On Wed, Mar 5, 2014 at 2:52 PM, Edgar L. Owen <[email protected]> wrote:
> Jesse, > > Yes, the views are infinite on several axes, but that can be addressed > simply by enumerating views at standard intervals on those axes. > But velocity intervals which are equal when the velocities are defined relative to one frame are not equal when the velocities are defined relative to a different frame. I already mentioned an example where if a frame 1 has velocity v=0.1c relative to me and another frame 2 has velocity v=0.15c relative to me, then the interval between them is 0.05c from my perspective, and likewise if a frame 3 has velocity v=0.9c relative to me and another frame 4 has velocity v=0.95c relative to me, then they have the same interval of 0.05c from my perspective; but for another observer moving at v=0.8c relative to me, frame 1 has a velocity of -0.761c and frame 2 has a velocity of -0.739c (so the interval between 1 and 2 is 0.022 for this observer), whereas frame 3 has a velocity of 0.357c and frame 4 has a velocity of 0.625c (so the interval between 3 and 4 is 0.268c for this observer, more than ten times larger than the interval between 1 and 2). These velocities are calculated using the relativistic velocity formula at http://math.ucr.edu/home/baez/physics/Relativity/SR/velocity.html where u = -0.8c is my velocity relative to the second observer, and v is the velocity of any given frame 1,2,3, or 4 relative to me. Point is, if your "intervals" are equal relative to one frame but unequal relative to all other frames, then you are privileging a particular frame's perspective from the start. > Or you could equally integrate over the continuous functions. > As I said, the only way to do this is to use some sort of weight/measure function, and a weight/measure function which is uniform when plotted against velocity in one frame will be non-uniform when plotted against velocity in other frames, so there doesn't seem to be a way of picking such a function that doesn't privilege one frame from the start. > > Considered together simply means you plot the correlation each frame view > (at the standard intervals as above) gives and see how they cluster. Which > I'm pretty sure will be around my result. > The will "cluster" around the judgment of whatever frame you choose to privilege from the start, either by your definition of "equal intervals" or by your weighting/measure function. So, using this to conclude anything about the "actual" correlation would just be another piece of circular reasoning. Jesse > > You don't need to view the resulting graph from any frame as you seem to > suggest, because the graph is OF the actual all frame view results. > > For every frame you simply calculate the apparent lack of simultaneity > between two events Nonsiimultaneity=(t1-t2) and plot it relative to the > simultaneity that my method claims is actual. > > Edgar > > > > On Wednesday, March 5, 2014 2:13:24 PM UTC-5, jessem wrote: >> >> >> >> On Wed, Mar 5, 2014 at 1:27 PM, Edgar L. Owen <[email protected]> wrote: >> >> Jesse, >> >> Yes, you are right. I phrased it incorrectly. >> >> What I meant to say was not that each individual view was somehow >> weighted, but that all views considered together would tend to cluster >> around m >> >> ... > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at http://groups.google.com/group/everything-list. > For more options, visit https://groups.google.com/groups/opt_out. > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/groups/opt_out.
