On 8/8/2019 2:03 PM, Jason Resch wrote:
On Thu, Aug 8, 2019 at 3:48 PM 'Brent Meeker' via Everything List <[email protected] <mailto:[email protected]>> wrote:On 8/8/2019 11:50 AM, Jason Resch wrote:On Thu, Aug 8, 2019 at 11:41 AM 'Brent Meeker' via Everything List <[email protected] <mailto:[email protected]>> wrote: On 8/8/2019 1:42 AM, Bruno Marchal wrote: >> Do you not see that there is only one intermediate state and the >> superposition is an artifact of expressing the state relative to a >> certain basis? > > If it was an artfifact, one photon would not been able to interfere > with itself, and there would be no Bell’s violation. It's an artifact of expressing the photon as a superposition of two bases |left slit> and |right slit> which are not orthogonal. There is still only one state, one wave function. Any multitude of things can also also be viewed as a single collection of that multitude. A multitude of classical computational traces can be found in a quantum computation. You point out this multitude of computation traces can be viewed as one state of a larger space. Viewing it this way, however, doesn't eliminate the multitude of the classical computational traces.To call them classical traces implies that they are not coherent and cannot interfere; yet their interference is an essential factor in the computation.As I've said already, whether or not the coherence is exploited by the quantum computer is algorithm-dependent.
If it doesn't exploit coherence, is it really doing quantum computation?
You agree there are the many states in Shor's algorithm before the Fourier transform, right? Then what happens to those many states if you skip the Fourier transform (don't use the interference), you still would say there were many states, do you not?
No, it's an isolated system going through coherent evolution. To say there are many states is just to choose an arbitrary set of basis and vectors and call each component a "state". There's only one state.
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