On Monday, September 29, 2025 at 4:21:29 PM UTC-6 Brent Meeker wrote:
On 9/29/2025 10:39 AM, Alan Grayson wrote: On Saturday, September 6, 2025 at 5:56:36 PM UTC-6 Brent Meeker wrote: No. You're over complicating the problem. It's as simple as the fact that two different thru spacetime are different lengths. Because the spatial coordinate distance, X, appears with a minus sign relative to the coordinate time, T, the proper time, S (which is what a clock measures). So the rocket, which takes the longer spatial path, experiences less proper time lapse. *Aren't you assuming that the integrated S over both paths is the same? This is the issue I previously flagged. How do we know that both paths when integrated, have identical lengths, S? AG * Certainly not. *The whole point is that they have different length!* The proper time S is what a clock (or age) measures. Brent *If they have different S lengths, how can you conclude the proper time on stationary twin's clock records more time than the traveling twin's clock? Only if the S lengths are identical (which I didn't believe when I posted my question) can you reach that conclusion. AG * -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion visit https://groups.google.com/d/msgid/everything-list/e264bf08-b771-4cab-b8f7-cc6c78c09940n%40googlegroups.com.
