On 12/19/2017 7:58 PM, agrayson2...@gmail.com wrote:


On Tuesday, December 19, 2017 at 8:58:18 PM UTC, Brent wrote:



    On 12/18/2017 11:54 PM, agrays...@gmail.com <javascript:> wrote:


    On Tuesday, December 19, 2017 at 3:32:22 AM UTC, Brent wrote:



        On 12/18/2017 6:36 PM, agrays...@gmail.com wrote:


        On Monday, December 18, 2017 at 8:48:08 PM UTC, Brent wrote:



            On 12/18/2017 12:19 AM, agrays...@gmail.com wrote:


            On Sunday, December 17, 2017 at 10:39:18 PM UTC,
            agrays...@gmail.com wrote:



                On Sunday, December 17, 2017 at 12:21:27 AM UTC,
                Brent wrote:



                    On 12/16/2017 2:59 PM, agrays...@gmail.com wrote:
                    There's a problem applying SR in this
                    situation because neither the ground or
                    orbiting clock is an inertial frame.AG

                    An orbiting clock is in an inertial frame.  An
                    inertial frame is just one in which no forces
                    are acting (and gravity is not a force) so that
                    it moves with constant momentum along a
                    geodesic.  Although it's convenient for
                    engineering calculations, from a fundamental
                    veiwpoint there is no separate special
                    relativity and general relativity and no
                    separate clock corrections.  General is just
                    special relativity in curved spacetime.  So
                    clocks measure the 4-space interval along their
                    path - whether that path is geodesic (i.e.
                    inertial) or accelerated.


                *Interesting way to look at it. So free falling in
                a gravity field is an extension of SR. But the
                thing I find puzzling is that in GR the curvature
                of space-time is caused by the presence of mass,
                yet I can draw the path of an accelerated body as
                _necessarily_ a curve in a space-time diagram. I am
                having trouble resolving these different sources of
                curvature. AG*


            *Einstein must have figured that since gravity produces
            an acceleration field, and accelerating test particles
            move along curved paths in space-time, he could replace
            acceleration by inertial paths in a space-time curved
            by the presence of mass-energy. But now, when comparing
            test particles moving along different paths in
            space-time, he couldn't use the Lorentz transformation
            because the relative velocities of the frames are not
            necessarily constant. So how did he propose to find the
            correct transformation equations, and what are they?
            And what were the laws of physics, in this case
            gravity, that had to be invariant? AG*

            What's invariant is the measure along a path in
            spacetime - it's what an ideal clock measures.  The
            relation between the measure along two different paths
            obviously depends on the lumpiness of the spacetime
            through which they travel.  It's as if I headed north
            thru the Sierras while you sailed up the coast.  There's
            no simple relation between our path lengths even if we
            travel between the same two points.


        *So what's invariant along along two paths with the same
        endpoints? *

        It's not about two paths.  The length of each path as
        measured using Einstein's  theory of the metric (i.e. as
        warped by mass-energy) is an invariant. Just as the distance
        your car's odometer would measure driving from NY to LA, it's
        some number and it depends on (a) the path you took and (b)
        the topography along that path.  The interesting point is
        that two such paths between a pair of events are different
        durations as measured by clocks carried along the trips.

*Why is this surprising? If dS^2 is path invariant between two space-time events, and dT^2 is time measured in the co-moving frame, one would expect the time duration to be different along different paths since the spatial length varies. *

It would surprise Newton.  He assumed that the time interval between two events was independent of a how a clock moved between them.

*AG*

        That's contrary to Newton, for whom time was an invariant.
        *Not clear from what you write. But whatever it is, why is
        that deemed to be invariant? *

        Because it doesn't depend on what reference system you use in
        spacetime.  It's measuring a distance which is a real thing,
        not something relative/subjective.

        *Shouldn't it be the laws of physics, in this case gravity,
        and hence the field equations? AG *

        It's the basis for them.  They can be written in terms of an
        extremal principle for the invariant path lengths.


    *Is this the method Einstein used to derive the field equations? *

    No, he worked from analogy with Newton's gravity potential.*
    *


*But the field equations are not uniquely determined, so there must have been additional guidelines. I read that Einstein tried many different equations until he found the right set. And the set he settled on in 1915 had been tried years earlier but mistakenly rejected. AG*

Yes, I think that's true but I'm not up on the question.

Brent

    *
    *
    *This is one of my key interests in this subject; to understand
    the _method_ he used to derive the field equations. If so, why is
    invariant path lengths such a crucial condition? I agree that
    physics seeks invariants, but why this particular one? AG
    *

    Having an interval measure is obviously at the heart of a
    geometric theory.

    Brent

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