On 4/21/2019 2:20 AM, [email protected] wrote:
On Saturday, April 20, 2019 at 9:51:13 PM UTC-6, Brent wrote:
On 4/20/2019 2:14 PM, [email protected] <javascript:> wrote:
The following (long!) video can also help (well, it did help me)
https://www.youtube.com/watch?v=foRPKAKZWx8
<https://www.youtube.com/watch?v=foRPKAKZWx8>
Bruno
*I've been viewing this video. I don't see how he established
that the metric tensor is a correction for curved spacetime. AG *
The metric tensor is the quantified embodiment of curved
spacetime. But How else would you define curvature, if not with
the metric?
Brent
*At 49:42 he defines the metric tensor. It has a Kronecker delta as
the leading term. So all cross terms will be zero in its matrix
representation. *
But then he says that in a curved space g_mn must be something else,
that does have cross terms. I don't find his presentation very
enlightening. He ends up wit ds^2 = g_m_n dx^r dx^s He doesn't even
have the indices match as in Einstein's summation forumula.
Bren
*Listen; this is pure mathematics. If what he calls the metric tensor
is the general correction for curved spacetime, it can be proven
mathematically, strictly by mathematics. What I see is a hand-waving
argument at best! Ball in your court. AG *
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