Sorry, but I don't understand the physics here. Could you please explain how a 10 us delay could add 0.01 us to a 1 us pulse? A typical pulse rep rate is 1 kHz. To me it seems that a 10 us delay would cause no interference effect at all, since the first pulse is over and another isn't due to arrive for another millisecond. What you said makes sense to me if you meant 10 ns, but that is not what your message said. Was that a typo?
> From: John Woodgate <[email protected]> > Reply-To: John Woodgate <[email protected]> > Date: Sun, 27 Jul 2003 21:20:07 +0100 > To: [email protected] > Subject: Re: pulse modulation in reverb chambers > > I read in !emc-pstc that Ken Javor <[email protected]> wrote > (in <bb4987fa.372a%[email protected]>) about 'pulse modulation > in reverb chambers' on Sun, 27 Jul 2003: > >> As long as >> those delays are much shorter than 1 us (path difference much less than >> 300 meters), the original modulation is received. > > Not really. If a reflection arrives with a delay of 10 us, the received > pulse is 1.01 us long. Some 'rays' suffer multiple reflections, which > increases the delay considerably, and the reflections in a reverberation > chamber must be low-loss. How much stretching can you accept? This message is from the IEEE EMC Society Product Safety Technical Committee emc-pstc discussion list. Visit our web site at: http://www.ewh.ieee.org/soc/emcs/pstc/ To cancel your subscription, send mail to: [email protected] with the single line: unsubscribe emc-pstc For help, send mail to the list administrators: Ron Pickard: [email protected] Dave Heald: [email protected] For policy questions, send mail to: Richard Nute: [email protected] Jim Bacher: [email protected] Archive is being moved, we will announce when it is back on-line. All emc-pstc postings are archived and searchable on the web at: http://www.ieeecommunities.org/emc-pstc
