On Tuesday, October 14, 2025 at 10:24:42 PM UTC-6 Brent Meeker wrote:



On 10/14/2025 12:20 PM, Alan Grayson wrote:



On Monday, October 13, 2025 at 10:28:30 PM UTC-6 Brent Meeker wrote:



On 10/13/2025 5:04 AM, Alan Grayson wrote:



On Sunday, October 12, 2025 at 11:50:58 PM UTC-6 Brent Meeker wrote:



On 10/12/2025 10:18 PM, Alan Grayson wrote:



On Sunday, October 12, 2025 at 10:37:32 PM UTC-6 Brent Meeker wrote:

If there's no collapse then every possible sequence of results is observed 
in some world and the relative counts of UP v. DOWN in the ensemble of 
worlds will have a binomial distribution.  So for a large numbers of trials 
those worlds in which UPs and DOWNs are roughly equal will predominate, 
regardless of what the Born rule says.  So in order that the Born rule be 
satisfied for values other than 50/50 there must be some kind of selective 
weight that enhances the number of sequences close to the Born rule instead 
of every possible sequence being of equal weight.  But then that is 
inconsistent with both values occuring on every trial.

Brent


Why does Born's rule depend on collapse of wf? AG 

Where did I say it did?

Brent


The greatest mathematicians tried to prove Euclid's 5th postulate from the 
other four, and failed; and the greatest physicists have tried to dervive 
Born's rule from the postulates of QM, and failed;, except for Brent Meeker 
in the latter case. You claimed it in the negative, by claiming that 
without collapse, Born's rule would fail in some world of the MWI. An 
assertion is just that, an assertion. Can you prove it using mathematics? AG


Sure.  Consider a sequence of n=4 Bernoulli trials.  Let h be the number of 
heads.  Then we can make a table of the number of all possible sequences bc 
with exactly h heads and with the corresponding observed proportion h/n

     h       bc       h/n     
    0         1        0.0      
    1         4        0.25
    2         6        0.5
    3         4        0.75
    4         1        1.0

So each possible sequence will correspond to one of Everett's worlds.  For 
example hhht and hthh belong to the fourth line h=3.  There are sixteen 
possible sequences, so there will be sixteen worlds and a fraction 
6/16=0.3125 will exhibit a prob(h)~0.5.  

But suppose it was an unfair coin, loaded so that the probability of tails 
was 0.9.  The possible sequences are the same, but now we can apply the 
Born rule and calculate probabilities for the various sequences, as follows:

     h       bc       h/n     prob
    0         1        0.0      0.656
    1         4        0.25    0.292
    2         6        0.5      0.049 
    3         4        0.75    0.003  
    4         1        1.0      0.000  

So  most of the observers will get empirical answers that differ 
drastically from the Born rule values.  The six worlds that observe 0.5 
will be off by a factor of 1.8.  And notice the error only becomes greater 
as longer test sequences are used.  The number of sequences peak more 
sharply around 0.5 while the the Born values peak more sharply around 0.9.

Brent


Sorry, I don't quite understand your example? What has this to-do with 
collapse of the wf and the MWI? Where is collapse implied or not? How is 
Born's rule applied when the wf is discrete? AG

You wrote, "...claiming that without collapse,* Born's rule would fail in 
some world of the MWI*....Can you prove it using mathematics?"  So I showed 
that in MWI, which is without collapse, 6 out of 16 experimenters  will 
observe p=0.5 even in a case in which the Born rule says the likelihood of 
p=0.5 is 0.049.  Of course your challenge was confused since it is not 
Born's rule that fails.  Born's rule is well supported by thousands if not 
millions of experiments.  Rather it is that MWI fails...unless it includes 
a weighting to enforce the Born rule. But as Bruce points out there is no 
mechanism for this.  If the experiment is done to measure the probability 
(with no assumption of the Born rule) then there are 16 possible sequences 
of four measurements and 6 of them give p=0.5 and 6/16=0.375, making p=0.5 
the most likely of the four outcomes.   What this has to do with collapse 
of the wave function is just that the Born rule predicts the probabilities 
of what it will collapse to.  So (assuming MWI) there are still 6 of the 16 
who see 2h and 2t but somehow those 6 experimenters have only a small 
weight of some kind.  Their existence is kind of wispy and not-robust.

Brent


I didn't mean to imply that Born's rule is violated. But what you need to 
do IMO, is show how Born's rule is applied to your assumed events as seen 
without colapse in some world of the MWI. Otherwise, you just have a set of 
claims without any proof of their validity. AG 




On 10/12/2025 6:56 PM, Alan Grayson wrote:

Correct me if I'm mistaken, but as far as I know the wf has never been 
observed; only the observations of the system it represents. This being the 
case, in a large number of trials. Born's rulle will be satisfied 
regardless of which interpretation an observer affirms; either the MWI with 
no collapse of the wf, or Copenhagen with collapse of the wf. That is, 
since we can only observe the statistical results of an experiment from a 
this-world perspective, and we see that Born's rule is satisfied, so I 
don't see how it can be argued that the rule fails to be satisfied if the 
MWI is assumed. I think the same can be said about the other worlds assumed 
by the MWI, namely, that IF we could measure their results, the rule would 
likewise be satisfied.AG -- 

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