I have narrowed down the problem to %2F in my url, anyone?


On Oct 6, 2:55 pm, Merrick <[EMAIL PROTECTED]> wrote:
> \w will only match alphanumeric characters, I need to match anything
> and will let my modelform verify that it is indeed a URL.
>
> On Oct 6, 2:43 pm, Merrick <[EMAIL PROTECTED]> wrote:
>
> > Thank you, I meant urls.py. APPEND_SLASH = False so I omitted the
> > trailing slash from the regex line:
>
> > r'^find/(?P<url>[-\w]+)$
>
> > and if I pull up the address:
>
> >http://mydomain.com/find/http%3A%2F%2Fwww.wired.com%2F
>
> > I still get
>
> > Not Found
>
> > The requested URL /find/http://www.wired.com/wasnot found on this
> > server.
>
> > I did figure out how to decode the URL in python using unquote_plus(),
> > but I cannot figure out this problem.
>
> > On Oct 6, 1:27 pm, "Keith Eberle" <[EMAIL PROTECTED]> wrote:
>
> > > it looks like you have mismatched parens, and no trailing slash, which 
> > > will
> > > matter if APPEND_SLASH = True.  the regex should look like:
>
> > >     r'^find/(?P<url>[-\w]+)/$'
>
> > > should be urls.py too, not views.py.
>
> > > keith
>
> > > On Mon, Oct 6, 2008 at 1:17 PM, Merrick <[EMAIL PROTECTED]> wrote:
>
> > > > I am trying to figure out how to match / capture a URL.
>
> > > > views.py
> > > > =======
> > > > urlpatterns = patterns('',
> > > >    url(r'^find/(?P<url>(.*)$',
> > > >        view = 'myapp.views.find',
> > > >        name = 'find'
> > > >    ),
>
> > > > when I enter in this address:
>
> > > > mydomain.com/find/www.wired.com
>
> > > > my view / template are executed, but if I do this:
>
> > > > mydomain.com/find/http%3A%2F%2Fwww.wired.com%2F
>
> > > > I get:
>
> > > > Not Found
>
> > > > The requested URL /find/http://www.wired.com/wasnotfound on this
> > > > server.
>
>
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