On Tuesday, December 5, 2017 at 12:50:54 AM UTC, Bruce wrote:
>
> On 5/12/2017 11:38 am, [email protected] <javascript:> wrote:
>
> On Tuesday, December 5, 2017 at 12:26:58 AM UTC, Bruce wrote: 
>>
>> On 5/12/2017 3:15 am, Bruno Marchal wrote: 
>> > On 01 Dec 2017, at 01:49, Bruce Kellett wrote: 
>> >> On 1/12/2017 8:57 am, Bruce Kellett wrote: 
>> >>> On 1/12/2017 4:21 am, Bruno Marchal wrote: 
>> >>>> On 29 Nov 2017, at 23:16, Bruce Kellett wrote: 
>> >>>> On 30/11/2017 2:24 am, Bruno Marchal wrote: 
>> >>>>>> On 29 Nov 2017, at 04:59, Bruce Kellett wrote: 
>> >>>>>> 
>> >>>>>>> I would suggest that there is no such world. Whether a coin 
>> >>>>>>> comes up head or tails on a simple toss is not a quantum event; 
>> >>>>>>> it is determined by quite classical laws of physics governing 
>> >>>>>>> initial conditions, air currents and the like. 
>> >>>>>> 
>> >>>>>> It depends. If you shake the coin long enough, the quantum 
>> >>>>>> uncertainties can add up to the point that the toss is a quantum 
>> >>>>>> event. With some student we have evaluate this quantitavely (a 
>> >>>>>> long time ago) and get that if was enough to shake the coin less 
>> >>>>>> than a minute, but more than few seconds ... (Nothing rigorous). 
>> >>>>> 
>> >>>>> That is a misunderstanding of quantum randomness. For the outcome 
>> >>>>> of a coin toss to be determined by quantum randomness, we would 
>> >>>>> have to have a single quantum event where the outcome was 
>> >>>>> amplified by decoherence so that it was directly entangled with 
>> >>>>> the way the coin landed. Schematically: 
>> >>>>> 
>> >>>>>  |quantum event>|coin> = (|outcome A> + |outcome B>)|coin> 
>> >>>>>  = (|outcome A>|coin heads> + |outcome B>|coin tails>) 
>> >>>> 
>> >>>> The coin is quantum. 
>> >>> 
>> >>> The coin is classical, consisting of something of the order of 10^22 
>> >>> atoms. Indeterminacy in position as given by the Heisenberg 
>> >>> Uncertainty Principle, is undetectably small. 
>> >> 
>> >> I think it is worth while to put some (approximate) numbers around 
>> >> this. The reduced Planck constant, h-bar, is approximately 10^{-27} 
>> >> g.cm^2/s. The Uncertainty Principle is 
>> >> 
>> >>    delta(x)*delta(p) >= h-bar/2. 
>> >> 
>> >> For a coin weighing approximately 10 g and moving at 1 cm/s, the 
>> >> momentum is mv = 10 g.cm/s. Taking the momentum uncertainty to be of 
>> >> this order, the uncertainty in position, delta(x) is of the order of 
>> >> 10^{-28} cm. A typical atom has a diameter of about 10^{-8} cm, so 
>> >> the uncertainty in position is approximately 20 orders of magnitude 
>> >> less than the atomic diameter. 
>> > 
>> > I think that is enough to get the macroscopic superposition, as, like 
>> > I explained, you have to take into account not just the quantum 
>> > indeterminacy, + the classical chaos. You might need to shake for some 
>> > minutes. 
>>
>> You could shake for longer than the age of the universe and you will 
>> still not convert quantum uncertainties and classical thermal motions 
>> into a macroscopic superposition. Do you know nothing about coherence? 
>> And the fact that coherent phases between the components are what 
>> separates a superposition from a mixture?
>
>
> Are the phase angles of components of a superposition identical? If so, is 
> this the definition of coherence? TIA, AG
>
>
> No, why should they be equal. You really do have to learn some basic 
> quantum mechanics, Alan, and stop bothering the list with such questions.
>
> Bruce
>

Was I bothering the list when I started this thread, and others? I recall 
from class the answer is NO, because the probabilities are unaffected when 
taking complex conjugates (ignoring interference), but other comments on 
Avoid2 for example, when I was a member, indicated otherwise. Also, the 
poster here you're replying to seemed not to understand as well. Next time 
take THAT into account. AG 

>
> Random quantum uncertainties 
>> and thermal motions are not coherent, so cannot form superpositions. 
>>
>

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