Mr. Stults is right, my analogy did not directly address his concern.  The
fact that I thought it did shows how thoroughly I see the two issues as
identical.

I can provide the derivation of the 2D**2/wavelength to those who are
interested.  It has to be an attachment.  presently I am sending it only to
Mr. Stults.

----------
>From: George Stults <[email protected]>
>To: "'Ken Javor'" <[email protected]>,
"'[email protected]'" <[email protected]>
>Subject: RE: rayleigh criterion and farfield
>Date: Thu, Nov 21, 2002, 2:37 PM
>

> As I understand it, your analogy agrees nicely with the prediction that as
> the dimensions increase, the far field distance increases.  I think my
> question is a little different. By the same analogy and considering a fixed
> dimension lense versus the length at which various frequencies could be
> focused; it seems like the formula predicts that higher frequencies of light
> would focus further out.  Does that happen?
>
> -----Original Message-----
> From: Ken Javor [mailto:[email protected]]
> Sent: Thursday, November 21, 2002 12:12 PM
> To: George Stults; '[email protected]'
> Subject: Re: rayleigh criterion and farfield
>
>
> The fact that an aperture antenna's (horn/dish) gain increases with
> increasing frequency DOES seem intuitively obvious to me.  Consider an
> optical analogy.  Lenses.  If you are familiar with 35 mm photography, you
> will recognize that a short lens like a 28 mm will focus from a couple
> inches from the lens to infinity.  Whereas a long lens like 200 mm won't
> focus closer than about 6 feet.  Minimum focusing distance is the same as
> far field.  The higher the gain, the further out from the antenna you have
> to be before achieving rated gain.
>
> ----------
>>From: George Stults <[email protected]>
>>To: "'[email protected]'" <[email protected]>
>>Subject: rayleigh criterion and farfield
>>Date: Thu, Nov 21, 2002, 11:59 AM
>>
>
>>
>> Hello Group,
>>
>> A book I've been reading gives the Rayleigh criterion for farfield
>> conditions based on antenna (or EUT max dimension) size as
>>
>> dist for farfield conditions  >  2*(max antenna dimension)^2/lambda
>>
>> When I look at this,  it says that the required distance for far field
>> conditions increases as the square of the dimensions of the antenna, which
>> seems intuitive.
>>
>> What I found strange is that if you hold the antenna dimension constant,
> (ie
>> for a given fixed antenna dimension)  it predicts that the distance for
>> farfield conditions will increase linearly with the frequency.  That does
>> not seem intuitive.
>>
>> Does anyone have a thought about how this works?
>>
>> Regards,
>>
>> George Stults
>> WatchGuard Technologies Inc
>>
>>
>>
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