On Wednesday, April 24, 2019 at 6:46:49 PM UTC-6, Brent wrote:
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>
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> On 4/24/2019 4:17 PM, agrays...@gmail.com <javascript:> wrote:
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> On Wednesday, April 24, 2019 at 5:11:13 PM UTC-6, agrays...@gmail.com 
> wrote: 
>>
>>
>>
>> On Wednesday, April 24, 2019 at 3:34:28 PM UTC-6, Brent wrote: 
>>>
>>>
>>>
>>> On 4/21/2019 7:35 PM, agrays...@gmail.com wrote:
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>>>
>>> On Sunday, April 21, 2019 at 8:07:28 PM UTC-6, Brent wrote: 
>>>>
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>>>> On 4/21/2019 6:31 PM, agrays...@gmail.com wrote:
>>>>
>>>> *Here's something odd. At 9:45 in Susskind's Lecture 2 on GR, he says 
>>>> the metric tensor is a Kronecker delta function. But I could swear that 
>>>> the 
>>>> diagonal of -1,1,1,1 represents flat space in SR. AG??*
>>>>
>>>>
>>>> What's odd about that??? Flat space is just special case of curved 
>>>> space in which the curvature is zero.
>>>>
>>>> Brent
>>>>
>>>
>>> *Sure, but he seems to be saying that the Kronecker delta is the metric 
>>> tensor for curved space. Isn't that how you interpret his comment?*
>>>
>>>
>>> No.?? After he goes thru the derivation with delta function in it, then 
>>> he says it's different for a curve?? space.
>>>
>>> Brent
>>>
>>
>> *I just reviewed it again. That's not my reading. In any event, it's not 
>> clear what he means, and using Bruno's suggestion, t' --> it,?? doesn't 
>> really help either since you end up with the Lorentz metric which is far 
>> from Euclidean intuition for demonstrating deviations from flatness. 
>> Further, there are transformations that keep spacetime flat with NON-zero 
>> off diagonal elements, such as a simple rotation. AG??*
>>
>
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> *Using the Lorentz metric, how is "flat" spacetime defined mathematically? 
> AG *
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> The general definition is that the Riemann tensor is zero.?? This is 
> independent of what coordinate system is used.?? 
> https://en.wikipedia.org/wiki/Riemann_curvature_tensor
>
> If the Lorentz metric applies globally the space is flat.
>
> Brent
>

Are the double question marks significant in some way, or typos? AG 

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