While I have not found the complete solution, I am closer. I added this to my apache settings for the virtual host:
AllowEncodedSlashes On I am no longer getting a 404. But even though the url has two instances of %2f to represent two slashes: http://mydomain.com/find/http%3A%2F%2Fwww.wired.com%2F I am able to capture the URL, but with only one slash. I pass it to my ModelForm and it prints in my template as: http:/www.wired.com/ Note the lack of double forward slashes after the colon. On Oct 6, 4:10 pm, Merrick <[EMAIL PROTECTED]> wrote: > keith, thanks for trying. > > %2f is the encoded value of /, but urls contain other characters as > well not just alphanumeric. > > I suspect this issue may have to do with apache or WSGI but not sure > what. > > On Oct 6, 4:06 pm, "Keith Eberle" <[EMAIL PROTECTED]> wrote: > > > quick solution, i think you could add the % to the regex (i'm hardly a > > regex master): > > > r'^find/(?P<url>[%-\w]+)$ > > > keith > > > On Mon, Oct 6, 2008 at 7:05 PM, Merrick <[EMAIL PROTECTED]> wrote: > > > > I have narrowed down the problem to %2F in my url, anyone? > > > > On Oct 6, 2:55 pm, Merrick <[EMAIL PROTECTED]> wrote: > > > > \w will only match alphanumeric characters, I need to match anything > > > > and will let my modelform verify that it is indeed a URL. > > > > > On Oct 6, 2:43 pm, Merrick <[EMAIL PROTECTED]> wrote: > > > > > > Thank you, I meant urls.py. APPEND_SLASH = False so I omitted the > > > > > trailing slash from the regex line: > > > > > > r'^find/(?P<url>[-\w]+)$ > > > > > > and if I pull up the address: > > > > > >http://mydomain.com/find/http%3A%2F%2Fwww.wired.com%2F > > > > > > I still get > > > > > > Not Found > > > > > > The requested URL /find/http://www.wired.com/wasnotfoundon this > > > > > server. > > > > > > I did figure out how to decode the URL in python using unquote_plus(), > > > > > but I cannot figure out this problem. > > > > > > On Oct 6, 1:27 pm, "Keith Eberle" <[EMAIL PROTECTED]> wrote: > > > > > > > it looks like you have mismatched parens, and no trailing slash, > > > which will > > > > > > matter if APPEND_SLASH = True. the regex should look like: > > > > > > > r'^find/(?P<url>[-\w]+)/$' > > > > > > > should be urls.py too, not views.py. > > > > > > > keith > > > > > > > On Mon, Oct 6, 2008 at 1:17 PM, Merrick <[EMAIL PROTECTED]> wrote: > > > > > > > > I am trying to figure out how to match / capture a URL. > > > > > > > > views.py > > > > > > > ======= > > > > > > > urlpatterns = patterns('', > > > > > > > url(r'^find/(?P<url>(.*)$', > > > > > > > view = 'myapp.views.find', > > > > > > > name = 'find' > > > > > > > ), > > > > > > > > when I enter in this address: > > > > > > > > mydomain.com/find/www.wired.com > > > > > > > > my view / template are executed, but if I do this: > > > > > > > > mydomain.com/find/http%3A%2F%2Fwww.wired.com%2F > > > > > > > > I get: > > > > > > > > Not Found > > > > > > > > The requested URL /find/http://www.wired.com/wasnotfoundonthis > > > > > > > server. > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
