On 24 February 2013 01:40, Bruce Klawiter <bmkl...@yahoo.com> wrote:

> I have just switch my mill over from linear scales to rotary encoders and
> I can't get my input scale right. OUTPUT_SCALE is 1, Units-inch
>

X axis has a 1250 CPR differential encoder, motor 14 tooth gear, screw 21
> tooth gear, .200 pitch screw. 1250 X 4 X 1.5 X 5 = INPUT_SCALE = 37500
>

My arithmetic may be way off, but I don't understand any of the above.
Where does 1.5 and 4 and 5 come into it?

The way I see it, 1250 counts = 1 motor rev = 14/21 x 0.2 = 0.13333333 in

therefore, 1 count = 0.133333 /1250 = 0.000106666 in
or,  1 inch = 9375 counts.

You should in any case, be able to jog the motor for 10 inches linear
travel and get a ballpark figure. Then /10 and you'll know 95% of what
you're aiming for.

Roland




>
> Y axis 5000 CPR differential encoders, motor 14 tooth gear, screw 21 tooth
> gear, .200 pitch screw. 5000 X 4 X 1.5 X 5 = INPUT_SCALE = 150000
>
> Z axis 5000 CPR differential encoders, motor 14 tooth gear, screw 28
> tooth gear, .200 pitch screw. 5000 X 4 X 2 X 5 = INPUT_SCALE = 200000
>
> If these calculations are correct they don't work, to even be in the
> ballpark of one inch of actual travel (+/- .020) equaling the DRO showing
> one inch I need.
> X axis INPUT_SCALE =38500
> Y axis INPUT_SCALE =750000
> Z axis INPUT_SCALE =1000000
>
> What am I missing here.
>
> Your help is greatly appreciated,
> Bruce
>
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