On 04/04/13 00:52, Carsten Haitzler (The Rasterman) wrote:
> On Wed, 03 Apr 2013 17:26:42 +0100 Tom Hacohen <tom.haco...@samsung.com> said:
>
>> On 28/03/13 10:49, Carsten Haitzler (The Rasterman) wrote:
>>> On Thu, 28 Mar 2013 09:56:40 +0000 Michael Blumenkrantz
>>> <michael.blumenkra...@gmail.com> said:
>>>
>>> thats cool. i just had to be grumpy about not having a bug report that told
>>> me what to look at instantly. i have found another bug. single letter words
>>> dont find word end markers.
>>
>> I just checked it, and it works for me:
>> #include <stdlib.h>
>> #include <wchar.h>
>> #include <stdio.h>
>> #include <wordbreak.h>
>>
>> int main()
>> {
>> {
>> const char *lang = "";
>> wchar_t *text = L"This is a test";
>> size_t len = wcslen(text);
>> char *breaks = malloc(len);
>> size_t i;
>>
>> printf("%ls\n", text);
>>
>> set_wordbreaks_utf32((const utf32_t *) text, len, lang, breaks);
>> for (i = 0 ; i < len ; i++)
>> printf("%d", (int) breaks[i]);
>> printf("\n");
>> }
>> return 0;
>> }
>>
>> The output is:
>> This is a test
>> 11100100001110
>>
>> 1s meaning no break, 0s meaning break here. It does break correctly
>> around the "a". Could you elaborate more on the bug you were seeing?
>
> no NON-breaks around "a". you can't tell that there is a word there at all. it
> may as well be " " (all spaces). :)
>
>> Cheers,
>> Tom.
>>
>
>
Yeah, well, you know it using other means. Unfortunately it's beyond the
scope of the word breaking algorithm... There are no word breaks there,
thus the algorithm produces none. You probably need to just skip whites
in your code, not only rely on the wordbreak data when "merging" the whites.
--
Tom.
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