On Tue, Nov 1, 2011 at 2:58 PM, Axel Rauschmayer <[email protected]> wrote:
> > Another point to consider: What happens if there are several calls > super.foo() and the last one makes a call this.foo() (infinite recursion > can be prevented via a parameter) > We're getting mixed up in time, as I just answered that in the previous message. To quote myself: > ... and even for fancier cases where you restart the same super() chain recursively > from the outside. Imagine if one of the deeper super.one()'s itself calls obj.one(), > with a direct reference to the instance (and a different parameter, to avoid infinite > recursion). You can imagine super counters as a stack instead of a value, and > push a fresh one on, popping it when the new obj.one() call exits. ... a simple stack of records, one for each re-starting of the super() chain, should do. When calling super() from a function, it's easy for the runtime to tell if that function was itself invoked via super(), or from the top level.
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