>> Le 29 oct. 2015 à 21:04, Waldemar Horwat <walde...@google.com> a écrit :
>> 
>> On 10/29/2015 12:19, Laurentiu Macovei wrote:
>>  `foo?.bar` and `foo?['bar']` syntax would work too.
> 
> No.  It would break existing code:
> 
>  x = foo?.3:.5;

That could be resolved by a simple lookahead, I think. 
> 
>  x = foo?[a]:[b];

That one is more problematic. IIRC, it was once suggested to use`?.[` instead. 

—Claude 

> 
> On the other hand, turning .. into a token should be fine.
> 
>    Waldemar
> 
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