The derivation of this formula involves considering a position in front of the 
antenna, on the line in the direction of radiation.  The distance from this 
point to the edge of the antenna will be slightly more than the distance to the 
centre.  If this distance is a significant fraction of a wavelength, the the 
far field pattern is not realised because of phase error / cancellation.  Hence 
at higher frequencies (shorter wavelengths), the same position in front of the 
antenna will have phase errors where there were no problems at lower 
frequencies.

Hope this helps,




Dr Luke Turnbull
Principal EMC Engineer
TRW Conekt
Statford Road
Solihull
B90 4GW

Tel:     +44 (0)121.627.3966
Fax:    +44 (0)121.627.4353
email:  [email protected]
web:     www.trw.com/conekt/

>>> George Stults <[email protected]> 11/21/02 05:59pm >>>

Hello Group,

A book I've been reading gives the Rayleigh criterion for farfield
conditions based on antenna (or EUT max dimension) size as 

dist for farfield conditions  >  2*(max antenna dimension)^2/lambda

When I look at this,  it says that the required distance for far field
conditions increases as the square of the dimensions of the antenna, which
seems intuitive.  

What I found strange is that if you hold the antenna dimension constant, (ie
for a given fixed antenna dimension)  it predicts that the distance for
farfield conditions will increase linearly with the frequency.  That does
not seem intuitive.   

Does anyone have a thought about how this works?

Regards,

George Stults
WatchGuard Technologies Inc



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