On 11/6/2016 1:57 PM, Robert Ellenberg wrote:
> On Sun, Nov 6, 2016 at 2:46 PM Danny Miller <dan...@austin.rr.com> wrote:
>
>> I did some rotary stuff on Mach3 and was baffled by similar issues.
>>
>> Seems like it'd be CAM's job to manage the feedrate, and calculate for
>> the work radius.  That would make sense if you were cutting a cylinder
>> and the G-code move was "X moves 3 inches, A rotates 100 times, feed X
>> at 1.5 inches/min"
>>
>> But if the cartesians aren't moving- which is common- the F value has no
>> meaning at all if it's cartesian.  There is no way for G-code language
>> to communicate "polar Feed =  200 deg/sec" and it's nonsense to combine
>> polar and cartesian vectors into a single scalar for a feedrate.
>>
> The F word is overloaded. If there's no cartesian motion, then it treats
> the number as degrees per min instead of in per min.
That sounds like a bad idea.  The interp of F jumps around to a totally 
different thing if there's no cartesian motion?
So if you MDI in  "G1 X1 A200 F3" it does one thing if you're at X=2 and 
a totally different thing if you're at X=1?  Or does the inclusion of 
any linear axis mode it over to cartesian?  Well, but, you couldn't do 
that- if you're already at X=1, F3 is all polar and it's impossible to 
interpret as a linear feedrate since there's no linear motion.

What if X moves 0.001" and that gets optimized out?
>
> Seems like the logical answer is amending G-code Feedrate with syntax
>> for an angular vector in addition to cartesian, but no CAM pkg would
>> support it.
>
> The "proper" way as I understand it is to use inverse time when doing both
> linear and angular moves. It's perfectly sensible to say "move X inches and
> A degress within T seconds".

Huh, ok, yeah inverse-time does make sense.
>


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