On 10/13/2025 5:04 AM, Alan Grayson wrote:


On Sunday, October 12, 2025 at 11:50:58 PM UTC-6 Brent Meeker wrote:



    On 10/12/2025 10:18 PM, Alan Grayson wrote:


    On Sunday, October 12, 2025 at 10:37:32 PM UTC-6 Brent Meeker wrote:

        If there's no collapse then every possible sequence of
        results is observed in some world and the relative counts of
        UP v. DOWN in the ensemble of worlds will have a binomial
        distribution.  So for a large numbers of trials those worlds
        in which UPs and DOWNs are roughly equal will predominate,
        regardless of what the Born rule says.  So in order that the
        Born rule be satisfied for values other than 50/50 there must
        be some kind of selective weight that enhances the number of
        sequences close to the Born rule instead of every possible
        sequence being of equal weight.  But then that is
        inconsistent with both values occuring on every trial.

        Brent


    Why does Born's rule depend on collapse of wf? AG
    Where did I say it did?

    Brent


The greatest mathematicians tried to prove Euclid's 5th postulate from the other four, and failed; and the greatest physicists have tried to dervive Born's rule from the postulates of QM, and failed;, except for Brent Meeker in the latter case. You claimed it in the negative, by claiming that without collapse, Born's rule would fail in some world of the MWI. An assertion is just that, an assertion. Can you prove it using mathematics? AG

Sure.  Consider a sequence of n=4 Bernoulli trials.  Let h be the number of heads.  Then we can make a table of the number of all possible sequences bc with exactly h heads and with the corresponding observed proportion h/n

     h       bc       h/n
    0         1        0.0
    1         4        0.25
    2         6        0.5
    3         4        0.75
    4         1        1.0

So each possible sequence will correspond to one of Everett's worlds.  For example hhht and hthh belong to the fourth line h=3. There are sixteen possible sequences, so there will be sixteen worlds and a fraction 6/16=0.3125 will exhibit a prob(h)~0.5.

But suppose it was an unfair coin, loaded so that the probability of tails was 0.9.  The possible sequences are the same, but now we can apply the Born rule and calculate probabilities for the various sequences, as follows:

     h       bc       h/n     prob
    0         1        0.0      0.656
    1         4        0.25    0.292
    2         6        0.5      0.049
    3         4        0.75    0.003
    4         1        1.0      0.000

So  most of the observers will get empirical answers that differ drastically from the Born rule values.  The six worlds that observe 0.5 will be off by a factor of 1.8.  And notice the error only becomes greater as longer test sequences are used.  The number of sequences peak more sharply around 0.5 while the the Born values peak more sharply around 0.9.

Brent


        On 10/12/2025 6:56 PM, Alan Grayson wrote:
        Correct me if I'm mistaken, but as far as I know the wf has
        never been observed; only the observations of the system it
        represents. This being the case, in a large number of
        trials. Born's rulle will be satisfied regardless of which
        interpretation an observer affirms; either the MWI with no
        collapse of the wf, or Copenhagen with collapse of the wf.
        That is, since we can only observe the statistical results
        of an experiment from a this-world perspective, and we see
        that Born's rule is satisfied, so I don't see how it can be
        argued that the rule fails to be satisfied if the MWI is
        assumed. I think the same can be said about the other worlds
        assumed by the MWI, namely, that IF we could measure their
results, the rule would likewise be satisfied.AG --

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