be one-- and preferably only one --obvious way to do it." >> >> >> Beyond these short quips, I was hoping there might also be an earlier >> discussion covering this. >> >> >> Kind regards, >> >> Sjoerd Job Postmus >> >> -- > You received this message because you are subscribed to the Google Groups > "Django developers (Contributions to Django itself)" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to django-developers+unsubscr...@googlegroups.com. > To post to this group, send email to email@example.com. > Visit this group at https://groups.google.com/group/django-developers. > To view this discussion on the web visit > https://groups.google.com/d/msgid/django-developers/1c86bd0a-0000-405b-b990-4f316bbec458%40googlegroups.com > <https://groups.google.com/d/msgid/django-developers/1c86bd0a-0000-405b-b990-4f316bbec458%40googlegroups.com?utm_medium=email&utm_source=footer> > . > For more options, visit https://groups.google.com/d/optout. > -- Adam -- You received this message because you are subscribed to the Google Groups "Django developers (Contributions to Django itself)" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-developers+unsubscr...@googlegroups.com. To post to this group, send email to firstname.lastname@example.org. Visit this group at https://groups.google.com/group/django-developers. To view this discussion on the web visit https://groups.google.com/d/msgid/django-developers/CAMyDDM1akghatg5AxpMf_sfEPH_FPXDShKdUJnpH9Ns3k5hh0g%40mail.gmail.com. For more options, visit https://groups.google.com/d/optout.