On 9/29/2025 3:38 PM, Alan Grayson wrote:
If they have different proper times, how can I conclude one is more than the other?? I can only conclude that if they are identical?? Have you lost your ability to read English??On Monday, September 29, 2025 at 4:21:29 PM UTC-6 Brent Meeker wrote: On 9/29/2025 10:39 AM, Alan Grayson wrote:On Saturday, September 6, 2025 at 5:56:36 PM UTC-6 Brent Meeker wrote: No. You're over complicating the problem. It's as simple as the fact that two different thru spacetime are different lengths. Because the spatial coordinate distance, X, appears with a minus sign relative to the coordinate time, T, the proper time, S (which is what a clock measures). So the rocket, which takes the longer spatial path, experiences less proper time lapse. *Aren't you assuming that the integrated S over both paths is the same? This is the issue I previously flagged. How do we know that both paths when integrated, have identical lengths, S? AG *Certainly not. *The whole point is that they have different length!* The proper time S is what a clock (or age) measures. Brent*If they have different S lengths, how can you conclude the proper time on stationary twin's clock records more time than the traveling twin's clock? Only if the S lengths are identical (which I didn't believe when I posted my question) can you reach that conclusion. AG *
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