On Sunday, April 21, 2019 at 5:59:25 PM UTC-6, [email protected] wrote:
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> On Sunday, April 21, 2019 at 5:54:33 PM UTC-6, Brent wrote:
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>> On 4/21/2019 2:20 AM, [email protected] wrote:
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>> On Saturday, April 20, 2019 at 9:51:13 PM UTC-6, Brent wrote: 
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>>> On 4/20/2019 2:14 PM, [email protected] wrote:
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>>> The following (long!) video can also help (well, it did help me)
>>>>
>>>> https://www.youtube.com/watch?v=foRPKAKZWx8
>>>>
>>>>
>>>> Bruno
>>>>
>>>
>>> *I've been viewing this video. I don't see how he established that the 
>>> metric tensor is a correction for curved spacetime. AG *
>>>
>>>
>>> The metric tensor is the quantified embodiment of curved spacetime.  But 
>>> How else would you define curvature, if not with the metric?
>>>
>>> Brent
>>>
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>> *At 49:42 he defines the metric tensor. It has a Kronecker delta as the 
>> leading term. So all cross terms will be zero in its matrix representation. 
>> *
>>
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>> But then he says that in a curved space g_mn must be something else, that 
>> does have cross terms.   I don't find his presentation very enlightening.  
>> He ends up wit ds^2 = g_m_n dx^r dx^s    He doesn't even have the indices 
>> match as in Einstein's summation forumula.
>>
>> Brent
>>
>
> Thanks. I'm going on to Susskind's lectures on GR.  AG
>

*Here's something odd. At 9:45 in Susskind's Lecture 2 on GR, he says the 
metric tensor is a Kronecker delta function. But I could swear that the 
diagonal of -1,1,1,1 represents flat space in SR. AG *

>
>> *Listen; this is pure mathematics. If what he calls the metric tensor is 
>> the general correction for curved spacetime, it can be proven 
>> mathematically, strictly by mathematics. What I see is a hand-waving 
>> argument at best! Ball in your court. AG *
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